Q. 41 Use antidifferentiation and/or s... [FREE SOLUTION]

Chapter 6: Q. 41 (page 570)

Use antidifferentiation and/or separation of variables to solve each of the initial-value problems in Exercises 29鈥�52
$\frac{d y}{d x} = \frac{x}{1 + x^{2}}$

Short Answer

Expert verified

The solution of the initial -value problem $\frac{d y}{d x} = \frac{x}{1 + x^{2}} a s y = \frac{1}{2} \ln | 1 + x^{2} | + 4$

Step by step solution

Step 1. Given information

The given initial value problem $\frac{d y}{d x} = \frac{x}{1 + x^{2}} . . . . . . . . . . . . . . . . . . . . . (1)$

Step 2. Use antidifferentiation and/or separation of variables to solve each of the initial-value

Note that the differential equation in (1) does not contain the independent variable at all, so technically the variables have already been separated. Hence, the differential equation can be solved by antidifferentiating. Thus, the solution of the differential equation involved in the initialvalue problem is given by

鈭� d y = 鈭� \frac{x}{1 + x^{2}} d x y = \frac{1}{2} 鈭� \frac{2 x}{1 + x^{2}} d x = \frac{1}{2} 鈭� \frac{1}{u} d u (1 + x^{2} = u, 2 x d x = d u) = \frac{1}{2} \ln | u | + C

Replace the variableu back in terms of variablex to get

y = \frac{1}{2} \ln | 1 + x^{2} | + C

Now, use the given initial condition

y (0) = 4

, that is take

x = 0, y = 4

in the above result and evaluate the constant C.

$4 = \frac{1}{2} \ln 1 + C C = 4$

Substitute this value of the constant Cin the solution of the differential equation and obtain the solution of the initial -value problem $\frac{d y}{d x} = \frac{x}{1 + x^{2}} a s y = \frac{1}{2} \ln | 1 + x^{2} | + 4$

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Use antidifferentiation and/or separation of variables to solve each of the initial-value problems in Exercises 29鈥�52
$\frac{d y}{d x} = \frac{x}{1 + x^{2}}$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Use antidifferentiation and/or separation of variables to solve each of the initial-value

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91影视

Use antidifferentiation and/or separation of variables to solve each of the initial-value problems in Exercises 29鈥�52dydx=x1+x2

Short Answer

Step by step solution

Step 1. Given information

Step 2. Use antidifferentiation and/or separation of variables to solve each of the initial-value

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Decision Maths

Geometry

Mechanics Maths

Discrete Mathematics

Theoretical and Mathematical Physics

Study anywhere. Anytime. Across all devices.

Use antidifferentiation and/or separation of variables to solve each of the initial-value problems in Exercises 29鈥�52
$\frac{d y}{d x} = \frac{x}{1 + x^{2}}$