Chapter 13: Problem 33
Sketch the graph of each equation. If the graph is a parabola, find irs vertex. If the graph is a circle, find its center and radius. $$x=y^{2}-3$$
Short Answer
Expert verified
The graph is a horizontal parabola with vertex at (-3, 0).
Step by step solution
01
Identify the Type of Conic Section
The given equation is \( x = y^2 - 3 \). This equation is not in the standard form of a parabola which is \( y = ax^2 + bx + c \). Rather, it has the form \( x = a(y - k)^2 + h \), identifying it as a horizontal parabola (opens along the x-axis) with vertex form.
02
Rewrite in Vertex Form and Find the Vertex
The given equation \( x = y^2 - 3 \) is already in the form \( x = a(y - k)^2 + h \), where \( a = 1 \), \( k = 0 \), and \( h = -3 \). Thus, this can be rewritten as \( x = (y - 0)^2 + (-3) \), indicating that the vertex \( (h, k) \) is \((-3, 0)\).
03
Determine Direction and Sketch the Parabola
Since \( a = 1 \) and is positive, the parabola opens to the right. To sketch the graph, plot the vertex \((-3, 0)\) and sketch a symmetric parabola opening to the right from this point. The curve will have a vertical axis of symmetry along \( y = 0 \).
04
Check Symmetry and Plot Additional Points for Accuracy
Since the parabola is symmetric about the vertex line \( y = 0 \), choose additional y-values to find corresponding x-values: e.g., for \( y = 1 \), \( x = 1^2 - 3 = -2 \); for \( y = -1 \), \( x = (-1)^2 - 3 = -2 \). Plot these points and others if needed, ensuring the curve remains symmetric and accurate.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabolas
Parabolas are a special type of conic section that have a unique, U-shaped curve. They can open up, down, left, or right, depending on the equation's orientation. When a parabola is in the form of \( y = ax^2 + bx + c \), it's a vertical parabola. However, if it’s formatted as \( x = a(y - k)^2 + h \), it will open horizontally. In our exercise, the equation \( x = y^2 - 3 \) represents a horizontal parabola. Key properties of parabolas include:
- Vertex: The turning point of the parabola, which serves as a point of symmetry.
- Axis of Symmetry: A line through the vertex that divides the parabola into two mirror-image halves.
- Direction of Opening: Determined by the sign and value of \( a \). A horizontal parabola opens left or right.
Graph Sketching
Graph sketching helps us visualize mathematical relationships in a more intuitive form. When sketching a parabola, understanding its vertex and direction of opening is crucial. Start by plotting the vertex. In this exercise, the vertex of the parabola \( x = y^2 - 3 \) is at \((-3, 0)\). From the vertex, visualize the general shape of the parabola.For sketching:
- Determine and plot the vertex.
- Identify the axis of symmetry. For horizontal parabolas, it's a vertical line through the vertex.
- Decide the direction of opening, based on the coefficient \( a \). For this equation, the parabola opens to the right because \( a = 1 \).
Vertex Form
The vertex form of a parabola is a powerful tool for graphing and understanding its geometry. Presented as \( x = a(y-k)^2 + h \), it immediately reveals the parabola's vertex, \( (h, k) \). It tells us more about the parabola, such as its direction and width of opening.In our equation \( x = y^2 - 3 \), we can see:
- Vertex: Located at \((-3, 0)\) with \( h = -3 \) and \( k = 0 \).
- Direction: The parabola opens right because \( a = 1 \), a positive number.