Chapter 13: Problem 34
Sketch the graph of each equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and radius. \(y=(x+3)^{2}+3\)
Short Answer
Expert verified
The equation represents a parabola with a vertex at (-3, 3).
Step by step solution
01
Identify the Type of Graph
The given equation is \( y = (x+3)^2 + 3 \). This equation is in the form \( y = a(x-h)^2 + k \), which represents a parabola. Therefore, we will be dealing with a parabolic graph.
02
Determine the Vertex of the Parabola
For a quadratic function in the form \( y = a(x-h)^2 + k \), the vertex of the parabola is at the point \((h, k)\). In our equation, \( h = -3 \) and \( k = 3 \). Thus, the vertex is at the point \((-3, 3)\).
03
Graph the Equation
Start by plotting the vertex \((-3, 3)\) on the coordinate plane. Since the parabola opens upward (as indicated by the positive coefficient of \((x+3)^2\)), sketch the parabola such that it is symmetrical about the line \(x = -3\) and opens upwards, approaching as a 'U' shape. Additional points can be calculated if needed, but often, understanding the vertex and the direction in which the parabola opens is enough for a basic sketch.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
In a parabolic graph, the vertex is a pivotal point that helps us understand the shape and position of the parabola on a coordinate plane. The vertex is essentially the "tip" or "turning point" of the curve. For any quadratic equation in the vertex form
- \( y = a(x-h)^2 + k \)
- \((h, k)\).
- \( y = (x+3)^2 + 3 \),
- \((h, k)\) is \((-3, 3)\),
Quadratic Functions
Quadratic functions are a type of polynomial function that are characterized by their highest power of the variable being squared. In their standard form, they appear as
- \( y = ax^2 + bx + c \).
- \( y = a(x-h)^2 + k \),
- \((h, k)\) and the direction in which the parabola opens.
- If \(a > 0\), then it opens upwards.
- If \(a < 0\), it opens downwards.
Sketching Graphs
Sketching the graph of a quadratic function, such as a parabola, requires the identification of key characteristics. Start by pinpointing the vertex, which serves as the foundation of your sketch. For
Another vital component in sketching is the axis of symmetry, a line that runs vertically through the vertex. Here, it will be
While graphing, it is often unnecessary to plot numerous points. Sketching primarily involves:
- \(y=(x+3)^2+3\)
- \((-3, 3)\)
Another vital component in sketching is the axis of symmetry, a line that runs vertically through the vertex. Here, it will be
- \(x=-3\),
While graphing, it is often unnecessary to plot numerous points. Sketching primarily involves:
- Ensuring the parabola is symmetrical around its axis,
- Clearly showing it opens in the calculated direction,
- And adjusting the width of the curve based on \(a\).