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The Fox TV network is considering replacing one of its prime-time crime investigation shows with a new family-oriented comedy show. Before a final decision is made, network executives commission a sample of 400 viewers. After viewing the comedy, 250 indicated they would watch the new show and suggested it replace the crime investigation show. a. Estimate the value of the population proportion. b. Compute the standard error of the proportion. c. Develop a 99 percent confidence interval for the population proportion. d. Interpret your findings.

Short Answer

Expert verified
The estimated population proportion is 0.625, with a confidence interval of (0.562, 0.688) for a 99% confidence level.

Step by step solution

01

Estimate the Population Proportion

To estimate the value of the population proportion (\( \hat{p} \)), we divide the number of viewers who indicated they would watch the new show by the total number of viewers. Therefore, \( \hat{p} = \frac{250}{400} = 0.625 \).
02

Compute the Standard Error of the Proportion

The standard error (SE) of the proportion is given by the formula \( SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \), where \( n \) is the sample size. Substituting the known values, \( SE = \sqrt{\frac{0.625 \times 0.375}{400}} \approx 0.0242 \).
03

Calculate the Confidence Interval

To develop a 99% confidence interval, we use the formula: \( \hat{p} \pm Z \times SE \), where \( Z \) is the Z-value corresponding to the desired confidence level (for 99%, \( Z \approx 2.576 \)). Thus, the confidence interval is: \( 0.625 \pm 2.576 \times 0.0242 \), which simplifies to \( (0.562, 0.688) \).
04

Interpretation of the Confidence Interval

The confidence interval (0.562, 0.688) indicates that we are 99% confident that the true proportion of the population who would prefer the comedy show over the crime show falls within this range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The standard error is a crucial concept in statistics when you want to understand how your sample proportions, like whether viewers prefer a new TV show, fluctuate around what you expect. It is like a measure of how much we expect sample proportion estimates to vary due to random chance.
  • The formula to calculate the standard error of the sample proportion is: \[ SE = \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} \]
  • Here, \( \hat{p} \) is your sample proportion, which tells you how many people in your sample liked the show.
  • \( n \) stands for the sample size, the total number of people surveyed, which was 400 in our example.

Imagine throwing a bunch of balls into a basket. Not all of them might land every time; some will bounce out. The standard error is like measuring how much these bounce-outs typically vary when thrown with the same force repeatedly. In our exercise, these calculations suggest how much viewers' opinions could differ just by accident. Using these formulas, we calculated an SE of approximately 0.0242.
Confidence Interval
When you create a confidence interval, you are essentially saying, "I'm pretty sure that the true proportion lies somewhere between these two numbers." Think of it as a net that you cast widely around your calculated estimate to be more sure you're catching the true population proportion.
  • Forming a confidence interval involves: \[ \hat{p} \pm Z \times SE \]
  • \( \hat{p} \) is the sample proportion, here given as 0.625.
  • \( Z \) is a multiplier that comes from statistical tables corresponding to your confidence level. For 99%, \( Z \approx 2.576 \).

In the example, using the TV network's survey, we computed the confidence interval as \((0.562, 0.688)\). This interval tells us that if we sampled many times, 99% of such intervals would contain the true preference proportion of all potential viewers for this new show. This broader interval for 99% confidence is saying, "We’re really serious about this. We want to make sure we're covering any reasonable chance."
Sample Size
Sample size, denoted by \( n \), is the number of observations or respondents in a sample and highly impacts the accuracy of statistics like the proportion. It acts like a lens; the larger the sample size, the clearer the picture of the population's preferences or behaviors.
  • The formula for the sample proportion \( \hat{p} \) and standard error indications implicitly show that larger samples will reduce the SE.
  • This happens because larger sample size \( n \) provides more data points, minimizing random fluctuations' impact.
  • As seen, in the provided exercise, a sample size of 400 was used to assess TV program preferences.

Think of sample size as the sound volume on a radio. Turn it up to get a better clarity of sound, just like increasing \( n \) improves estimate accuracy and shrinks the standard error. Adequately sized samples assure better reliability of findings, making the network executives' decision based on this input, sound and evidence-based.

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