/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Schadek Silkscreen Printing, Inc... [FREE SOLUTION] | 91Ó°ÊÓ

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Schadek Silkscreen Printing, Inc. purchases plastic cups on which to print logos for sporting events, proms, birthdays, and other special occasions. Zack Schadek, the owner, received a large shipment this morning. To ensure the quality of the shipment, he selected a random sample of 300 cups. He found 15 to be defective. a. What is the estimated proportion defective in the population? b. Develop a 95 percent confidence interval for the proportion defective. c. Zack has an agreement with his supplier that he is to return lots that are 10 percent or more defective. Should he return this lot? Explain your decision.

Short Answer

Expert verified
a) 0.05. b) [0.0253, 0.0747]. c) Do not return; defect rate is likely below 10%.

Step by step solution

01

Calculate the Sample Proportion

To find the estimated proportion of defective cups in the shipment (population), use the sample data. The sample contains 300 cups, of which 15 are defective. The sample proportion \( \hat{p} \) can be calculated as follows:\[ \hat{p} = \frac{\text{Number of defective cups}}{\text{Total number of cups in the sample}} = \frac{15}{300} = 0.05 \]
02

Calculate the Standard Error of the Proportion

The standard error of the sample proportion is calculated using the formula:\[ SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \]Where \( n \) is the sample size. Plug in the values:\[ SE = \sqrt{\frac{0.05(1 - 0.05)}{300}} = \sqrt{\frac{0.05 \times 0.95}{300}} \approx 0.0126 \]
03

Determine the Critical Value for 95% Confidence

For a 95% confidence interval, we use the Z-distribution to find the critical value (Z). The Z-value that corresponds to a 95% confidence level is approximately 1.96.
04

Calculate the Confidence Interval

The confidence interval for the proportion is given by:\[ \hat{p} \pm Z \cdot SE \]Substitute the known values:\[ 0.05 \pm 1.96 \times 0.0126 \]Calculate each expression:- Lower bound: \( 0.05 - 1.96 \times 0.0126 = 0.0253 \)- Upper bound: \( 0.05 + 1.96 \times 0.0126 = 0.0747 \)So, the 95% confidence interval is \([0.0253, 0.0747]\).
05

Decision on Returning the Lot

According to Zack's agreement, lots that are 10% or more defective should be returned. The upper bound of the 95% confidence interval for the defective proportion is 0.0747, which is less than 0.10. Therefore, it is statistically unlikely that the actual proportion of defective cups in the entire shipment is 10% or greater.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
In the world of statistics, the sample proportion is a crucial concept, especially when estimating characteristics of a population based on a sample. The sample proportion, denoted as \( \hat{p} \), is essentially the ratio of items in the sample that belong to a particular category of interest. In our exercise, this category is the defective plastic cups. If Zack collected a sample of 300 cups and found 15 were defective, the calculation of the sample proportion becomes straightforward:
  • Number of defective cups = 15
  • Total number of cups in the sample = 300
The sample proportion is calculated as follows: \[\hat{p} = \frac{15}{300} = 0.05\] This result tells us that approximately 5% of the cups in Zack's sample are defective.
This estimated proportion helps us infer about the level of defects in the entire shipment and aids in further statistical analysis.
Standard Error
The standard error of a statistic gives us a measure of how much that statistic is expected to vary from sample to sample, due to sampling variability. For a sample proportion, the standard error (SE) can be calculated using the formula: \[ SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \]where \( n \) is the sample size.
Using Zack's data:
  • Sample proportion \( \hat{p} = 0.05 \)
  • Sample size \( n = 300 \)
Plug these values into the formula:\[SE = \sqrt{\frac{0.05 \times (1 - 0.05)}{300}} \approx 0.0126\]This number, 0.0126, indicates the expected variability in the sample proportion from different samples of the same size from the population.
The smaller the standard error, the more precise our estimate of the population proportion is.
Defective Proportion
Defective proportion refers to the part of the shipment that does not meet the required quality standards. In Zack's context, it's the proportion of plastic cups that are faulty or unsatisfactory. Calculating and understanding this proportion is vital for making data-driven business decisions.
Zack's goal is to use the estimated defective proportion from his sample to make inferences about the entire shipment.
By calculating a 95% confidence interval for the defective proportion, Zack can estimate a range where the true defective proportion likely lies:
  • Estimated defective proportion (\( \hat{p} \)) = 0.05
  • Confidence interval calculated to be [0.0253, 0.0747]
This confidence interval suggests that, although 5% of the sample was defective, the actual proportion in the entire shipment could reasonably be anywhere from 2.53% to 7.47%.
As this is below 10%, Zack concludes that returning the shipment might not be statistically justified.
Z-distribution
The Z-distribution is a type of statistical distribution that follows the standard normal distribution, ideal for handling population statistics when the sample size is large. It allows statisticians to determine probabilities and critical values used in hypothesis testing and confidence interval construction.
In our exercise, the Z-distribution helps in constructing a confidence interval for Zack's defective cup proportion. When creating a confidence interval estimate for a proportion, the critical value from the Z-distribution is used:
  • The critical value for a 95% confidence level is 1.96.
This value reflects the range within which we are 95% confident that the true population proportion lies.
Zack used it to compute the limits of his confidence interval:\[ p \pm 1.96 \times SE \]Substituting his sample proportion and standard error:
  • Lower bound: 0.05 - 1.96 × 0.0126 = 0.0253
  • Upper bound: 0.05 + 1.96 × 0.0126 = 0.0747
This enables Zack to confidently gauge the proportion of defects, ensuring quality standards are efficiently checked and maintained.

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Most popular questions from this chapter

Past surveys reveal that 30 percent of tourists going to Las Vegas to gamble during a weekend spend more than \(\$ 1,000 .\) The Las Vegas Area Chamber of Commerce wants to update this percentage. a. The new study is to use the 90 percent confidence level. The estimate is to be within 1 percent of the population proportion. What is the necessary sample size? b. Management said that the sample size determined above is too large. What can be done to reduce the sample? Based on your suggestion recalculate the sample size.

Suppose you want an 85 percent confidence level. What value would you use to multiply the standard error of the mean?

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