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A state runs a lottery in which six numbers are randomly selected from 40 without replacement. A player chooses six numbers before the state's sample is selected. a. What is the probability that the six numbers chosen by a player match all six numbers in the state's sample? b. What is the probability that five of the six numbers chosen by a player appear in the state's sample? c. What is the probability that four of the six numbers chosen by a player appear in the state's sample? d. If a player enters one lottery each week, what is the expected number of weeks until a player matches all six numbers in the state's sample?

Short Answer

Expert verified
a) \( 2.61 \times 10^{-7} \). b) \( 5.31 \times 10^{-5} \). c) \( 0.00219 \). d) 3,838,380 weeks.

Step by step solution

01

Understanding the Total Number of Combinations

The total number of ways to select 6 numbers from 40 is given by the combination formula \( \binom{40}{6} \). The formula for combinations is \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \). Therefore, \( \binom{40}{6} = \frac{40!}{6!(40-6)!} = 3,838,380 \).
02

Probability of Matching All Six Numbers

Since there is only one way for a player to match all 6 numbers out of the 3,838,380 possible combinations, the probability is \( \frac{1}{3,838,380} \).
03

Probability of Matching Five Numbers

To find the probability that a player matches exactly 5 out of 6 numbers, consider choosing 5 correct numbers out of 6, with \( \binom{6}{5} = 6 \) ways, and choosing 1 incorrect number from the remaining 34, with \( \binom{34}{1} = 34 \) ways. Thus, there are \( 6 \times 34 = 204 \) favorable outcomes. Therefore, the probability is \( \frac{204}{3,838,380} \approx 5.31 \times 10^{-5} \).
04

Probability of Matching Four Numbers

Similarly, to find the probability that a player matches exactly 4 numbers, choose 4 correct numbers out of 6, which can be done in \( \binom{6}{4} = 15 \) ways, and choose 2 incorrect numbers from the remaining 34, \( \binom{34}{2} = 561 \) ways. Thus, there are \( 15 \times 561 = 8,415 \) favorable outcomes. Therefore, the probability is \( \frac{8,415}{3,838,380} \approx 0.00219 \).
05

Expected Number of Weeks to Win

The expected number of weeks until a player matches all six numbers is the reciprocal of the probability of matching all six numbers, which is \( \frac{1}{\frac{1}{3,838,380}} = 3,838,380 \) weeks.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a branch of mathematics focused on counting, arranging, and analyzing discrete structures. It's essential for understanding probability, as it helps determine the number of possible configurations or outcomes in a scenario.
For example, when calculating the number of ways to choose 6 numbers from a set of 40 in a lottery, we use combinations. The combination formula, represented as \( \binom{n}{r} \), gives us the possible ways of selecting \( r \) items from \( n \) items without regard to the order.
This can be calculated by \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \). In our lottery context, choosing 6 numbers from 40 yields \( \binom{40}{6} = 3,838,380 \) possible combinations. This large number highlights how many different ticket options exist in such games of chance.
Lottery Probability
Lottery probability involves calculating the chance of certain outcomes, like winning or matching numbers, within a lottery system. It forms a practical application of combinatorial principles to assess how likely different lottery results might be.
In our exercise, consider the probability of picking 6 numbers that match the drawn ones. There's only 1 favorable result, against 3,838,380 possible outcomes. This makes the probability very low, about \( \frac{1}{3,838,380} \).
Other scenarios include matching five or four numbers. For five matching numbers, combinations help figure out possible groupings of 5 correct and 1 incorrect numbers, resulting in \( 204 \) favorable outcomes. Thus, the probability is \( \frac{204}{3,838,380} \). With four numbers, the approach is similar, yielding about \( 0.00219 \) as a probability, showcasing how probabilities decrease rapidly as exact matches increase.
Expected Value
Expected value is a key concept in probability theory, representing the long-term average or mean of random events. In lottery terms, it helps determine how frequently one might expect to win based on probability.
For example, the probability of matching all six numbers in a lottery is \( \frac{1}{3,838,380} \). The expected number of attempts to get this result is the reciprocal of this probability. Thus, one might expect to play around 3,838,380 times before hitting a jackpot.
Expected value presents how likely an event is across many trials. Although you could win sooner or much later, statistically over an immense number of tries, the expected figure stabilizes around this computed value.
Discrete Probability
Discrete probability involves situations where outcomes are distinct and finite possibilities, unlike continuous probability which deals with an infinite number of outcomes. This applies to processes like lotteries, card games, and dice rolls.
In a lottery, the possibilities of picking numbers are distinct. Each number choice is one separate event, and the total possible outcomes are bounded by the initial setup, like 40 numbers to choose from.
Using discrete probability helps compute how often one can expect specific results, such as matching certain numbers in a lottery. Calculating these outcomes relies heavily on understanding and applying combinatorial methods. This forms the backbone of knowing odds and probabilities in any scenario with a set number of possible results.

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