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Heart failure is due to either natural occurrences (87\%) or outside factors (13\%). Outside factors are related to induced substances or foreign objects. Natural occurrences are caused by arterial blockage, disease, and infection. Assume that causes of heart failure for the individuals are independent. a. What is the probability that the first patient with heart failure who enters the emergency room has the condition due to outside factors? b. What is the probability that the third patient with heart failure who enters the emergency room is the first one due to outside factors? c. What is the mean number of heart failure patients with the condition due to natural causes who enter the emergency room before the first patient with heart failure from outside factors?

Short Answer

Expert verified
a. 0.13 b. 0.0986 c. 6.69

Step by step solution

01

Understanding the Problem

We need to find probabilities related to heart failure causes, specifically outside factors (13%) and natural occurrences (87%). These causes are independent events for arriving patients.
02

Probability of First Patient from Outside Factors

For part (a), since each patient entering the emergency room has a 13% chance of heart failure due to outside factors, this probability is simply the given percentage: \( P(X_1 = \text{outside}) = 0.13 \).
03

Geometric Probability for Third Patient from Outside Factors

For part (b), the first two patients must have heart failure due to natural causes (87%), and the third due to outside factors (13%). The probability is calculated by multiplying these probabilities: \[ P(X_3 = \text{outside}) = 0.87^2 \times 0.13 \approx 0.0986. \]
04

Mean Number of Patients Before First Outside Factor Case

For part (c), this scenario follows a geometric distribution with success probability 13%. The expected number of trials (natural causes) before the first success (outside factor) is given by the formula \( \frac{1-p}{p} \), where \( p = 0.13 \). Thus, \( \frac{1-0.13}{0.13} = \frac{0.87}{0.13} \approx 6.69. \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Distribution
The geometric distribution is used to model scenarios where we are interested in knowing the number of trials needed to get the first success. In this context, "trials" refer to each patient entering the emergency room, and "success" is defined as a patient whose heart failure is due to outside factors, occurring with a probability of 13%.

To calculate the probability of the first successful event happening on a specific trial, such as the third patient in our example, we can use the formula for geometric probability:
  • The formula is: \( P(X = k) = (1-p)^{k-1} \times p \)
  • Where \( p = 0.13 \) is the probability of success, and \( k \) is the trial number.
For the third patient being the first with heart failure due to outside factors, the calculation involves:
  • First two patients must have natural causes, probability \( 0.87 \times 0.87 \)
  • The third is the first with outside cause, probability \( 0.13 \)
Thus, the combined probability is calculated as: \( 0.87^2 \times 0.13 \approx 0.0986 \). This is how the geometric distribution helps us understand a sequence of independent attempts until a first success.
Independent Events
In probability, independent events are those in which the occurrence of one event does not affect the occurrence of another. When we look at patients arriving with heart failure, each patient's likelihood of having a condition due to natural or outside factors is independent of previous patients. This means that each patient has a fresh start in probability terms.

If we say the chances are 87% for natural causes and 13% for outside factors, this breakdown applies consistently and independently to each arriving patient.
  • The probability that any single patient has heart failure from outside factors remains at 13%, no matter how many patients have come before.
  • The probability does not "accumulate" or "reset" because prior events do not influence future events.
Understanding independence is vital because it simplifies calculations and confirms that variables do not impact one another, allowing us to use tools like the geometric distribution correctly.
Expected Value
Expected value gives us an average outcome if we were to repeat the scenario multiple times. Here, it tells us the average number of patients we expect to see with heart issues due to natural causes before encountering one from outside factors.

For the geometric distribution, the expected number of trials before achieving the first success is calculated using the formula \( \frac{1-p}{p} \), where \( p \) is the probability of success. In our situation:
  • Success is defined as a patient having heart failure due to outside factors (13%).
  • Thus, the calculation is \( \frac{0.87}{0.13} \approx 6.69 \).
This means, on average, approximately 6.69 patients with naturally caused heart failure would arrive before witnessing heart failure due to outside factors. This calculation is crucial as it helps medical staff and planners anticipate and prepare for typical hospital scenarios.

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