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Astronomers treat the number of stars in a given volume of space as a Poisson random variable. The density in the Milky Way Galaxy in the vicinity of our solar system is one star per 16 cubic light-years. a. What is the probability of two or more stars in 16 cubic light-years? b. How many cubic light-years of space must be studied so that the probability of one or more stars exceeds \(0.95 ?\)

Short Answer

Expert verified
a) The probability is approx. 0.2642. b) 48 cubic light-years.

Step by step solution

01

Understand the Problem

We are given that the number of stars in a given volume follows a Poisson distribution. The rate (or the average number of stars per volume) is 1 star per 16 cubic light-years. We need to calculate probabilities using this Poisson distribution.
02

Step a: Define the Poisson Probability

Because the mean number of stars (\(\lambda\) ) in 16 cubic light-years is 1, the Poisson distribution can be described as: \(P(X=k)=\frac{ \lambda^k e^{- \lambda}}{k!}\) where \(\lambda=1\) and \(k\) is the number of stars.
03

Calculate Probability for Zero and One Star

Calculate the probabilities for finding zero or one star in 16 cubic light-years: \(P(X=0)=\frac{1^0 \times e^{-1}}{0!}=e^{-1}\) and \(P(X=1)=\frac{1^1 \times e^{-1}}{1!}=e^{-1}\).
04

Probability of Two or More Stars

The probability of having two or more stars is the complement of having zero or one star. Calculate this as: \(P(X\geq2)=1-(P(X=0)+P(X=1))=1-(e^{-1}+e^{-1})=1-2e^{-1}\).
05

Step b: Establish the Desired Probability Condition

We want the probability of finding one or more stars to exceed 0.95. Use the formula \(P(X\geq1) = 1 - P(X=0)\geq0.95\) to find the volume needed.
06

Define the Rate for Unknown Volume

Suppose the volume is \(k\) cubic light-years. The rate \(\lambda\) will be 1 star per 16 cubic light-years multiplied by \(\frac{k}{16}\).
07

Solve the Inequality

Since \(P(X=0) = e^{-\lambda}\) and \(\lambda=\frac{k}{16}\), set the inequality as \(e^{- \frac{k}{16}}\leq0.05\) and solve for \(k\). Taking natural logarithm of both sides gives \(\frac{k}{16}\geq -\ln(0.05)\).
08

Calculate the Volume

Solve \(k = 16 \times -\ln(0.05) \approx 16 \times 2.9957 = 47.9312\). Round up to the nearest cubic light-year, \(k=48\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculation is a core part of statistics that helps us determine how likely an event is to happen. In many real-world scenarios, like predicting the number of stars in a region of space, we use specific probability distributions to model these occurrences. The Poisson distribution is one such tool.

Here’s how we apply probability calculation to the problem of figuring out the likelihood of stars in space:
  • The mean number of events (stars in our problem) per unit volume is known. For our example, it is 1 star per 16 cubic light-years.

  • We use the Poisson probability formula: \(P(X=k)=\frac{ \lambda^k e^{- \lambda}}{k!}\), where \(\lambda\) is the average rate, \(k\) is the number of events, and \(e\) is Euler's number.

  • We calculate the probability of having zero or one star and then use these to find the probability of having two or more stars.
Probability calculations are essential for making informed predictions and understanding the likelihood of different outcomes in uncertain situations.
Stars in the Milky Way
The Milky Way is the galaxy that contains our solar system, and it's home to a vast number of stars, each spread across the vastness of space. Astronomers often need to figure out how stars are distributed to help with various scientific studies and cosmic theories.

In this problem, astronomers assume that the number of stars in a certain volume follows a Poisson distribution, which helps in simplifying the computations. This is particularly useful in the Milky Way, where the distribution of stars isn’t completely uniform due to its spiral structure.
  • The region considered is around our solar system, where the density is roughly one star per 16 cubic light-years.
  • This density, or average rate, is crucial to setting up the problem using the Poisson distribution.
This approach allows astronomers to make probabilistic forecasts about star occurrence in a specific spherical area within the galaxy.
Random Variables
Random variables are a fundamental concept in statistics, used to represent outcomes that depend on chance. In situations like analyzing the distribution of stars in the Milky Way, a random variable can be used to model the number of stars.

A Poisson random variable, which is what we use in this star distribution problem, helps describe the number of times an event—like observing a star—occurs within a certain interval or region.
  • Each possible outcome (0 stars, 1 star, etc.) has a probability associated with it, determined by the mean rate \(\lambda\).
  • In our scenario, \(X\) is the random variable representing the number of stars found in a 16 cubic light-year space.
  • The random variable follows a Poisson process because it counts the occurrence of "stars" in areas of "space."
Random variables provide a way to model and quantify uncertainty in real-world situations, giving us a statistical framework to predict future events.
Exponential Function
The exponential function is a key mathematical concept that frequently appears in probability and statistics, especially with the Poisson distribution. In formulas, it is usually denoted by \(e^x\), where \(e\) is Euler's number, an irrational constant approximately equal to 2.71828.

In our Poisson distribution calculations, the exponential function shows up when we compute probabilities. This is because the distribution is defined as \(P(X=k)=\frac{ \lambda^k e^{- \lambda}}{k!}\).
  • In this equation, \(e^{-\lambda}\) reflects the probability that a star isn’t found in a certain region, demonstrating the decrease in probability with increasing rate \(\lambda\).
  • The exponential part of the formula adjusts the average rate to accommodate varying intervals or volumes, like 16 cubic light-years in this case.
  • When calculating the complement probability for two or more stars, the exponential function is vital in determining \(e^{-\lambda}\).
Understanding the exponential function helps simplify complex calculations, making it a powerful tool in probabilistic modeling and various fields of analysis.

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