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Let \(X\) be a binomial random variable with \(p=0.1\) and \(n=10 .\) Calculate the following probabilities. a. \(P(X \leq 2)\) b. \(P(X>8)\) c. \(P(X=4)\) d. \(P(5 \leq X \leq 7)\)

Short Answer

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a. Sum probabilities from Step 2. b. Sum probabilities from Step 3. c. Use Step 4. d. Sum probabilities from Step 5.

Step by step solution

01

Understanding the Binomial Distribution

Recall that for a binomial distribution, the probability mass function is given by \( P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \) where \( n \) is the number of trials, \( p \) is the probability of success on each trial, and \( k \) is the number of successes. Here, we have \( n = 10 \) and \( p = 0.1 \).
02

Calculate P(X ≤ 2)

This probability can be found by summing up the probabilities of \( P(X=0) \), \( P(X=1) \), and \( P(X=2) \). Calculate each using the probability mass function, then sum them:- \( P(X=0) = \binom{10}{0} (0.1)^0 (0.9)^{10} \)- \( P(X=1) = \binom{10}{1} (0.1)^1 (0.9)^9 \)- \( P(X=2) = \binom{10}{2} (0.1)^2 (0.9)^8 \)Add these results together for the final answer.
03

Calculate P(X > 8)

Since \( X \) can only be 9 or 10 in this case, calculate \( P(X=9) \) and \( P(X=10) \):- \( P(X=9) = \binom{10}{9} (0.1)^9 (0.9)^1 \)- \( P(X=10) = \binom{10}{10} (0.1)^{10} \)Sum these probabilities for the answer.
04

Calculate P(X = 4)

Use the probability mass function for \( P(X=4) \):\[ P(X=4) = \binom{10}{4} (0.1)^4 (0.9)^6 \]
05

Calculate P(5 ≤ X ≤ 7)

Find \( P(X=5) \), \( P(X=6) \), and \( P(X=7) \) then sum them:- \( P(X=5) = \binom{10}{5} (0.1)^5 (0.9)^5 \)- \( P(X=6) = \binom{10}{6} (0.1)^6 (0.9)^4 \)- \( P(X=7) = \binom{10}{7} (0.1)^7 (0.9)^3 \)Add these results together for the final probability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Mass Function
The Probability Mass Function (PMF) is the foundation of the binomial distribution, which helps us find the likelihood of a specific number of successes in a fixed number of trials. Essentially, it's a formula that tells us the probability of any given outcome. For a binomial random variable, the PMF is:\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]Here:
  • \( n \) is the total number of trials.
  • \( k \) is the number of successful trials you are interested in.
  • \( p \) is the probability of success on a single trial.
  • \( \binom{n}{k} \) is a binomial coefficient, calculated as \( \frac{n!}{k!(n-k)!} \).
To compute the probability of an exact number of successes, or even a range, just plug the specific values into this formula. The PMF helps translate the abstract concept of probability into tangible calculations.
Random Variables
In probability theory, a random variable is a variable that takes on different values based on the result of a random event. For binomial distribution, the random variable represents the count of successes in a series of independent trials. Let's break it down:
  • Discrete Random Variables: These are variables like the ones we deal with in binomial distribution. They can take on a finite number of values. For example, if you flip a coin 10 times, the number of heads (successes) is a discrete random variable that can range from 0 to 10.

  • Binomial Random Variables: Specifically refer to the number of successes in \( n \) trials of a binary experiment (only two possible outcomes: success or failure). Each trial is independent, and the probability \( p \) is consistent across all trials.
Random variables are essential in statistics and probability because they allow us to quantify exactly what we're measuring or analyzing. When using a binomial distribution, understanding random variables helps set up the framework for calculating probabilities and making predictions.
Probability Calculations
Probability calculations enable us to determine the likelihood of various outcomes from our random variables. In a binomial distribution setting, probability calculations give us numeric values associated with different potential results.

Calculating for a Range

To find a cumulative probability like \( P(X \leq 2) \), you sum up individual probabilities for all outcomes from zero to two. This involves calculating \( P(X=0) \), \( P(X=1) \), and \( P(X=2) \) using the PMF and then adding these numbers. Summing these discrete probabilities gives you the cumulative probability.

Specific Value Calculations

For exact probabilities, such as \( P(X=4) \), insert the specific values into the PMF. This tells you how often, theoretically, an exact count of successes occurs.
  • Simplicity with Complements: Calculations like \( P(X>8) \) demonstrate simplifying efforts by calculating only complementary probabilities. Here, find \( P(X=9) \) and \( P(X=10) \) rather than using broader cumulative figures.
Knowing how to perform these calculations is critical for interpreting statistical data and making informed decisions based on probability theory.

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