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3.5 .5 Determine the cumulative distribution function of a binomial random variable with \(n=3\) and \(p=1 / 4\)

Short Answer

Expert verified
The CDF is: \(F(x) = \frac{27}{64}\) for \(x=0\), \(\frac{54}{64}\) for \(x=1\), \(\frac{63}{64}\) for \(x=2\), and \(1\) for \(x=3\).

Step by step solution

01

Understand the Binomial Distribution

A binomial random variable with parameters \(n\) and \(p\) denotes the number of successes in \(n\) independent Bernoulli trials, where \(p\) is the probability of success on each trial. In this case, we have \(n=3\) trials and \(p=\frac{1}{4}\).
02

Define Individual Binomial Probabilities

The probability of exactly \(k\) successes in \(n\) trials is given by the formula:\[P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\] For this problem, we need to calculate \(P(X=k)\) for \(k = 0, 1, 2, 3\).
03

Calculate Probabilities for k = 0, 1, 2, 3

Substitute \(n=3\), \(p=\frac{1}{4}\) into the binomial probability formula:- \(P(X=0) = \binom{3}{0} \left(\frac{1}{4}\right)^0 \left(\frac{3}{4}\right)^3 = 1 \times 1 \times \frac{27}{64} = \frac{27}{64}\)- \(P(X=1) = \binom{3}{1} \left(\frac{1}{4}\right)^1 \left(\frac{3}{4}\right)^2 = 3 \times \frac{1}{4} \times \frac{9}{16} = \frac{27}{64}\)- \(P(X=2) = \binom{3}{2} \left(\frac{1}{4}\right)^2 \left(\frac{3}{4}\right)^1 = 3 \times \frac{1}{16} \times \frac{3}{4} = \frac{9}{64}\)- \(P(X=3) = \binom{3}{3} \left(\frac{1}{4}\right)^3 \left(\frac{3}{4}\right)^0 = 1 \times \frac{1}{64} \times 1 = \frac{1}{64}\)
04

Calculate the Cumulative Distribution Function (CDF)

The cumulative distribution function \(F(x)\) is defined as \(F(x) = P(X \leq x)\). We calculate \(F(x)\) for \(x = 0, 1, 2, 3\):- \(F(0) = P(X=0) = \frac{27}{64}\)- \(F(1) = P(X \leq 1) = P(X=0) + P(X=1) = \frac{27}{64} + \frac{27}{64} = \frac{54}{64}\)- \(F(2) = P(X \leq 2) = P(X=0) + P(X=1) + P(X=2) = \frac{54}{64} + \frac{9}{64} = \frac{63}{64}\)- \(F(3) = P(X \leq 3) = P(X=0) + P(X=1) + P(X=2) + P(X=3) = \frac{63}{64} + \frac{1}{64} = 1\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cumulative Distribution Function (CDF)
The cumulative distribution function, abbreviated as CDF, is an essential concept in probability theory, especially when dealing with random variables like the binomial distribution. Imagine that you are recording successes over several trials. The CDF helps us understand the probability of getting a certain number of successes or fewer.
In a binomial setup, where outcomes are defined by a fixed number of independent trials, the CDF, denoted as \(F(x)\), can be calculated by summing up the probabilities of getting up to that specific number of successes. This means if you want to know the probability that a variable takes on a value of \(x\) or less, you sum the probabilities of all outcomes from 0 to \(x\).
For example, given \(n = 3\) trials and a success probability \(p = \frac{1}{4}\), the CDF at \(x=2\) would be calculated as the sum: \(P(X \leq 2) = P(X=0) + P(X=1) + P(X=2)\). Calculating CDF gives us a full context of the distribution at any point and helps in understanding how likely we are to accumulate up to a particular number of successes.
Probability Calculation
Probability calculation is at the heart of understanding binomial distributions, and it provides us with the complete picture of the possible outcomes. In the context of binomial experiments, the probability of exactly \(k\) successes in \(n\) trials is calculated using the binomial probability formula: \[P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\]This formula involves a few crucial components:
  • \(\binom{n}{k}\): The binomial coefficient, representing combinations of our trials
  • \(p^k\): The probability of success raised to the number of successes
  • \((1-p)^{n-k}\): The probability of failure raised to the number of failures

By financializing these factors, you get the probability of observing \(k\) successes. It's a straightforward computation once you have all the numbers plugged in. For example, with \(n=3\) and \(p=\frac{1}{4}\), calculating \(P(X=1)\) involves multiplying \(\binom{3}{1} (\frac{1}{4})^1 (\frac{3}{4})^2\). Each part of this formula incorporates real-world probabilities into a digestible number.
Bernoulli Trials
Bernoulli trials are the foundation for understanding the binomial distribution. These are simple experiments that result in one of two outcomes: success or failure. When a series of Bernoulli trials are conducted, they must be independent - meaning the result of one trial should not affect the outcome of the others.
Each Bernoulli trial has its own probability of success \(p\), while the probability of failure is \(1-p\). In the context of binomial distribution, when you perform \(n\) number of Bernoulli trials, you're mostly interested in the number of successes out of those trials.
Imagine flipping a coin, where landing a heads is considered a success. If you flip the coin three times, you have performed three Bernoulli trials. If we let \(p = \frac{1}{4}\) as the probability of success, this might be an unfair coin where landing heads happens less frequently. The binomial distribution then is used to describe all potential combinations of heads (successes) and tails (failures) you might record.
Understanding this, lays the groundwork for grasping more complex probability topics, like the cumulative probability and calculating probabilities of specific outcomes.

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