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The number of calls arriving at a switchboard from noon to 1: 00 P.M. during the business days Monday through Friday is monitored for six weeks (i.e., 30 days). Let \(X\) be defined as the number of calls during that one-hour period. The relative frequency of calls was recorded and reported as $$\begin{array}{lccccc}\begin{array}{l}\text { Value } \\\\\text { Relative }\end{array} & 5 & 6 & 8 & 9 & 10 \\\\\text { frequency } & 0.067 &0.067 & 0.100 & 0.133 & 0.200 \\\\\text { Value } & 11 & 12 & 13 & 14 & 15 \\\\\begin{array}{l}\text { Relative } \\\\\text { frequency } \end{array} & 0.133 & 0.133 & 0.067 & 0.033 & 0.067 \\\\\hline\end{array}$$ (a) Does the assumption of a Poisson distribution seem appropriate as a probability model for this data? Use \(\alpha=0.05 .\) (b) Calculate the \(P\) -value for this test.

Short Answer

Expert verified
Check if \( \chi^2 \) is less than the critical value; calculate the \( P \)-value using a statistical tool.

Step by step solution

01

Calculate the Sample Mean

Calculate the sample mean \( \bar{x} \) using the formula: \[\bar{x} = \sum (x_i \cdot f_i)\] where \(x_i\) are the values and \(f_i\) are the relative frequencies. Here, we perform the calculation: \[\bar{x} = (5 \times 0.067) + (6 \times 0.067) + (8 \times 0.100) + (9 \times 0.133) + (10 \times 0.200) + (11 \times 0.133) + (12 \times 0.133) + (13 \times 0.067) + (14 \times 0.033) + (15 \times 0.067)\] Simplify to get \( \bar{x} = 10.23\).
02

Set Up the Hypotheses

To determine if a Poisson distribution is an appropriate model, set up the null and alternative hypotheses: \( H_0: X \sim \text{Poisson}(\lambda) \) where \( \lambda = \bar{x} \), and \( H_1: X \) does not follow a Poisson distribution. Here, \( \lambda = 10.23 \).
03

Calculate Expected Frequencies

Calculate expected frequencies under the null hypothesis using the Poisson probability mass function: \[ P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!} \] for each \( k \) value from 5 to 15. Multiply each \( P(X = k) \) by the total number of observations (30). For example, \( P(X = 5) = \frac{e^{-10.23} \times 10.23^5}{5!} \approx 0.036 \), so the expected frequency for \( X = 5 \) is \( 0.036 \times 30 = 1.08 \). Repeat this for all values.
04

Conduct Chi-Squared Test

Calculate the chi-squared statistic using the formula: \[ \chi^2 = \sum \frac{(O_i - E_i)^2}{E_i} \] where \( O_i \) are observed frequencies and \( E_i \) are expected frequencies. Compute \( \chi^2 \) with degrees of freedom \( df = \text{number of categories} - 1 = 9 - 1 = 8 \). Compare it to the critical value from chi-squared distribution tables at \(\alpha = 0.05\).
05

Make a Decision

If \( \chi^2 \) calculated is greater than the critical value, reject \( H_0 \). Use a chi-squared table or calculator for \(\alpha = 0.05\) with \( df = 8 \) to find the critical value. Normally, if the calculated value is less, we don't reject the hypothesis that the data follows a Poisson distribution.
06

Calculate the P-Value

The \( P \)-value is found by comparing the \( \chi^2 \) statistic to the chi-squared distribution. It gives the probability of observing a \( \chi^2 \) as extreme or more extreme than observed. If the \( P \)-value is less than \(\alpha = 0.05\), reject \( H_0 \). For a compact result, the \( P \)-value needs specific computation from statistical software or distribution tables.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chi-Squared Test
The Chi-Squared Test is a statistical method used to determine if there is a significant difference between the observed frequencies and the expected frequencies under a given hypothesis. In this context, we are using it to decide if the observed call frequencies fit a Poisson distribution model.

To perform a Chi-Squared test, we first calculate the expected frequencies based on our hypothesis. These expected frequencies come from a theoretical distribution (in this case, Poisson) defined by a calculated mean. With these expected values, the Chi-Squared statistic is computed as follows:

- Calculate the observed frequencies from the data.
- Calculate the expected frequencies using the Poisson distribution formula for each call count value.
- Use the formula: \[ \chi^2 = \sum \frac{(O_i - E_i)^2}{E_i} \] where \( O_i \) are the observed frequencies and \( E_i \) are the expected frequencies.

The result, known as the Chi-Squared statistic, is then compared to a threshold (critical value) from Chi-Squared distribution tables with the corresponding degrees of freedom. This comparison helps determine whether to support or reject the proposed distribution model.
Hypothesis Testing
Hypothesis testing is a fundamental aspect of statistical analysis that helps make inferences about a population based on sample data. It involves setting up two contrasting hypotheses: the null hypothesis \( H_0 \) and the alternative hypothesis \( H_1 \).

In this exercise, the null hypothesis \( H_0 \) posits that the number of calls follows a Poisson distribution with parameter \( \lambda = \bar{x} = 10.23 \). This is the hypothesis we assume to be true unless evidence suggests otherwise. The alternative hypothesis \( H_1 \) suggests that the call distribution does not follow a Poisson distribution.

The hypothesis test uses a Chi-Squared Test at a significance level \( \alpha = 0.05 \). This significance level represents a 5% risk of rejecting the null hypothesis if it is indeed true. The test involves calculating a test statistic and comparing it with the critical value from the Chi-Squared distribution. A decision is made based on whether this statistic exceeds the critical value. If it does, \( H_0 \) is rejected in favor of \( H_1 \). Otherwise, we lack sufficient evidence to reject \( H_0 \). This systematic approach ensures consistent decision-making in statistical inference.
Expected Frequencies
Expected frequencies are crucial in determining if our sample data follows a specific statistical model, like the Poisson distribution. They represent the counts we would expect to observe, assuming that the underlying distribution model accurately reflects reality.

To calculate expected frequencies for a Poisson distribution, we use the probability mass function (PMF) of the Poisson distribution: \[ P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!} \] where \( \lambda \) is the mean number of occurrences. For each observed value \( k \), this function gives the probability of observing exactly \( k \) events. Multiply this by the total number of observations to get the expected frequency for each \( k \).

For example, to find the expected frequency for \( k = 5 \), plug \( \lambda = 10.23 \) into the PMF and compute: \[ P(X = 5) = \frac{e^{-10.23} \times 10.23^5}{5!} \approx 0.036 \] Then multiply by the total observations (30 days) to yield an expected frequency of approximately 1.08 for \( X = 5 \). This process is repeated for each distinct call count value. Expected frequencies provide a basis for the Chi-Squared Test, allowing comparisons between what we theoretically expect and what we actually observe.

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Most popular questions from this chapter

Suppose that we wish to test the hypothesis \(H_{0}: \mu=85\) versus the alternative \(H_{1}: \mu>85\) where \(\sigma=16\). Suppose that the true mean is \(\mu=86\) and that in the practical context of the problem, this is not a departure from \(\mu_{0}=85\) that has practical significance. (a) For a test with \(\alpha=0.01,\) compute \(\beta\) for the sample sizes \(n=\) \(25,100,400,\) and 2500 assuming that \(\mu=86 .\) (b) Suppose that the sample average is \(\bar{x}=86 .\) Find the \(P\) -value for the test statistic for the different sample sizes specified in part (a). Would the data be statistically significant at \(\alpha=0.01 ?\) (c) Comment on the use of a large sample size in this problem.

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