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Suppose that we wish to test the hypothesis \(H_{0}: \mu=85\) versus the alternative \(H_{1}: \mu>85\) where \(\sigma=16\). Suppose that the true mean is \(\mu=86\) and that in the practical context of the problem, this is not a departure from \(\mu_{0}=85\) that has practical significance. (a) For a test with \(\alpha=0.01,\) compute \(\beta\) for the sample sizes \(n=\) \(25,100,400,\) and 2500 assuming that \(\mu=86 .\) (b) Suppose that the sample average is \(\bar{x}=86 .\) Find the \(P\) -value for the test statistic for the different sample sizes specified in part (a). Would the data be statistically significant at \(\alpha=0.01 ?\) (c) Comment on the use of a large sample size in this problem.

Short Answer

Expert verified
The data is not statistically significant at \(\alpha = 0.01\) for any sample size. Large sample sizes can make small differences significant but may lack practical significance.

Step by step solution

01

Calculate the Critical Value

For a one-tailed test with \(\alpha = 0.01\), find the critical z-value corresponding to \(\alpha = 0.01\). Since this is a right-tail test, use a Z-table to find \(z_{\alpha} = 2.33\).
02

Compute Beta for Each Sample Size

The power of the test is calculated as follows:1. Find the test statistic z for \(\mu = 86\): \[ z = \frac{\bar{x} - \mu_0}{\sigma/\sqrt{n}} \]2. Solve for z when \(\bar{x} = 86\) for each \(n\): \[ z = \frac{86 - 85}{16/\sqrt{n}} \]3. Calculate \(\beta = P(\text{Fail to reject } H_0 | \mu = 86) = P(Z < z_{h})\), where \(z_{h} = z_{\alpha} - \left(\frac{\Delta}{\sigma/\sqrt{n}}\right)\) and \(\Delta = 1\).Perform these calculations for each sample size:- **n = 25:** - \( z_{h} = 2.33 - \frac{1}{16/5} = 2.33 - 0.3125 = 2.0175\) - \( \beta = P(Z < 2.0175) = 0.9783\)- **n = 100:** - \( z_{h} = 2.33 - \frac{1}{16/10} = 2.33 - 0.1 = 2.23\) - \( \beta = P(Z < 2.23) = 0.9871\)- **n = 400:** - \( z_{h} = 2.33 - \frac{1}{16/20} = 2.33 - 0.05 = 2.28\) - \( \beta = P(Z < 2.28) = 0.9887\)- **n = 2500:** - \( z_{h} = 2.33 - \frac{1}{16/50} = 2.33 - 0.02 = 2.31\) - \( \beta = P(Z < 2.31) = 0.9896\)
03

Calculate P-values for Sample Sizes

The P-value is the probability of obtaining a test statistic as extreme as the one observed, given that the null hypothesis is true.- Using \( \bar{x} = 86\), calculate the test statistic: \[ z = \frac{86 - 85}{16/\sqrt{n}} \]- Find the P-value \( P(Z > z) \):- **n = 25:** - \( z = 0.3125 \) - P-value = \( P(Z > 0.3125) = 0.3770 \)- **n = 100:** - \( z = 0.10 \) - P-value = \( P(Z > 0.10) = 0.4602 \)- **n = 400:** - \( z = 0.05 \) - P-value = \( P(Z > 0.05) = 0.4801 \)- **n = 2500:** - \( z = 0.02 \) - P-value = \( P(Z > 0.02) = 0.4920 \)
04

Assess Statistical Significance

Compare each P-value to \(\alpha = 0.01\). Since all P-values are greater than 0.01, we fail to reject the null hypothesis \(H_0\). The data do not show statistically significant evidence at \(\alpha = 0.01\) for any of the sample sizes.
05

Comment on Large Sample Size Use

With large sample sizes, even small differences become statistically significant (increased power), but this does not necessarily equate to practical significance. It highlights the potential discrepancy between statistical significance and practical relevance, particularly when dealing with marginal differences as in this case where \(\mu = 86\) is not practically significant from \(\mu = 85\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Significance
Statistical significance is an important concept in hypothesis testing that helps us decide if the results of our test are likely due to chance or if they represent true differences. We typically use a significance level, denoted by \(\alpha\), as a threshold. In this exercise, \(\alpha = 0.01\), meaning we are willing to accept a 1% chance of incorrectly rejecting the null hypothesis. This low alpha level is often chosen in contexts where avoiding false positives is critical.

The p-value helps us determine the statistical significance of a test result. It indicates the probability of obtaining a test statistic as extreme as the observed one, assuming the null hypothesis is true. If the p-value is less than \(\alpha\), we say the result is statistically significant, and we reject the null hypothesis. Otherwise, we fail to reject it.
  • If the p-value is less than 0.01, the result is statistically significant at \(\alpha = 0.01\).
  • If the p-value is greater than 0.01, as in this exercise, it means the data do not provide strong evidence against the null hypothesis.
Statistical significance does not imply that the result is practically important. There can be situations where small, statistically significant differences do not have meaningful real-world implications.
Sample Size
The size of the sample, denoted by \(n\), plays a crucial role in hypothesis testing. It affects both the precision of the parameter estimates and the power of the test. Larger sample sizes typically lead to more reliable results, as they tend to represent the population more accurately.
In the given exercise, the impact of sample size is evident. As \(n\) increases, the test statistic \(z\) computed for the sample averages also changes, reflecting more precise estimates. With larger sample sizes, there is less variability in the sample mean estimate, reducing the standard error \(\sigma/\sqrt{n}\).
  • For \(n = 25\), \(z = 0.3125\).
  • For \(n = 2500\), \(z = 0.02\).
Larger samples also tend to lower the p-value, making it more likely to find statistical significance if a true effect exists. However, as seen in this problem, a large sample can also highlight tiny differences that aren't practically meaningful, necessitating careful interpretation of results.
Power of a Test
The power of a statistical test is the probability that the test correctly rejects a false null hypothesis, i.e., detecting an effect when there is one. It is denoted by \(1 - \beta\), where \(\beta\) is the probability of a Type II error (failing to reject a false null hypothesis).
In the context of this exercise, calculations reveal how power changes with different sample sizes. Given a small true effect, such as \(\mu = 86\) instead of \(\mu = 85\), increasing the sample size increases the power:
  • For \(n = 25\), \(\beta = 0.9783\), resulting in very low power.
  • For \(n = 2500\), \(\beta = 0.9896\), still indicating low power due to a tiny effect size.
The power of a test is crucial when planning studies. Adequate power is necessary to confidently detect effects. However, as observed, even a test with high power may identify statistically significant results that lack practical importance. This emphasizes the need for balancing statistical and practical significance in interpreting test outcomes.

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Most popular questions from this chapter

Human oral normal body temperature is believed to be \(98.6^{\circ} \mathrm{F},\) but there is evidence that it actually should be \(98.2^{\circ} \mathrm{F}\) [Mackowiak, Wasserman, Steven and Levine, JAMA (1992, Vol. \(268(12),\) pp. \(1578-1580)] .\) From a sample of 52 healthy adults, the mean oral temperature was 98.285 with a standard deviation of 0.625 degrees. (a) What are the null and alternative hypotheses? (b) Test the null hypothesis at \(\alpha=0.05\). (c) How does a \(95 \%\) confidence interval answer the same question?

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