/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 The proportion of residents in P... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The proportion of residents in Phoenix favoring the building of toll roads to complete the freeway system is believed to be \(p=0.3 .\) If a random sample of 10 residents shows that 1 or fewer favor this proposal, we will conclude that \(p<0.3\). (a) Find the probability of type I error if the true proportion is \(p=0.3\). (b) Find the probability of committing a type II error with this procedure if \(p=0.2\) (c) What is the power of this procedure if the true proportion is \(p=0.2 ?\)

Short Answer

Expert verified
(a) 0.1493; (b) 0.6242; (c) 0.3758

Step by step solution

01

Understanding Type I Error

A type I error occurs when we reject the null hypothesis even though it is true. In this context, it means concluding that the proportion of residents favoring the proposal is less than 0.3, even though the true proportion is 0.3.
02

Calculating Probability of Type I Error

For a binomial distribution with parameters \(n = 10\) and \(p = 0.3\), the probability of at most 1 success can be calculated by finding \(P(X \leq 1)\). This can be expressed as the sum of probabilities \(P(X = 0) + P(X = 1)\).Using the binomial probability formula: \[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]Calculate:- \(P(X = 0) = \binom{10}{0} (0.3)^0 (0.7)^{10} \approx 0.0282\)- \(P(X = 1) = \binom{10}{1} (0.3)^1 (0.7)^9 \approx 0.1211\)Adding these probabilities gives:\[P(X \leq 1) = 0.0282 + 0.1211 = 0.1493\]
03

Understanding Type II Error

A type II error occurs when we fail to reject the null hypothesis when the alternative is true. In this context, it means failing to conclude that the proportion is less than 0.3 when, in reality, it is 0.2.
04

Calculating Probability of Type II Error

For a binomial distribution with parameters \(n = 10\) and \(p = 0.2\), the probability of obtaining more than 1 success is required. This is equivalent to \(1 - P(X \leq 1)\) where \(P(X \leq 1)\) is the probability of obtaining 0 or 1 success.Calculate \(P(X \leq 1)\):- \(P(X = 0) = \binom{10}{0} (0.2)^0 (0.8)^{10} \approx 0.1074\)- \(P(X = 1) = \binom{10}{1} (0.2)^1 (0.8)^9 \approx 0.2684\)\[P(X \leq 1) = 0.1074 + 0.2684 = 0.3758\]Thus, the probability of Type II error is:\[1 - P(X \leq 1) = 1 - 0.3758 = 0.6242\]
05

Understanding Power of a Test

The power of a test is the probability of correctly rejecting the null hypothesis when the alternative hypothesis is true (i.e., the probability of not making a type II error).
06

Calculating Power of the Test

The power is calculated as \(1 - \text{Probability of Type II Error}\).Substitute the previously calculated value:\[1 - 0.6242 = 0.3758\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type I Error
In hypothesis testing, a Type I error occurs when we wrongly reject a true null hypothesis. Imagine you think a coin is biased and test flipping it. Even if the coin is fair, there’s a chance your test suggests it's biased - that's a Type I error. For our Phoenix toll road exercise, rejecting the notion that 30% of residents favor the proposal when exactly 30% do favor it is a Type I error.
To calculate this error, we use the binomial distribution – a statistical test used for counts of outcomes. The formula involves understanding the number of trials (n), usually representing sample size, and the probability of success (p). For our case:
  • n = 10 (sample size)
  • p = 0.3 (proportion favoring the proposal)
The probability of Type I error (rejecting the null when it’s true) is the chance of 1 or fewer successes in 10 trials. This is computed using: \(P(X \leq 1)\) for a binomial setup, resulting in around 0.1493, or 14.93% chance of making this mistake.
Type II Error
A Type II error occurs when we fail to reject a false null hypothesis. It’s like missing that the coin actually is biased. Using Phoenix residents again, a Type II error implies concluding that the percent favoring toll roads isn't less than 30%, when it actually is lower. Specifically, if only 20% prefer it but we fail to recognize it, that’s a Type II error.For a binomial distribution with n = 10 and p = 0.2, to find this error, we calculate 1 minus the probability of up to 1 success, \(P(X \leq 1)\). Here’s how to break that down:
  • Compute \(P(X = 0)\) which gives the chance all 10 disagree (all 0's).
  • Then \(P(X = 1)\), which indicates 1 out of 10 are in favor.
Adding those gives us 0.3758. Thus, the Type II error probability is 1 - 0.3758 = 0.6242, or 62.42%.
Binomial Distribution
Understanding the binomial distribution is key to tackling hypothesis testing problems like our exercise. This distribution is used when counting outcomes of binary events (success/failure) across several trials. Common examples include coin tosses or survey responses, where answers fall into two categories.Each event or trial must be independent, such as separate yes/no responses from surveyed residents. The number of trials (n) and the probability of success (p) define your distribution.This case has:
  • n = 10 trials (residents surveyed)
  • p = 0.3 for Type I, or p = 0.2 for Type II when assessing likelihood.
The formula to calculate exact probabilities uses this setup: \(P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\) allowing precise probabilities for specific outcomes, foundation to hypothesis testing.
Power of a Test
In hypothesis testing, the power of a test reveals how good a test is at finding a true effect or rejecting a false null hypothesis. High power means the test is effective at detecting real, often subtle differences. For our exercise, the power is about accurately recognizing if less than 30% of Phoenix residents support toll roads, assuming actual support is at 20%. An effective test with a low Type II error rate has higher power. This value is computed as 1 minus the Type II error rate. Using our exercise values:
  • Type II Error = 0.6242 (from previous calculation),
  • Power = 1 - 0.6242 = 0.3758.
Thus, there is a 37.58% power, suggesting our test might not be the best at recognizing the true lower support level.

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