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Determine the cumulative distribution function of a binomial random variable with \(n=3\) and \(p=1 / 2\).

Short Answer

Expert verified
The CDF is: \( F(x) = \begin{cases} 0, & x < 0 \\ \frac{1}{8}, & 0 \leq x < 1 \\ \frac{1}{2}, & 1 \leq x < 2 \\ \frac{7}{8}, & 2 \leq x < 3 \\ 1, & x \geq 3 \end{cases} \).

Step by step solution

01

Understand the Problem

We're given a binomial distribution with parameters \( n = 3 \) and \( p = \frac{1}{2} \). Our goal is to find the cumulative distribution function (CDF), which is the probability that the random variable \( X \) takes a value less than or equal to a specific value \( x \).
02

Define the Binomial Probability Mass Function

The probability mass function (PMF) for a binomial distribution is given by \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \). For our case with \( n = 3 \) and \( p = \frac{1}{2} \), it becomes \( P(X = k) = \binom{3}{k} \left(\frac{1}{2}\right)^k \left(\frac{1}{2}\right)^{3-k} \).
03

Calculate Probabilities for Each Possible Value of X

Calculate \( P(X = 0) \), \( P(X = 1) \), \( P(X = 2) \), and \( P(X = 3) \):- \( P(X = 0) = \binom{3}{0} \left(\frac{1}{2}\right)^0 \left(\frac{1}{2}\right)^3 = \frac{1}{8} \)- \( P(X = 1) = \binom{3}{1} \left(\frac{1}{2}\right)^1 \left(\frac{1}{2}\right)^2 = \frac{3}{8} \)- \( P(X = 2) = \binom{3}{2} \left(\frac{1}{2}\right)^2 \left(\frac{1}{2}\right)^1 = \frac{3}{8} \)- \( P(X = 3) = \binom{3}{3} \left(\frac{1}{2}\right)^3 \left(\frac{1}{2}\right)^0 = \frac{1}{8} \)
04

Compute the Cumulative Distribution Function

Calculate the cumulative probabilities for each possible value of \( x \). The CDF \( F(x) \) for a binomial random variable is found by summing the probabilities for all \( k \leq x \):- \( F(0) = P(X \leq 0) = P(X = 0) = \frac{1}{8} \)- \( F(1) = P(X \leq 1) = P(X = 0) + P(X = 1) = \frac{1}{8} + \frac{3}{8} = \frac{1}{2} \)- \( F(2) = P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = \frac{1}{8} + \frac{3}{8} + \frac{3}{8} = \frac{7}{8} \)- \( F(3) = P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 1 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cumulative Distribution Function
The Cumulative Distribution Function (CDF) is an essential concept when studying probability distributions. For a given random variable, the CDF represents the probability that the variable will be less than or equal to a certain value. In simpler terms, it's a way to accumulate probabilities up to a particular point.

Consider the binomial random variable in the original exercise with parameters \( n = 3 \) and \( p = \frac{1}{2} \). The CDF, denoted as \( F(x) \), gives us the total probability for all outcomes less than or equal to \( x \). This means if you add up the probabilities for outcomes \( X = 0 \) through \( X = 3 \), you will get \( F(3) = 1 \), as this represents the entire probability space.

Using the binomial Probability Mass Function (PMF), the individual probabilities were calculated and summed for each possible outcome of \( x \). Thus, \( F(0) = \frac{1}{8} \), \( F(1) = \frac{1}{2} \), \( F(2) = \frac{7}{8} \), and finally, \( F(3) = 1 \), providing a complete description of the distribution's behavior. The CDF is invaluable because, by using it, you can easily determine the likelihood that the random variable does not exceed a certain threshold.
Probability Mass Function
The Probability Mass Function (PMF) is a fundamental concept in discrete probability, used to specify the probability that a discrete random variable is exactly equal to a particular value. For a binomial distribution like in our original problem, it tells us the likelihood of obtaining a specific number of successes when performing a set number of independent experiments.

In the exercise, we use the PMF formula for a binomial distribution: \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \). This formula incorporates the binomial coefficient \( \binom{n}{k} \), which represents the number of ways to choose \( k \) successes out of \( n \) trials.

For our example, with \( n = 3 \) and success probability \( p = \frac{1}{2} \), the PMF helps calculate the probability for \( X \) being 0 to 3. These computations yield the specific probabilities that contribute to the cumulative distribution. For instance, \( P(X = 0) = \frac{1}{8} \) and \( P(X = 1) = \frac{3}{8} \), etc., all of which are required to build the CDF.
Binomial Random Variable
A binomial random variable is a type of discrete random variable that counts the number of successes in a fixed number of independent Bernoulli trials, each with the same probability of success. In simpler terms, imagine flipping a coin multiple times and counting how many times it lands heads (success).

For the given problem, we have a binomial random variable \( X \) with \( n = 3 \) trials and a success probability \( p = \frac{1}{2} \). This means we're looking at an experiment with three coin flips, and we calculate probabilities for getting 0, 1, 2, or 3 heads.

Binomial random variables like this one are modeled using the binomial distribution. It's crucial to understand that the probability of each outcome (0, 1, 2, or 3 successes) relies on the same underlying PMF. The beauty of binomial random variables lies in their versatility; they're apt for a wide variety of real-world processes, like quality control in manufacturing or modeling disease spread, wherever the phenomena can be simplified into independent yes/no scenarios.

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Most popular questions from this chapter

Samples of rejuvenated mitochondria are mutated (defective) in \(1 \%\) of cases. Suppose that 15 samples are studied and can be considered to be independent for mutation. Determine the following probabilities. The binomial table in Appendix A can help. (a) No samples are mutated. (b) At most one sample is mutated. (c) More than half the samples are mutated.

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