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The probability of a successful optical alignment in the assembly of an optical data storage product is 0.8 . Assume that the trials are independent. (a) What is the probability that the first successful alignment requires exactly four trials? (b) What is the probability that the first successful alignment requires at most four trials? (c) What is the probability that the first successful alignment requires at least four trials?

Short Answer

Expert verified
(a) 0.008; (b) 0.992; (c) 0.008.

Step by step solution

01

Understanding the Problem

We are given a probability scenario where the probability of success in each trial is 0.8. We need to determine probabilities related to the number of trials needed to achieve the first success. This follows a geometric probability distribution.
02

Probability of Success on Exactly Four Trials

The probability that the first successful trial happens on the fourth attempt can be calculated by having three failures followed by one success. Given, \( P( ext{success}) = 0.8 \) and \( P( ext{failure}) = 1 - 0.8 = 0.2 \). The probability of success on exactly the fourth trial is calculated as: \[ P(X=4) = (0.2)^3 imes 0.8 \] Calculate this to obtain the probability.
03

Probability of Success on At Most Four Trials

To find this, we must calculate the cumulative probability of the first success occurring on or before the fourth trial. That includes one success on the first, second, third, or fourth trial. Calculate \( P(X\leq4) \) as the sum of probabilities: \[ P(X=1) + P(X=2) + P(X=3) + P(X=4) \] Utilize the formula \( P(X=k) = (0.2)^{k-1} \times 0.8 \) for each of these probabilities.
04

Probability of Success on At Least Four Trials

To find the probability that the first success occurs on at least four trials, recognize that it's the complement of having one before the fourth trial. Use the complement rule: \[ P(X \geq 4) = 1 - P(X \leq 3) \] Calculate \( P(X \leq 3) \) the same way in Step 2, but only summing probabilities up to the third trial.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of Success
In a geometric distribution, the "probability of success" is a fundamental aspect. It represents the likelihood of achieving a favorable outcome in a single trial of a given experiment. For example, if you are flipping a coin to land on heads, the probability of success is 0.5. In our exercise, the probability of successfully aligning the optical data storage product is given as 0.8. This indicates that in each individual trial, there is an 80% chance that the alignment process will be successful.
This metric is crucial because it forms the basis upon which we calculate other probabilities in geometric distributions. It is denoted by \( p \). Consequently, the probability of failure is \( 1-p \), which is 0.2 in this case. Understanding this helps you predict the number of trials needed for your first success.
Cumulative Probability
Cumulative probability adds up the probabilities of obtaining a certain number of successes up to a particular trial. You're essentially summing the probabilities for a series of outcomes, each of which could mark the first success. In the exercise, you are asked to calculate the likelihood of the first success occurring within four trials, which requires finding the cumulative probability.
To do this, you sum the probabilities of success in trials one, two, three, and four. The formula for each is \( P(X=k) = (0.2)^{k-1} \times 0.8 \). You just plug in \( k = 1, 2, 3, \) and \( 4 \). Then, add them together: \( P(X \leq 4) = P(X=1) + P(X=2) + P(X=3) + P(X=4) \). These values give you the comprehensive probability figure for achieving at least one success in up to four trials.
Complement Rule
The complement rule in probability states that the probability of an event not occurring is 1 minus the probability of the event occurring. If you know the probability of something happening, you can easily find out the probability of it not happening using this rule.
In the problem, you need to determine the probability of achieving the first success on or after the fourth trial. It's much easier to calculate the probability of success occurring before the fourth trial and then subtract that from 1 to find the complement.
  • Calculate \( P(X \leq 3) \), the cumulative probability of success within three tries.
  • Subtract this from 1 to find \( P(X \geq 4) \).
This method gives you the probability that the first success requires at least four trials, which is much less computationally intensive.
Independent Trials
Independent trials imply that the outcome of one trial does not affect the outcome of another. In the context of probability and geometric distribution, each trial stands alone.
For example, if you're trying to achieve a successful alignment, each attempt is independent - meaning success in one attempt doesn't influence the next. This is crucial because it allows us to apply the geometric distribution model.
  • Probability of success stays constant at 0.8 for every trial.
  • Probability of failure remains 0.2 regardless of what happened on previous trials.
Understanding independence helps you apply these models correctly and compute probabilities without dependencies or changes across trials.

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