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Patient response to a generic drug to control pain is scored on a 5 -point scale where a 5 indicates complete relief. Historically, the distribution of scores is $$ \begin{array}{lllll} 1 & 2 & 3 & 4 & 5 \\ 0.05 & 0.1 & 0.2 & 0.25 & 0.4 \end{array} $$ Two patients, assumed to be independent, are each scored. (a) What is the probability mass function of the total score? (b) What is the probability mass function of the average score?

Short Answer

Expert verified
(a) PMF of \( T \) is from 2 to 10, (b) PMF of \( A \) is derived from PMF of \( T \).

Step by step solution

01

Define the random variables

Let \( X_1 \) and \( X_2 \) be the scores of the first and second patient, respectively. Both are independent random variables with the possible scores \( \{1, 2, 3, 4, 5\} \) and the corresponding probabilities are \( P(X_i = k) \) for each score \( k \).
02

Calculate PMF for the total score

Define \( T = X_1 + X_2 \) as the total score. The possible values for \( T \) range from 2 to 10. For each possible value \( t \), compute \( P(T = t) \) by summing \( P(X_1 = x_1) \cdot P(X_2 = x_2) \) over all pairs \((x_1, x_2)\) such that \( x_1 + x_2 = t \).
03

Calculate PMF for the average score

Define \( A=\frac{X_1 + X_2}{2} \) as the average score. The possible average values for \( A \) are 1.0, 1.5, ..., 5.0. Each average value arises from specific combinations of \( X_1 \) and \( X_2 \). Compute \( P(A = a) \) by summing the probabilities \( P(X_1 = x_1, X_2 = x_2) \) for each distinct combination that results in the specific average \( a \). Note that since \( A \) is from averaging two scores, it might not require new calculations if derived from the PMF of \( T \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
Random variables are fundamental concepts in probability theory, used to model uncertain outcomes. In this exercise, the scores given to two patients are represented as random variables, denoted as \( X_1 \) and \( X_2 \). Each variable describes possible outcomes, here being the scores \( \{1, 2, 3, 4, 5\} \).
A random variable essentially assigns a numeric value to each potential event in a sample space. A key aspect is that it can take on different values, each with a specific probability. For our patients, these probabilities are given in the problem. For example, the probability of either patient receiving a score of 1 is 0.05.
Understanding random variables is crucial as they allow analysis of probability distributions such as the probability mass function, which shows how probabilities are distributed over possible values.
Independence
Independence is a vital concept when dealing with multiple random variables. Two random variables are said to be independent if the occurrence of one does not affect the probability of the other. In the patient drug score scenario, \( X_1 \) and \( X_2 \) are considered independent.
The implication here is that the treatment effectiveness for one patient does not influence the effectiveness for the other. Therefore, calculating probabilities involving more than one random variable, such as their total or average score, can be approached by multiplying their individual probabilities. For example, to find the joint probability of one patient scoring 3 and the other scoring 4, you multiply their individual probabilities: \( P(X_1 = 3) \times P(X_2 = 4) \).
Recognizing independence simplifies many probability calculations, a key tool making it easier to understand joint distributions.
Total Score
The total score is derived by summing the scores given to each patient, or \( T = X_1 + X_2 \). This represents a new random variable whose values range from 2 (\(1+1\)) to 10 (\(5+5\)). Calculating the probability mass function (PMF) for \( T \) involves finding the probability of each possible outcome.
To do this, you calculate \( P(T = t) \) for each value by summing the products of probabilities of each unique pair \( (x_1, x_2) \) that results in \( x_1 + x_2 = t \). This method allows us to comprehend how likely each total score scenario is, considering the independence of \( X_1 \) and \( X_2 \).
  • For example, for \( T = 3 \), we add \( P(X_1 = 1) \cdot P(X_2 = 2) \) and \( P(X_1 = 2) \cdot P(X_2 = 1) \).
Understanding total score helps us in aggregated analysis where individual outcomes contribute towards a combined metric.
Average Score
The average score is another derived metric, calculated as \( A = \frac{X_1 + X_2}{2} \). This operation results in possible values such as 1.0, 1.5, and up to 5.0. Here, the average score gives insight into the expected score per patient on average.
To find the probability of each average score, you identify combinations of \( X_1 \) and \( X_2 \) that yield the specific average and calculate the sum of their joint probabilities. Often, if the PMF of the total score \( T \) is already known, it can directly help in determining the PMF of \( A \) due to the straightforward relationship between total and average score.
  • For instance, the average score of 2.5 occurs when the total score \( T = 5 \) from pairs like \( (1,4) \), \( (2,3) \).
Understanding average scores is beneficial for interpreting general trends and expectations from the collected data without focusing on individual details.

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Most popular questions from this chapter

Suppose that a healthcare provider selects 20 patients randomly (without replacement) from among 500 to evaluate adherence to a medication schedule. Suppose that \(10 \%\) of the 500 patients fail to adhere with the schedule. Determine the following: (a) Probability that exactly \(10 \%\) of the patients in the sample fail to adhere. (b) Probability that fewer than \(10 \%\) of the patients in the sample fail to adhere. (c) Probability that more than \(10 \%\) of the patients in the sample fail to adhere. (d) Mean and variance of the number of patients in the sample who fail to adhere.

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