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Determine the cumulative distribution function of a binomial random variable with \(n=3\) and \(p=1 / 4\).

Short Answer

Expert verified
The CDF for \( n=3 \) and \( p=1/4 \) gives probabilities: \( F(0)=27/64 \), \( F(1)=54/64 \), \( F(2)=63/64 \), \( F(3)=1 \).

Step by step solution

01

Understanding the Cumulative Distribution Function (CDF)

The cumulative distribution function (CDF) of a binomial random variable is the probability that the random variable is less than or equal to a certain value. For a binomial random variable with parameters \( n \) and \( p \), the CDF at a value \( x \) is denoted by \( F(x) \) and is the sum of probabilities from \( 0 \) to \( x \).
02

Binomial Probability Formula

The probability mass function (PMF) for a binomial variable \( X \) with \( n \) trials and success probability \( p \) is given by the formula: \[ P(X = x) = \binom{n}{x} p^x (1-p)^{n-x} \] where \( \binom{n}{x} \) is the binomial coefficient, calculated as \( \frac{n!}{x!(n-x)!} \).
03

Calculate Individual Probabilities

For \( n=3 \) and \( p=1/4 \), calculate \( P(X = x) \) for each possible value of \( x \), i.e., \( x = 0, 1, 2, 3 \):\[ P(X = 0) = \binom{3}{0} (\frac{1}{4})^0 (\frac{3}{4})^3 = 1 \cdot 1 \cdot \frac{27}{64} = \frac{27}{64} \]\[ P(X = 1) = \binom{3}{1} (\frac{1}{4})^1 (\frac{3}{4})^2 = 3 \cdot \frac{1}{4} \cdot \frac{9}{16} = \frac{27}{64} \]\[ P(X = 2) = \binom{3}{2} (\frac{1}{4})^2 (\frac{3}{4})^1 = 3 \cdot \frac{1}{16} \cdot \frac{3}{4} = \frac{9}{64} \]\[ P(X = 3) = \binom{3}{3} (\frac{1}{4})^3 (\frac{3}{4})^0 = 1 \cdot \frac{1}{64} \cdot 1 = \frac{1}{64} \]
04

Compute Cumulative Probabilities

Using the probabilities calculated, find the cumulative probability \( F(x) \) for each \( x \):\[ F(0) = P(X \leq 0) = P(X = 0) = \frac{27}{64} \]\[ F(1) = P(X \leq 1) = P(X = 0) + P(X = 1) = \frac{27}{64} + \frac{27}{64} = \frac{54}{64} \]\[ F(2) = P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = \frac{54}{64} + \frac{9}{64} = \frac{63}{64} \]\[ F(3) = P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = \frac{63}{64} + \frac{1}{64} = 1 \]
05

Summarize the CDF

The cumulative distribution function of the binomial random variable with \( n=3 \) and \( p=\frac{1}{4} \) is as follows:- \( F(0) = \frac{27}{64} \)- \( F(1) = \frac{54}{64} \)- \( F(2) = \frac{63}{64} \)- \( F(3) = 1 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cumulative Distribution Function (CDF)
Imagine you have a random variable that follows a binomial distribution. The cumulative distribution function (CDF) helps you understand the probability that this random variable takes a value less than or equal to a certain number. In simpler terms, it tells us the likelihood of finding a result up to a specific point. For a binomial random variable with parameters \( n \) (number of trials) and \( p \) (probability of success), the CDF for a value \( x \) is given by \( F(x) \), which is the sum of probabilities from \( 0 \) to \( x \).

If we consider our example with \( n = 3 \) and \( p = 1/4 \), the CDF \( F(x) \) is calculated by adding up the probabilities for all possible outcomes up to \( x \). This gives us cumulative probabilities, such as \( F(0) = \frac{27}{64} \), \( F(1) = \frac{54}{64} \), \( F(2) = \frac{63}{64} \), and finally \( F(3) = 1 \), showing the probability of all possible outcomes being 100%.
Probability Mass Function (PMF)
The probability mass function (PMF) provides a way to specify the probability of each possible outcome of a discrete random variable. In the context of a binomial distribution, it tells us the probability that a binomial random variable equals a particular value. The formula for the PMF of a binomial random variable \( X \) with \( n \) trials and probability of success \( p \) is:
  • \( P(X = x) = \binom{n}{x} p^x (1-p)^{n-x} \)
You can read this formula as: the probability of getting exactly \( x \) successes in \( n \) trials. In our specific example where \( n = 3 \) and \( p = 1/4 \), we calculate \( P(X = 0) \), \( P(X = 1) \), \( P(X = 2) \), and \( P(X = 3) \) using this formula to know the chances of getting those exact numbers of successes. For example:

* \( P(X = 0) = \frac{27}{64} \) means there's a probability of 27/64 that no trials are successful.
Binomial Coefficient
A key player in calculating the PMF is the binomial coefficient, often represented as \( \binom{n}{x} \). This coefficient tells us how many ways we can choose \( x \) successes from \( n \) trials, and is calculated using the formula:
  • \( \binom{n}{x} = \frac{n!}{x!(n-x)!} \)
Here, \(!\) stands for factorial, which means multiplying a series of descending natural numbers. For instance, \( 3! = 3 \times 2 \times 1 = 6 \).

If we take our example, \( \binom{3}{0} = 1 \), \( \binom{3}{1} = 3 \), \( \binom{3}{2} = 3 \) and \( \binom{3}{3} = 1 \). These values are crucial to computing the PMF, as they indicate the different combinations of successful trial outcomes.
Discrete Random Variable
A discrete random variable is a type of random variable that can take on a countable number of distinct values. In other words, you can "count" the outcomes that a discrete random variable might take. This is in contrast to continuous random variables, which can take on an infinite number of outcomes.

In the case of a binomial distribution, our random variable is the number of successful trials, and this is a discrete variable. For example, with \( n = 3 \), our discrete random variable could take values like \( 0, 1, 2, \) or \( 3 \), each representing a possible outcome of successes in the binomial experiment.

The concept of discrete random variables is crucial for understanding distributions like the binomial distribution, where we deal with probabilities associated with specific, clearly defined outcomes.

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Most popular questions from this chapter

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