/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 85 he number of pages in a PDF docu... [FREE SOLUTION] | 91Ó°ÊÓ

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he number of pages in a PDF document you create has a discrete uniform distribution from five to nine pages (including the end points). What are the mean and standard deviation of the number of pages in the document?

Short Answer

Expert verified
The mean is 7, and the standard deviation is approximately 1.41.

Step by step solution

01

Define the Discrete Uniform Distribution

A discrete uniform distribution is defined as one where a finite number of outcomes are equally likely. In this case, the pages can be any integer value from 5 to 9. So, the possible values are 5, 6, 7, 8, and 9.
02

Calculate the Mean

The mean of a discrete uniform distribution can be calculated using the formula for the mean of discrete uniform distribution: \( \mu = \frac{a + b}{2} \), where \( a \) is the smallest value and \( b \) is the largest value. Here, \( a = 5 \) and \( b = 9 \). Therefore, \( \mu = \frac{5 + 9}{2} = 7 \).
03

Calculate the Standard Deviation

The standard deviation of a discrete uniform distribution is calculated as \( \sigma = \sqrt{\frac{(b-a+1)^2-1}{12}} \). Substituting the values, \( b = 9 \) and \( a = 5 \), gives \( \sigma = \sqrt{\frac{(9-5+1)^2-1}{12}} = \sqrt{\frac{5^2-1}{12}} = \sqrt{\frac{24}{12}} = \sqrt{2} \approx 1.41 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean of Discrete Uniform Distribution
The mean, or average, of a discrete uniform distribution is calculated by simply finding the midpoint between the smallest and largest values. This is because, in a discrete uniform distribution, every outcome is equally likely. This balance results in the mean being right in the center of the values.For example, if you have a PDF document where the number of pages ranges from 5 to 9, you will use 5 as your smallest value (\( a \)) and 9 as your largest value (\( b \)). The formula for finding the mean \( \mu \) is:\[ \mu = \frac{a + b}{2} \]Substituting the values from our scenario gives:\[ \mu = \frac{5 + 9}{2} = 7 \]This tells us that the average number of pages in our PDF document is 7, giving us an easy benchmark for what to expect in terms of document length.
Standard Deviation of Discrete Uniform Distribution
The standard deviation measures how spread out the numbers in a distribution are from the mean. In a discrete uniform distribution, this calculation becomes straightforward with its specific formula. The standard deviation is crucial because it tells us how much variability we can expect.To calculate the standard deviation \( \sigma \), use the formula:\[ \sigma = \sqrt{\frac{(b-a+1)^2-1}{12}} \]Here, substituting the smallest value \( a = 5 \) and the largest value \( b = 9 \), we find:\[ \sigma = \sqrt{\frac{(9-5+1)^2-1}{12}} = \sqrt{\frac{5^2-1}{12}} = \sqrt{\frac{24}{12}} = \sqrt{2} \approx 1.41 \]This result means that most documents will have a number of pages within approximately 1.41 pages from the mean of 7. Understanding this helps you anticipate the diversity in document length.
Probability Distribution
A probability distribution provides a mathematical description of how the probabilities of a random variable are distributed. For a discrete uniform distribution, each outcome is equally likely, meaning each value has the same probability of occurring.In the context of our PDF document, where pages range from 5 to 9, there are five distinct possible outcomes. Each page count (5, 6, 7, 8, 9) has an identical probability since the distribution is uniform.Here’s how to understand the probability:- The total number of outcomes is 5.- The probability of any single outcome is computed by the formula:\[ P(x) = \frac{1}{n} \]where \( n \) is the number of outcomes. Therefore, for each count of pages in the document:\[ P(x) = \frac{1}{5} = 0.2 \]Thus, there is a 20% chance for each number of pages from 5 to 9. Recognizing this uniform spread helps in planning and understanding the random nature of document creation within these bounds.

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