/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 115 The probability that a visitor t... [FREE SOLUTION] | 91Ó°ÊÓ

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The probability that a visitor to a Web site provides contact data for additional information is \(0.01 .\) Assume that 1000 visitors to the site behave independently. Determine the following probabilities: (a) No visitor provides contact data. (b) Exactly 10 visitors provide contact data. (c) More than 3 visitors provide contact data.

Short Answer

Expert verified
(a) Approximately 0.000043, (b) Approximately 0.0000008, (c) Approximately 0.0807.

Step by step solution

01

Identify the Distribution

First, recognize that this is a binomial distribution problem. The probability of success (a visitor provides contact data) is \( p = 0.01 \), the number of trials (visitors) is \( n = 1000 \), and the random variable \( X \) represents the number of visitors providing contact data.
02

Calculate the Probability for (a)

We want the probability that no visitor provides contact data, \( X = 0 \). Use the binomial probability formula: \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \). Substitute \( k = 0 \), \( n = 1000 \), \( p = 0.01 \).\[ P(X = 0) = \binom{1000}{0} (0.01)^0 (0.99)^{1000} = (0.99)^{1000}.\]Calculate \( (0.99)^{1000} \) to find the probability.
03

Calculate the Probability for (b)

Now, find the probability that exactly 10 visitors provide contact data, \( X = 10 \). Use the same binomial probability formula with \( k = 10 \).\[ P(X = 10) = \binom{1000}{10} (0.01)^{10} (0.99)^{990}.\]Calculate \( \binom{1000}{10} \), then multiply by \( (0.01)^{10} \) and \( (0.99)^{990} \).
04

Calculate the Probability for (c)

We need the probability that more than 3 visitors provide contact data, \( P(X > 3) \). This can be calculated using the complement rule: \( P(X > 3) = 1 - P(X \leq 3) \), where \( P(X \leq 3) \) is the sum \( P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) \). Compute each of these probabilities using the binomial formula, then subtract their sum from 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the branch of mathematics that deals with analyzing random events. It might seem daunting, but we encounter probabilities in many everyday scenarios. In the context of this exercise, it helps to imagine each visitor to the website as an independent trial.
Each trial is a distinct chance for a visitor to provide contact information, which we'll call a "success."
The probability of obtaining a "success" is consistent in trials and is denoted as \( p = 0.01 \) in this example.
  • Trials: Each visitor visiting the website is a separate trial.
  • Independent Events: The behavior of one visitor does not affect another visitor.
  • Probability of Success: The likelihood that a visitor provides contact data is \( p = 0.01 \).
Understanding these key points makes it easier to grasp how we can apply probabilistic methods like binomial distribution, which tell us the likelihood of different outcomes of a random event.
Random Variables
Random variables are a way to quantify outcomes of random phenomena. They assign numbers to potential outcomes, simplifying the analysis of probabilities.
In this exercise, we use the random variable \( X \) to represent the number of visitors who decide to provide contact information out of the 1000 total visitors.
  • Type of Random Variable: \( X \) is a discrete random variable because it can only take on whole number values like 0, 1, 2, ..., 1000 under given conditions.
  • Expected Outcome: Using the properties of random variables, you can calculate the expected number of "successes" (contact data provided) through the formula \( E(X) = np \), which simplifies to \( E(X) = 1000 \times 0.01 = 10 \). This is the average number of visitors expected to provide contact data.
Once you understand that \( X \) helps us manage and analyze the probabilities of random events, solving these types of probability problems becomes a breeze.
Statistical Calculations
Statistical calculations are all about applying formulas and methods to find probabilities or outcomes. While they may seem complex, breaking them down into steps makes the whole process manageable.
Let's dive into the calculations for the different parts of this exercise, using the binomial probability formula:
  • Calculating \( P(X = 0) \): To find the probability that no visitors provide contact data, use the formula \( P(X = 0) = \binom{1000}{0} (0.01)^0 (0.99)^{1000} \). The value \( (0.99)^{1000} \) is calculated to get the probability.
  • Calculating \( P(X = 10) \): For exactly 10 visitors, plug \( k = 10 \) into \( P(X = 10) = \binom{1000}{10} (0.01)^{10} (0.99)^{990} \). Utilize a calculator for \( \binom{1000}{10} \) and simplify.
  • Calculating \( P(X > 3) \): For more than 3 visitors providing contact data, use the complement rule: \( P(X > 3) = 1 - P(X \leq 3) \). Compute individual probabilities for \( X = 0, 1, 2, \) and \( 3 \), then sum them. Finally, subtract from 1 to find the result.
Applying these calculations helps you see how powerful statistical tools can simplify complex probability questions. With practice, these methods become intuitive, enabling more accurate data analysis and a better understanding of random events.

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