/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Errors in an experimental transm... [FREE SOLUTION] | 91Ó°ÊÓ

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Errors in an experimental transmission channel are found when the transmission is checked by a certifier that detects missing pulses. The number of errors found in an eight-bit byte is a random variable with the following distribution: $$ F(x)=\left\\{\begin{array}{lr} 0 & x<1 \\ 0.7 & 1 \leq x<4 \\ 0.9 & 4 \leq x<7 \\ 1 & 7 \leq x \end{array}\right. $$ Determine each of the following probabilities: (a) \(P(X \leq 4)\) (b) \(P(X>7)\) (c) \(P(X \leq 5)\) (d) \(P(X>4)\) (e) \(P(X \leq 2)\)

Short Answer

Expert verified
(a) 0.9, (b) 0, (c) 0.9, (d) 0.1, (e) 0.7.

Step by step solution

01

Determine Probability for (a)

The question asks for the probability of \(X \leq 4\). From the distribution function \(F(x)\), for \(4 \leq x < 7\), we see that \(F(4) = 0.9\). Therefore, \(P(X \leq 4) = 0.9\).
02

Determine Probability for (b)

To find \(P(X > 7)\), we observe from \(F(x)\) that for \(x \geq 7\), \(F(x) = 1\). Since \(P(X > 7) = 1 - F(7)\), and \(F(7) = 1\), it implies \(P(X > 7) = 0\).
03

Determine Probability for (c)

For \(P(X \leq 5)\), we consider that for values up to 5, \(5 \leq 7\), hence we use \(F(5)\) which falls in the category \(4 \leq x < 7\). Thus, \(P(X \leq 5) = 0.9\).
04

Determine Probability for (d)

To calculate \(P(X > 4)\), we need to use the complement rule \(P(X > 4) = 1 - P(X \leq 4)\). From Step 1, we know \(P(X \leq 4) = 0.9\). Thus, \(P(X > 4) = 1 - 0.9 = 0.1\).
05

Determine Probability for (e)

We need \(P(X \leq 2)\). Since \(1 \leq x < 4\) gives \(F(x) = 0.7\), we immediately know \(P(X \leq 2) = F(2) = 0.7\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable
In probability and statistics, a "Random Variable" is a fundamental concept. It's essentially a variable whose possible values are outcomes of a random phenomenon. Imagine you are flipping a coin or rolling a die; these are random processes, and a random variable could represent the result. In this exercise, the number of errors found in an eight-bit byte serves as our random variable, denoted as \( X \). This random variable takes on discrete values, depending on the number of errors discovered during transmission.

Random variables can broadly be classified into two categories:
  • Discrete Random Variables: These have countable possible values, like the roll of a die (1 through 6) or the number of errors detected in this context.
  • Continuous Random Variables: These can take any value within a given range, like the time it takes for a certifier to detect errors, which might range from seconds to minutes.
Understanding how random variables work allows us to calculate probabilities using distribution functions. Here, the probabilities of specific scenarios for the number of errors are determined using a defined distribution function \( F(x) \).
Cumulative Distribution Function
The "Cumulative Distribution Function" (CDF), denoted as \( F(x) \), is a crucial concept in understanding the behavior of a random variable. It looks at the probability that a random variable \( X \) will take a value less than or equal to \( x \). Essentially, the CDF helps in determining how the probability accumulates as the variable increases.

For the transmission errors case given, the CDF is piecewise defined. This means that the distribution changes its probability value at certain intervals. For instance:
  • \( F(x) = 0 \) for \( x < 1 \) – There's zero probability for finding errors less than 1.
  • \( F(x) = 0.7 \) for \( 1 \leq x < 4 \) – There's a 70% chance the number of errors is less than 4.
  • \( F(x) = 0.9 \) for \( 4 \leq x < 7 \) – There's an 90% chance that the errors number up to 6.
  • \( F(x) = 1 \) for \( 7 \leq x \) – All probabilities sum up to 1 when errors equal or exceed 7.
Using this CDF, we can easily find probabilities for the random variable by looking at these defined intervals and values. This is particularly useful for determining probabilities like \( P(X \leq 4) \) or even enabling calculations for cases like \( P(X \leq 5) \).
Complement Rule
One handy concept in probability calculations is the "Complement Rule." It helps find the probability of an event not occurring by using the information about the event occurring. Mathematically, it’s expressed as:

\[ P(A^c) = 1 - P(A) \]

Where \( A \) is an event, and \( A^c \) is its complement, meaning the event does not happen. For the problem at hand, this rule is particularly useful. For instance, finding \( P(X > 4) \) is easier by using the complement rule:

  • Since \( P(X > 4) = 1 - P(X \leq 4) \), and from the CDF we've established \( P(X \leq 4) = 0.9 \).
  • Using the complement rule, we easily calculate \( P(X > 4) = 1 - 0.9 = 0.1 \).
The complement rule significantly simplifies problems where the direct calculation of an event seems more complex than calculating its opposite. Additionally, it gives a broader understanding of how probabilities work together, ensuring all possibilities total to 1.

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