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A state runs a lottery in which six numbers are randomly selected from 40 without replacement. A player chooses six numbers before the state's sample is selected. (a) What is the probability that the six numbers chosen by a player match all six numbers in the state's sample? (b) What is the probability that five of the six numbers chosen by a player appear in the state's sample? (c) What is the probability that four of the six numbers chosen by a player appear in the state's sample? (d) If a player enters one lottery each week, what is the expected number of weeks until a player matches all six numbers in the state's sample?

Short Answer

Expert verified
(a) \( \frac{1}{3,838,380} \) (b) \( \frac{204}{3,838,380} \) (c) \( \frac{8,415}{3,838,380} \) (d) 3,838,380 weeks.

Step by step solution

01

Understanding the Probabilities Involved in Matching Numbers

To find the probability that the player's numbers match all the numbers in the state's sample (part a), we calculate the total number of ways to choose 6 numbers from 40 and find the one specific combination of numbers that matches the player's choice. This involves the concept of combinations. The formula for combinations is given by \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose. Here, \( n = 40 \) and \( r = 6 \).
02

Calculate the Total Number of Combinations

The total number of ways to choose 6 numbers from 40 is given by \( \binom{40}{6} \). Calculating this gives:\[ \binom{40}{6} = \frac{40!}{6!(40-6)!} = 3,838,380. \] This is the total number of possible ways the state's numbers can be drawn.
03

Probability for Matching All Six Numbers (Part a)

Since there is only one way to choose exactly the 6 numbers that match the player's choice, the probability of matching all numbers is:\[ P(\text{match all 6}) = \frac{1}{\binom{40}{6}} = \frac{1}{3,838,380}. \]
04

Probability of Matching Five of Six Numbers (Part b)

To match five of the six numbers, the player must select 5 numbers correctly and 1 number incorrectly. Calculate the combinations of choosing 5 correct numbers out of 6:\[ \binom{6}{5} = 6. \]Then, choose 1 incorrect number from the 34 remaining numbers (since 1 number is incorrect out of 40):\[ \binom{34}{1} = 34. \]The total number of outcomes that yield 5 matches is:\[ \binom{6}{5} \times \binom{34}{1} = 6 \times 34 = 204. \]Thus, the probability is:\[ P(\text{match 5}) = \frac{204}{\binom{40}{6}} = \frac{204}{3,838,380}. \]
05

Probability of Matching Four of Six Numbers (Part c)

For matching four numbers, the player selects 4 correct numbers and 2 incorrect ones. First, choose 4 correct numbers:\[ \binom{6}{4} = 15. \]Then, choose 2 incorrect numbers from the 34 remaining:\[ \binom{34}{2} = 561. \]Thus, the total combinations for 4 matches are:\[ 15 \times 561 = 8,415. \]The probability of matching exactly four numbers is:\[ P(\text{match 4}) = \frac{8,415}{3,838,380}. \]
06

Expected Number of Weeks to Match All Numbers (Part d)

The expected number of weeks until a match is achieved is the reciprocal of the probability of matching all 6 numbers. This is because, on average, that fraction of outcomes results in a match. Thus, the expected number of weeks is:\[ E = \frac{1}{P(\text{match all 6})} = 3,838,380. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a branch of mathematics dealing with the study of combinations, arrangements, and selections of objects. It's particularly useful in calculating possibilities in games like lotteries. In combinatorics, the concept of counting helps us determine the number of ways a certain event can occur, which is crucial for probability calculations. When choosing lottery numbers, for example, combinatorics allows us to calculate how many different ways we can pick a subset of numbers from a larger set.
Let's consider the lottery problem involving 40 possible numbers where a player has to select 6. The fundamental task is to find the total number of different combinations of 6 numbers that can be chosen from 40. This is achieved using the formula for combinations, denoted as \( \binom{n}{r} \), which reads as 'n choose r'. This formula doesn't depend on the order of selection, unlike permutations, making it suitable for situations like lotteries where order doesn't matter.
Expected Value
Expected value is a concept that helps in predicting the average outcome of a random event over a large number of trials. It's a sort of mean-value of all possible outcomes, weighted by their probabilities. In a lottery, when you want to know how many weeks, on average, it would take for a player to match all 6 numbers, you calculate the expected value.
To find the expected number of weeks to get a perfect match, you take the inverse of the probability of matching all 6 numbers. This gives you the average number of trials (or weeks) needed. In essence, if the probability of winning in one week is very low, then the expected number of weeks to win will be high, which is common in lotteries. Thus, if the probability of matching all numbers is \( \frac{1}{3,838,380} \), the expected number of weeks is simply \( 3,838,380 \). This shows how rare and difficult it is to win a lottery.
Binomial Coefficient
The binomial coefficient is central in combinatorics, especially when determining probabilities in lotteries. It is represented by \( \binom{n}{r} \) and is read as 'n choose r'. It gives us the number of ways to choose 'r' elements from a set of 'n' elements.
The formula for the binomial coefficient is given by \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \), where \(!\) denotes factorial, the product of all positive integers up to that number. In our lottery example, where a player picks 6 numbers out of 40, the binomial coefficient \( \binom{40}{6} \) tells us the total number of different possible combinations of numbers. Calculating this helps in understanding the rarity of matching all numbers exactly in games of chance like a lottery.
Permutations
Permutations are about the arrangement of objects where order matters. Although not directly applicable to the lottery example provided, understanding permutations helps to distinguish situations where order is important from those where it isn’t. In permutations, different ordering of the same items are considered distinct outcomes.
While the lottery scenario relies on combinations, since the order of numbers doesn't matter, permutations can apply in scenarios where you might need to arrange those numbers in a specific sequence or order. This is crucial when the context involves things like lock combinations or rank-based prioritization, where the list's order suddenly becomes significant. Recognizing when to use permutations versus combinations is vital in solving probability and counting problems across various contexts.

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