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Saguaro cacti are large cacti indigenous to the southwestern United States and Mexico. Assume that the number of saguaro cacti in a region follows a Poisson distribution with a mean of 280 per square kilometer. Determine the following: (a) Mean number of cacti per 10,000 square meters. (b) Probability of no cacti in 10,000 square meters. (c) Area of a region such that the probability of at least two cacti in the region is \(0.9 .\)

Short Answer

Expert verified
Mean is 2.8; probability of no cacti is 0.0608; area is 8,214 square meters.

Step by step solution

01

Convert area from square kilometers to square meters

1 square kilometer is equal to 1,000,000 square meters. Since we are considering a 10,000 square meters area, first convert the mean of the distribution to this new area.The conversion factor is: \[10,000 \text{ square meters} = \frac{10,000}{1,000,000} \text{ square kilometers} \]Multiply the mean by this factor to find the mean for 10,000 square meters:\[\text{Mean for } 10,000 \text{ sqm} = 280 \times \frac{10,000}{1,000,000} = 2.8\]
02

Determine mean number of cacti per 10,000 square meters

The mean number of cacti for a 10,000 square meter area is 2.8.
03

Calculate the probability of no cacti in 10,000 square meters

For a Poisson distribution, the probability of observing \(k\) events in an interval with mean \( \lambda \) is given by:\[P(k; \lambda) = \frac{\lambda^k e^{-\lambda}}{k!}\]Set \(k = 0\) and use the mean \(\lambda = 2.8\):\[P(0; 2.8) = \frac{2.8^0 \cdot e^{-2.8}}{0!} = e^{-2.8} \approx 0.0608\]
04

Calculate the area for probability of at least two cacti to be 0.9

First, calculate the probability of at most one cactus occurring:\[ P(0) + P(1) = 1 - P(X \geq 2) = 0.1 \]Using \(P(0) = e^{-\lambda}\) and \(P(1) = \lambda e^{-\lambda}\), solve for \(\lambda\) such that:\[ e^{-\lambda}(1 + \lambda) = 0.1\]Substitute different values for \(\lambda\) to find this condition numerically.When approximating, get \(\lambda \approx 2.3\).The equivalent area can be found by:\[\text{Area} = \frac{\lambda}{280} \times 1,000,000 \approx \frac{2.3}{280} \times 1,000,000 \approx 8,214 \text{ square meters}\]
05

Interpret results

The mean number of cacti per 10,000 square meters is 2.8. There's approximately a 6.08% chance of finding no cacti in that area. To have at least two cacti with a probability of 0.9, an area of approximately 8,214 square meters is needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
When dealing with a Poisson distribution, the mean (\(\lambda\)) is crucial for understanding event occurrence within a given area. In this problem, the number of saguaro cacti per square kilometer is specified with a mean of 280. However, to find the mean number of cacti in a smaller area, such as 10,000 square meters, a conversion is necessary. Convert the area first, knowing that 1 square kilometer equals 1,000,000 square meters. Hence, 10,000 square meters is a fraction of a square kilometer: \[\frac{10,000}{1,000,000} = 0.01\]Thus, multiply the original mean by this fraction to get the mean number for the smaller area:\[280 \times 0.01 = 2.8\]This calculation shows that the mean number of cacti in 10,000 square meters is 2.8. Understanding how area conversions affect the mean helps in accurately predicting occurrences within specific zones.
Probability Calculation
To calculate the probability of certain events within a Poisson distribution, it's important to apply the probability mass function:\[P(k; \lambda) = \frac{\lambda^k e^{-\lambda}}{k!}\]Here, it defines the probability of observing \(k\) events given a mean \(\lambda\). For example, to find the probability of having no cacti (\(k = 0\)) in a 10,000 square meter area where the mean is 2.8, plug in the values:\[P(0; 2.8) = \frac{2.8^0 \cdot e^{-2.8}}{0!} = e^{-2.8} \approx 0.0608\]This result tells us there is approximately a 6.08% chance of no cacti being present in the given area. Using the Poisson probability formula for different \(k\) values can predict various outcomes, which is invaluable for statistical modeling.
Area Conversion
Converting areas is a practical step when linking probability outcomes to physical space. For instance, how do we determine an area where the likelihood of at least two cacti is 0.9? First, calculate the probability of observing at most one cactus in this area:\[P(0) + P(1) = 1 - P(X \geq 2) = 0.1\]Utilizing the expressions for \(P(0)\) and \(P(1)\), with \(P(0) = e^{-\lambda}\) and \(P(1) = \lambda e^{-\lambda}\), find \(\lambda\) such that:\[e^{-\lambda}(1 + \lambda) = 0.1\]Solve this numerically, and once \(\lambda \approx 2.3\) is identified, convert this into an area. Since this new \(\lambda\) represents the mean for the unexplored area, use proportions to convert back:\[\text{Area} = \frac{2.3}{280} \times 1,000,000 \approx 8,214 \text{ square meters}\]This solution illustrates using mean-based transformations to map probabilities in distinct locations, highlighting the versatility of Poisson distributions in environmental studies.

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