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An article in Knee Surgery, Sports Traumatology, Arthroscopy ["Arthroscopic Meniscal Repair with an Absorbable Screw: Results and Surgical Technique" ( \(2005,\) Vol. \(13,\) pp. \(273-279\) ) cites a success rate of more than \(90 \%\) for meniscal tears with a rim width under \(3 \mathrm{~mm}\), but only a \(67 \%\) success rate for tears of \(3-6 \mathrm{~mm}\). If you are unlucky enough to suffer a meniscal tear of under \(3 \mathrm{~mm}\) on your left knee and one of width \(3-6 \mathrm{~mm}\) on your right knee, what is the probability mass function of the number of successful surgeries? Assume that the surgeries are independent.

Short Answer

Expert verified
The probability mass function is: 0 successful surgeries: 0.033, 1 successful: 0.364, 2 successful: 0.603.

Step by step solution

01

Define the Random Variable

Let's define a random variable, \(X\), representing the number of successful surgeries. Since each knee surgery has two possible outcomes (success or failure), \(X\) can take values 0, 1, or 2, corresponding to 0, 1, or 2 successful surgeries.
02

Determine Probabilities for Each Knee

The probability of a successful surgery for the left knee (tear under 3 mm) is 0.9, and the probability for a successful surgery on the right knee (tear 3-6 mm) is 0.67. These are denoted as \(P(S_L) = 0.9\) and \(P(S_R) = 0.67\).
03

Calculate Probability of 0 Successful Surgeries

The probability of neither surgery being successful is the product of the probabilities of failure for each knee: \(P(0) = (1 - 0.9)(1 - 0.67) = 0.1 \times 0.33 = 0.033\).
04

Calculate Probability of 1 Successful Surgery

There are two scenarios with one successful surgery: 1) Left knee succeeds, right fails or 2) Right knee succeeds, left fails. Thus: \(P(1) = P(S_L)(1 - P(S_R)) + (1 - P(S_L))P(S_R) = 0.9 \times 0.33 + 0.1 \times 0.67 = 0.297 + 0.067 = 0.364\).
05

Calculate Probability of 2 Successful Surgeries

The probability that both surgeries are successful is the product of their individual success probabilities: \(P(2) = 0.9 \times 0.67 = 0.603\).
06

Confirm the Validity of the Probability Mass Function

Confirm the probabilities sum to 1: \(P(0) + P(1) + P(2) = 0.033 + 0.364 + 0.603 = 1.0\), which is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
Random variables are a fundamental concept in probability theory and statistics. They are used to represent outcomes of random processes. In the context of this exercise, we define a random variable, denoted by \(X\), which represents the number of successful knee surgeries. This means that \(X\) can take on discrete values based on the possible outcomes: 0, 1, or 2.

Each value corresponds to a different scenario: 0 indicates neither surgery is successful, 1 denotes one successful surgery, and 2 signifies both surgeries are successful.

It's important to remember that random variables are not just numbers. They describe the probabilities associated with each outcome. The probability mass function (PMF) then gives us the probability of each particular outcome, which is essential in understanding how likely each scenario is.
Independent Events
Independent events are key to solving probability problems, especially when we deal with scenarios like surgeries on two different knees. Two events are said to be independent if the outcome of one does not affect the outcome of the other.

In our exercise, the left knee surgery and the right knee surgery are considered independent events. This assumption allows us to calculate the probability of each surgery being successful separately, without one influencing the other. This is crucial because it simplifies the calculation of joint probabilities.

When two events, A and B, are independent, the probability of both A and B occurring is the product of their individual probabilities: \(P(A \cap B) = P(A) \times P(B)\). This principle underlines our calculations throughout this exercise.
Probability Calculation
Probability calculation is the process of determining how likely an event is to occur. In our scenario, we are calculating the probability of different numbers of successful surgeries.

The calculation steps are straightforward:
  • 0 Successful Surgeries: Multiply the probabilities of both surgeries failing.
  • 1 Successful Surgery: Consider two cases - success on the left and failure on the right, or vice versa. Calculate and sum these probabilities.
  • 2 Successful Surgeries: Multiply the probabilities of success for both surgeries.

For example, the probability of both surgeries being successful, \(P(2)\), involves multiplying the success probabilities, resulting in \(0.9 \times 0.67 = 0.603\). Such calculations allow us to construct a probability mass function (PMF), which outlines the probabilities for each potential outcome of \(X\).
Success Rate Analysis
Understanding success rates is vital in any form of analysis, especially medical procedures. Success rates are essentially probabilities reflecting the likelihood of a positive outcome.

In this case, the success rate for the left knee surgery is \(90\%\), and the right knee surgery is \(67\%\). These percentages translate directly into probabilities (0.9 and 0.67, respectively).

Analyzing these success rates helps us determine the risk and potential outcomes of undergoing these surgeries. Knowing that the surgeries are independent, we can confidently predict the probability of various outcomes. Moreover, the analysis allows for better-informed decisions for treatment, and expectations regarding the likelihood of success.

This sort of analysis gives valuable insights into medical research and patient consultations, providing a clear picture of the benefits and limitations of certain procedures.

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