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The time to failure (in hours) for a laser in a cytometry machine is modeled by an exponential distribution with \(\lambda=0.00004\) (a) What is the probability that the laser will last at least 20,000 hours? (b) What is the probability that the laser will last at most 30,000 hours? (c) What is the probability that the laser will last between 20,000 and 30,000 hours?

Short Answer

Expert verified
(a) 0.4493. (b) 0.6988. (c) 0.1491.

Step by step solution

01

Understanding Exponential Distribution

The exponential distribution is characterized by its rate parameter \( \lambda \). The probability density function is given by \( f(t) = \lambda \cdot e^{-\lambda t} \), and the cumulative distribution function is \( F(t) = 1 - e^{-\lambda t} \). The parameter \( \lambda = 0.00004 \) indicates that the average rate of failure is 0.00004 per hour.
02

Finding Probability of Lasting At Least 20,000 Hours

To find the probability that the laser lasts at least 20,000 hours, use the formula for the survival function, \( S(t) = 1 - F(t) = e^{-\lambda t} \). Substituting \( t = 20000 \), we have:\[ S(20000) = e^{-0.00004 \times 20000} = e^{-0.8} \] Compute \( e^{-0.8} \) to find this probability.
03

Calculating Surviving 20,000 Hours (numerical evaluation)

Evaluate \( e^{-0.8} \) using a calculator:\[ e^{-0.8} \approx 0.4493 \]Hence, the probability that the laser will last at least 20,000 hours is approximately 0.4493.
04

Finding Probability of Lasting At Most 30,000 Hours

The probability of the laser lasting at most 30,000 hours is given by the cumulative distribution function: \[ F(30000) = 1 - e^{-\lambda \times 30000} \]Substitute \( \lambda = 0.00004 \):\[ F(30000) = 1 - e^{-0.00004 \times 30000} = 1 - e^{-1.2} \]Compute \( 1 - e^{-1.2} \) for this probability.
05

Calculating Lasting At Most 30,000 Hours (numerical evaluation)

Evaluate \( e^{-1.2} \):\[ 1 - e^{-1.2} \approx 1 - 0.3012 = 0.6988 \]So, the probability that the laser will last at most 30,000 hours is approximately 0.6988.
06

Finding Probability of Lasting Between 20,000 and 30,000 Hours

For the probability that the laser lasts between 20,000 and 30,000 hours, compute the difference between the cumulative probabilities at these times:\[ P(20000 < T < 30000) = F(30000) - F(20000) \]Previously, \( F(30000) = 0.6988 \) and \( F(20000) = 0.5507 \), so:\[ P(20000 < T < 30000) = 0.6988 - 0.5507 \]
07

Calculating Probability of Lasting Between 20,000 and 30,000 Hours (numerical evaluation)

Compute the difference:\[ 0.6988 - 0.5507 = 0.1491 \]Thus, the probability that the laser lasts between 20,000 and 30,000 hours is approximately 0.1491.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Understanding probability calculations in the context of an exponential distribution is essential. It helps us make predictions about certain events occurring over continuous time. The exponential distribution, known for modeling time until an event, like a machine failure, involves the rate parameter \(\lambda\).
- In the original exercise, the failure time for a laser machine is modeled using \(\lambda = 0.00004\) per hour.
- The formula \(f(t) = \lambda \cdot e^{-\lambda t}\) represents the probability density function, describing how probabilities are distributed over time.

This setup allows us to calculate probabilities for different scenarios like:
  • Lasting at least a certain time
  • Lasting at most a certain time
  • Lasting between two specific times
These probabilities give insights into how long the machine is likely to operate before failing, making it useful for maintenance planning and risk management.
Cumulative Distribution Function
The cumulative distribution function (CDF) is a fundamental concept in probability and statistics. For an exponential distribution, the CDF is used to determine the probability that a random variable is less than or equal to a certain value.

In the case of this exercise, we examine the probability of the laser lasting a certain amount of time. The CDF is given by:
  • \(F(t) = 1 - e^{-\lambda t}\)
- To find the probability that the laser lasts at most 30,000 hours, we simply evaluate the CDF at \(t = 30,000\).
- Mathematically, this becomes \(1 - e^{-0.00004 \times 30000}\), computed as approximately 0.6988.

The CDF helps us understand the proportion of instances where the laser may fail up to that point in time.
It is especially useful for calculating probabilities over ranges, as seen when determining the likelihood of the laser lasting at most or between certain times.
Survival Function
The survival function complements the cumulative distribution function by focusing on the probability that a system or component lasts longer than a specified time. Also known as the reliability function, the survival function is crucial in scenarios where duration is important.

To calculate the probability that the laser will last at least 20,000 hours, we use the survival function \( S(t) = e^{-\lambda t} \). This function represents the event that the laser continues to function beyond the given time period.

- For 20,000 hours, the computation becomes \( e^{-0.00004 \times 20000} \), which is approximately 0.4493, indicating a 44.93% chance the laser will exceed this time.

Using the survival function, engineers and maintenance teams can better prepare for equipment reliability and plan for replacements, minimizing operational disruptions.

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