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A European standard value for a low-emission window glazing uses 0.59 as the proportion of solar energy that enters a room. Suppose that the distribution of the proportion of solar energy that enters a room is a beta random variable (a) Calculate the mode, mean, and variance of the distribution for \(\alpha=3\) and \(\beta=1.4\) (b) Calculate the mode, mean, and variance of the distribution for \(\alpha=10\) and \(\beta=6.25\) (c) Comment on the difference in dispersion in the distributions from the previous parts.

Short Answer

Expert verified
(a) Mode: 0.8333, Mean: 0.6818, Variance: 0.1448. (b) Mode: 0.6316, Mean: 0.6154, Variance: 0.1383. (c) First distribution has greater dispersion.

Step by step solution

01

Understanding the Beta Distribution

The beta distribution is a family of continuous probability distributions defined on the interval [0, 1], parameterized by two positive shape parameters, \( \alpha \) and \( \beta \). The probability density function of a beta distribution is \( f(x; \alpha, \beta) = \frac{x^{\alpha-1}(1-x)^{\beta-1}}{B(\alpha, \beta)} \), where \( B(\alpha, \beta) \) is the beta function.
02

Analyzing Case (a): \(\alpha=3\), \(\beta=1.4\)

For the given beta distribution, the mode is calculated as \( \frac{\alpha - 1}{\alpha + \beta - 2} = \frac{3 - 1}{3 + 1.4 - 2} = \frac{2}{2.4} = 0.8333 \). The mean is calculated as \( \frac{\alpha}{\alpha + \beta} = \frac{3}{3 + 1.4} = \frac{3}{4.4} = 0.6818 \). The variance is \( \frac{\alpha \beta}{(\alpha + \beta)^2 (\alpha + \beta + 1)} = \frac{3 \times 1.4}{(3 + 1.4)^2 (3 + 1.4 + 1)} = \frac{4.2}{29.04} = 0.1448 \).
03

Analyzing Case (b): \(\alpha=10\), \(\beta=6.25\)

For this beta distribution, the mode is \( \frac{\alpha - 1}{\alpha + \beta - 2} = \frac{10 - 1}{10 + 6.25 - 2} = \frac{9}{14.25} = 0.6316 \). The mean is \( \frac{\alpha}{\alpha + \beta} = \frac{10}{10 + 6.25} = \frac{10}{16.25} = 0.6154 \). The variance is \( \frac{\alpha \beta}{(\alpha + \beta)^2 (\alpha + \beta + 1)} = \frac{10 \times 6.25}{(10 + 6.25)^2 (10 + 6.25 + 1)} = \frac{62.5}{451.5625} = 0.1383 \).
04

Comparing Dispersion

The variance in the first distribution (0.1448) is slightly higher than in the second distribution (0.1383), indicating a larger spread of values around the mean for the first case. This shows that as \( \alpha \) and \( \beta \) increase while maintaining a roughly similar ratio, the distribution tends to become more concentrated around its mean.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
In any probability distribution, the probability density function (PDF) provides a way to determine how likely certain outcomes are. For the beta distribution, it's essential to understand that it is defined only on the interval [0, 1]. This is ideal for modeling proportions, such as the proportion of solar energy entering a room.

The formula for the beta distribution is given by:
  • \[ f(x; \alpha, \beta) = \frac{x^{\alpha-1}(1-x)^{\beta-1}}{B(\alpha, \beta)} \]
  • This function helps to understand how probabilities are distributed over this interval.
  • Here, \( B(\alpha, \beta) \) is the beta function, an integral that normalizes the distribution.
This PDF becomes crucial when conducting further analyses like calculating mean, variance, and understanding dispersion. Each shape parameter \( \alpha \) and \( \beta \) influences the form of this curve significantly, affecting skewness and kurtosis, which tell us how data is distributed around the mean.
Shape Parameters
The shape parameters \( \alpha \) and \( \beta \) in the beta distribution define its form and characteristics, such as skewness and spread. They are akin to the knobs you might turn to alter a shape on a graph. Here's what they do:

  • \( \alpha \) and \( \beta \) must be positive values.
  • A larger \( \alpha \) relative to \( \beta \) skews the distribution to the right, closer to 1, while a larger \( \beta \) skews it to the left, towards 0.
  • When both parameters are equal (e.g., \( \alpha = \beta \)), the distribution is symmetric and centered.
With \( \alpha = 3 \) and \( \beta = 1.4 \), the distribution is right-skewed and peaks closer to 1, while \( \alpha = 10 \) and \( \beta = 6.25 \) lead to a distribution that is also right-skewed but with a shape indicating more concentration around its mean.
Mean and Variance Calculations
Calculating the mean and variance of the beta distribution helps summarize the data in the distribution. The formulas are straightforward but revealing:

  • **Mean:** \[ \text{Mean} = \frac{\alpha}{\alpha + \beta} \]
  • For \( \alpha = 3 \) and \( \beta = 1.4 \), the mean calculates to 0.6818.
  • Mean offers a point of central tendency where we might expect data to cluster.
  • **Variance:** \[ \text{Variance} = \frac{\alpha \beta}{(\alpha + \beta)^2 (\alpha + \beta + 1)} \]
  • For \( \alpha = 3 \) and \( \beta = 1.4 \), variance is 0.1448, whereas for \( \alpha = 10 \) and \( \beta = 6.25 \), variance is 0.1383.
Mean and variance offer insights into central values and data spread, setting the stage for dispersion analysis which compares the concentration or spread across different parameter settings.
Dispersion Analysis
Dispersion analysis in the context of the beta distribution examines how wide or narrow a distribution appears based on the variance.

The variance tells us how much spread exists. In comparing our two cases:
  • Case (a) with \( \alpha = 3 \) and \( \beta = 1.4 \) results in a variance of 0.1448, indicating a wider spread.
  • Case (b) with \( \alpha = 10 \) and \( \beta = 6.25 \) achieves a variance of 0.1383, suggesting a narrower concentration.
  • A smaller variance in case (b) implies data values are more consistently near the mean.
This understanding means that as \( \alpha \) and \( \beta \) increase, particularly maintaining a balance, the noise or variability around the center tends to decrease. This can be crucial in applications where predictability and data robustness are valued.

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