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Suppose the length of stay (in hours) at an emergency department is modeled with a lognormal random variable \(X\) with \(\theta=1.5\) and \(\omega=0.4\). Determine the following: (a) mean and variance (b) \(P(X<8)\) (c) Comment on the difference between the probability \(P(X<0)\) calculated from this lognormal distribution and a normal distribution with the same mean and variance.

Short Answer

Expert verified
(a) Mean: \( e^{1.58} \); Variance: \(( e^{0.16} - 1 ) e^{3.08}\). (b) Use standard normal table for \( Z \). (c) \( P(X<0)=0 \) for lognormal; non-zero for normal.

Step by step solution

01

Understanding the Lognormal Distribution

A lognormal random variable is a distribution of a random variable whose logarithm is normally distributed. If a random variable \( X \) is lognormally distributed with scale parameter \( \theta \) and shape parameter \( \omega \), it means that \( \ln(X) \) is normally distributed with mean \( \theta \) and standard deviation \( \omega \).
02

Calculating the Mean of X

For a lognormal distribution, the mean \( E[X] \) is given by:\[ E[X] = e^{\theta + \frac{\omega^2}{2}} \]Substitute \( \theta = 1.5 \) and \( \omega = 0.4 \) to find the mean:\[ E[X] = e^{1.5 + \frac{0.4^2}{2}} = e^{1.5 + 0.08} = e^{1.58} \]Calculate \( e^{1.58} \) to get the mean.
03

Calculating the Variance of X

The variance \( \text{Var}(X) \) of a lognormal distribution is given by:\[ \text{Var}(X) = \left( e^{\omega^2} - 1 \right) e^{2\theta + \omega^2} \]Substitute \( \theta = 1.5 \) and \( \omega = 0.4 \) into the formula:\[ = \left( e^{0.4^2} - 1 \right) e^{2\cdot 1.5 + 0.4^2} = \left( e^{0.16} - 1 \right) e^{3.08} \]Calculate \( e^{0.16} \) and \( e^{3.08} \) to find the variance.
04

Calculating P(X

Convert \( X < 8 \) to a standard normal variable:\[ Z = \frac{\ln(8) - \theta}{\omega} \]Calculate \( \ln(8) \), and then evaluate\[ Z = \frac{\ln(8) - 1.5}{0.4} \]Use the standard normal distribution to find \( P(Z < \text{calculated value}) \) which will equal \( P(X < 8) \).
05

Analyzing P(X

Since a lognormal distribution models the logarithm of a normal distribution, it cannot take on negative values; hence, \( P(X<0) = 0 \) for a lognormal distribution. Conversely, a normal distribution can take negative values, so \( P(X<0) \) would not be zero if the normal distribution has the same mean and variance as \( X \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Variance Calculation
A lognormal distribution is a bit like a "transformed" version of a normal distribution. To find the mean and variance of our lognormal distribution, we first need to think about the related normal distribution of the variable's logarithm.
For a lognormal variable, the mean is calculated using the formula:
  • \[ E[X] = e^{\theta + \frac{\omega^2}{2}} \]
If you plug in the values \( \theta = 1.5 \) and \( \omega = 0.4 \), you get:\[ E[X] = e^{1.5 + \frac{0.4^2}{2}} = e^{1.58} \]Once you compute \( e^{1.58} \), you can find the exact mean value.
Variance, on the other hand, shows how much values deviate from the mean. For the variance of a lognormal distribution, use:
  • \[ \text{Var}(X) = \left( e^{\omega^2} - 1 \right) e^{2\theta + \omega^2} \]
Substitute the known values:\[ = \left( e^{0.4^2} - 1 \right) e^{3.08} \]Calculate \( e^{0.16} \) and then \( e^{3.08} \), to find the variance of our lognormal variable.
Probability Calculation
Calculating the probability \( P(X < 8) \) for a lognormal distribution involves a conversion to make things simpler. This conversion turns the lognormal problem into a normal distribution problem. If \( X \) is lognormal, then \( \ln(X) \) is normal.
First, convert to standard normal by computing:
  • Find \( Z \), a standard normal variable, using the formula:
\[ Z = \frac{\ln(8) - \theta}{\omega} \]Calculate \( \ln(8) \), then plug in \( \theta = 1.5 \) and \( \omega = 0.4 \).
Find the standard normal cumulative probability for this \( Z \) value. This gives you \( P(X < 8) \), by checking a standard normal distribution table or using a calculator.
Comparison with Normal Distribution
The way a lognormal distribution behaves compared to a normal distribution can be interesting. A lognormal distribution, defined only for positive values, has some key differences when it comes to probabilities related to zero.
For a lognormal distribution, \( P(X < 0) \) is always zero. This is because it's impossible for a log-transformed normal variable exponentiated back to real-life terms to drop below zero; in simpler terms, a lognormal variable can't be negative.
In contrast, a normal distribution allows for negative values. Even when a normal distribution and a lognormal distribution have the same mean and variance, \( P(X < 0) \) for the normal distribution won't be zero. The tails of a normal distribution stretch infinitely in both directions, which includes negative values.
Understanding these differences helps in choosing the correct statistical model for data analysis, ensuring realistic and accurate representation of data based on its nature.

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