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In the process of meiosis, a single parent diploid cell goes through eight different phases. However, only \(60 \%\) of the processes pass the first six phases and only \(40 \%\) pass all eight Assume the results from each phase are independent. (a) If the probability of a successful pass of each one of the first six phases is constant, what is the probability of a successful pass of a single one of these phases? (b) If the probability of a successful pass of each one of the last two phases is constant, what is the probability of a successful pass of a single one of these phases?

Short Answer

Expert verified
(a) Approx. 0.925; (b) Approx. 0.816.

Step by step solution

01

Understanding the Situation

In meiosis, we have a set process with eight phases. The probability of a process successfully passing the first six phases is 60% and for successfully passing all eight phases is 40%. Processes passing the phases are independent events.
02

Define Probability for First Six Phases

The probability of passing the first six phases is given by the formula: \( P_6 = (P_F)^6 \), where \( P_F \) is the probability of passing a single phase among the first six. We know \( P_6 = 0.60 \). Thus, we have the equation:\[ (P_F)^6 = 0.60 \]
03

Calculate Probability for One Phase Among First Six

Solve the equation \((P_F)^6 = 0.60\) by taking the sixth root of 0.60:\[ P_F = (0.60)^{1/6} \approx 0.925 \]Thus, the probability of successfully passing a single one of the first six phases is approximately 0.925.
04

Define Probability for Last Two Phases

Given the 40% passing probability for all eight phases, and we have already determined the probability for the first six phases. Let \( P_L \) be the probability of passing each of the last two phases. The formula is \( P_8 = (P_F)^6 \, \cdot (P_L)^2 = 0.40 \).
05

Calculate Probability for One Phase Among Last Two

We use the calculation from Step 3, which gives us \((0.925)^6 = 0.60\), and substitute into the equation from Step 4: \[ 0.60 \cdot (P_L)^2 = 0.40 \]So, solve for \( P_L \):\[ (P_L)^2 = \frac{0.40}{0.60} = \frac{2}{3} \]Thus,\[ P_L = \sqrt{\frac{2}{3}} \approx 0.816 \]So, the probability of successfully passing a single one of the last two phases is approximately 0.816.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Meiosis Phases
Meiosis is a specialized form of cell division that results in four daughter cells, each with half the number of chromosomes as the parent cell. It is an essential process for sexual reproduction, ensuring genetic diversity.
There are two main stages in meiosis: Meiosis I and Meiosis II. Each of these stages is further divided into several distinct phases, making up a total of eight phases overall. Here's a brief overview:
  • Prophase I: Chromosomes condense and pair up as homologous pairs. Crossing-over occurs here, exchanging genetic material between chromatids.
  • Metaphase I: Homologous chromosome pairs line up at the cell equator.
  • Anaphase I: The paired chromosomes are pulled apart to opposite sides.
  • Telophase I and Cytokinesis: The cell divides into two cells, each with half the number of chromosomes.
  • Prophase II: Chromosomes condense again in each of the two new cells.
  • Metaphase II: Chromosomes align at the equator.
  • Anaphase II: Sister chromatids are separated and pulled to opposite sides.
  • Telophase II and Cytokinesis: Finally, four haploid cells are formed.
Each of these phases is critical for ensuring that genetic material is accurately distributed to the daughter cells.
Independent Events in Probability
In probability theory, events are said to be independent if the occurrence of one event does not affect the probability of the other events. This means the outcome of one phase of meiosis does not influence the others.
When calculating probabilities for independent events, you multiply the probabilities of the individual events. For example, if there are several phases in a process like meiosis, where each phase is independent, the overall probability of successfully passing all phases is the product of the probabilities of each phase.
This principle is crucial in determining the probabilities of passing the sequences of phases in meiosis. Since each phase is an independent event, the probability of passing the entire sequence is the collective product of probabilities from each phase.
Success Probability Calculation
Calculating the probability of passing phases in meiosis requires understanding how to work with exponents and roots in probability.
For instance, if you know that the probability of passing the first six phases in meiosis is (0.60), and this probability can be expressed as the product of six identical probabilities (one for each phase), you use the formula: \( (P_F)^6 = 0.60 \). To find the probability of passing a single phase, solve this equation using the sixth root: \( P_F = (0.60)^{1/6} \), yielding approximately 0.925.
Similarly, knowing the success probability for all eight phases combined (0.40), you can apply similar analysis to find the probability of success for the last two phases. Using the relationship \( P_8 = (P_F)^6 \cdot (P_L)^2 = 0.40 \), you solve for \( P_L \) to find the probability of passing one of the last two phases.
This step-by-step breakdown of how success probabilities are structured and calculated helps to understand how each phase of meiosis contributes to the overall success of the process.

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