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A fault-tolerant system that processes transactions for a financial services firm uses three separate computers. If the operating computer fails, one of the two spares can be immediately switched online. After the second computer fails, the last computer can be immediately switched online. Assume that the probability of a failure during any transaction is \(10^{-8}\) and that the transactions can be considered to be independent events. (a) What is the mean number of transactions before all computers have failed? (b) What is the variance of the number of transactions before all computers have failed?

Short Answer

Expert verified
Mean: \(3 \times 10^8\); Variance: \(3 \times 10^{16}\).

Step by step solution

01

Understanding the Problem

The given problem involves three computers in a fault-tolerant system. We need to calculate the number of transactions before all computers fail, considering the failure probability for each transaction is \(10^{-8}\). A failure occurs when all three computers have failed.
02

Model the Failures Using Geometric Distribution

Since the transaction failures are independent, we can model the number of transactions between failures using a geometric distribution. The probability of a failure during a transaction is \(p = 10^{-8}\).
03

Calculate Mean for One Computer

For a geometric distribution, the mean number of trials until the first failure is given by \(\frac{1}{p}\). Therefore, for one computer, the mean number of transactions before failure is \(\frac{1}{10^{-8}} = 10^{8}\).
04

Use Three Independent Means for Full System Failure

Since the system uses three computers, the mean number of transactions until all three fail is the sum of the individual means due to independence: \(3 \times 10^8 = 3 \times 10^8\).
05

Calculate Mean before All Failures

Thus, the mean number of transactions before all computers have failed is \(3 \times 10^8\).
06

Calculate Variance for One Computer

For a geometric distribution, the variance of transactions before the first failure for one computer is given by \(\frac{1-p}{p^2}\). Substituting the values, we have \(\frac{1-10^{-8}}{(10^{-8})^2} \approx 10^{16}\).
07

Total Variance for Three Computers

Since the transactions leading up to each failure are independent, the variance for the full system is the sum of individual variances: \(3 \times 10^{16} = 3 \times 10^{16}\).
08

Calculate Variance before All Failures

Thus, the variance of the number of transactions before all computers have failed is \(3 \times 10^{16}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Distribution
In probability theory, a geometric distribution is a model used to describe the number of independent trials needed to achieve the first success in a series of Bernoulli trials. A Bernoulli trial is an experiment with two possible outcomes: success or failure. This type of distribution is particularly useful when repeated attempts are made under identical conditions, such as transactions in a fault-tolerant system.

Key characteristics of a geometric distribution include:
  • Each trial is independent of the others.
  • The probability of success, denoted by \( p \), is constant for all trials.
  • The trials continue until the first success is achieved.
Understanding this distribution helps model scenarios where there is a fixed probability of failure, which is particularly relevant to ensuring fault tolerance in computational systems.
Transaction Failure Probability
Transaction failure probability is the likelihood that a transaction will fail during its execution. In the context of a fault-tolerant system like the one described, this probability helps in determining the reliability of the system. With a given transaction failure probability of \(10^{-8}\), it indicates an extremely low chance of failure.

This low probability is crucial for systems handling critical operations, such as those in financial firms, where even minor failures can lead to significant disruptions. Knowing this probability allows engineers to calculate expectations about system behavior and incorporate sufficient redundancy, like additional computers, to switch over seamlessly in the event of failures.
Mean of Geometric Distribution
The mean of a geometric distribution gives us the average number of trials expected until the first success occurs. It is calculated using the formula \( \frac{1}{p} \), where \( p \) is the probability of success during each trial.

In our fault-tolerant system with a transaction failure probability \( p = 10^{-8} \), the mean number of transactions before one computer fails is calculated as:

\[ \text{Mean} = \frac{1}{10^{-8}} = 10^8 \]

For the entire system with three computers, the mean number of transactions before all fail is the sum of the means of each computer, which equals \( 3 \times 10^8 \). This provides a sense of how long, on average, the system can operate before experiencing complete failure.
Variance of Geometric Distribution
The variance of a geometric distribution provides insight into the spread or dispersion of the number of trials around the mean. For a geometric distribution, the variance is given by the formula \( \frac{1-p}{p^2} \), where \( p \) is the probability of success.

Applying this to one computer in our system, with \( p = 10^{-8} \), the variance of transactions before its failure is calculated as:

\[ \text{Variance} = \frac{1-10^{-8}}{(10^{-8})^2} \approx 10^{16} \]

For a system with three independent computers, each contributing these variances, the total variance of transactions before all computers have failed is three times that for a single computer:

\[ 3 \times 10^{16} \]

Understanding the variance helps in assessing the reliability and stability of fault-tolerant systems, providing a measure of how consistent the expected performance is over repeated instances.

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