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The number of errors in a textbook follows a Poisson distribution with a mean of 0.01 error per page. What is the probability that there are three or less errors in 100 pages?

Short Answer

Expert verified
The probability is approximately 0.9809.

Step by step solution

01

Define the Poisson distribution parameters

The Poisson distribution is characterized by a mean \( \lambda \). For this problem, the mean number of errors per page is 0.01. Since we are considering 100 pages, the mean number of errors in 100 pages is \( \lambda = 0.01 \times 100 = 1 \).
02

Identify the probability formula

The probability of observing \( k \) events in a Poisson distribution is given by the formula: \( P(X = k) = \frac{\lambda^k e^{-\lambda}}{k!} \). We need to use this formula for \( k = 0, 1, 2, \text{ and } 3 \).
03

Calculate individual probabilities

Compute the probabilities for \( k = 0, 1, 2, \text{ and } 3 \) using the formula.1. For \( k = 0 \): \[ P(X = 0) = \frac{1^0 e^{-1}}{0!} = e^{-1} \approx 0.3679 \]2. For \( k = 1 \): \[ P(X = 1) = \frac{1^1 e^{-1}}{1!} = e^{-1} \approx 0.3679 \]3. For \( k = 2 \): \[ P(X = 2) = \frac{1^2 e^{-1}}{2!} = \frac{e^{-1}}{2} \approx 0.1839 \]4. For \( k = 3 \): \[ P(X = 3) = \frac{1^3 e^{-1}}{3!} = \frac{e^{-1}}{6} \approx 0.0613 \]
04

Sum up the probabilities

Add the probabilities calculated for \( k = 0, 1, 2, \text{ and } 3 \) to find the probability of observing three or less errors.\[P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) \P(X \leq 3) \approx 0.3679 + 0.3679 + 0.1839 + 0.0613 = 0.9809\]
05

Conclusion

The probability that there are three or less errors in 100 pages is approximately 0.9809.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation in Poisson Distribution
The concept of probability calculation in a Poisson distribution is relatively straightforward. We are often interested in finding out how likely it is for a certain number of events to occur within a fixed interval or region. In the case of Poisson distribution, these events are assumed to happen independently and at a constant average rate.
Let's consider an example. Suppose you're observing the number of errors that appear in a textbook. This number can be modeled as a Poisson distribution if these errors occur independently. The mean rate, denoted as \( \lambda \), helps us understand the average frequency of errors. For instance, if the mean number of errors per page is 0.01, and we're considering 100 pages, the overall mean becomes \( \lambda = 0.01 \times 100 = 1 \).
Once \( \lambda \) is established, we can calculate the probability of observing exactly \( k \) errors using the Poisson probability formula:
  • \( P(X = k) = \frac{\lambda^k e^{-\lambda}}{k!} \)
By calculating the probabilities for each potential number of errors (e.g., 0, 1, 2, or 3 errors), we can then add these probabilities to find out the probability of observing up to \( k \) errors. This step-by-step approach helps us systematically arrive at the solution.
Finding the Mean of Poisson Distribution
In Poisson distribution, the mean is a vital component. It represents the average number of occurrences of an event in a given time frame or space. The mean, \( \lambda \), plays a crucial role in defining the Poisson distribution. It directly influences how the probabilities are calculated.
To find the mean of a Poisson distribution, you consider the rate at which the events occur and multiply it by the length of the time period or size of the space being considered. For instance, if the rate of errors in a textbook is 0.01 errors per page and you are looking at 100 pages, the mean number of errors across these pages is calculated as:
  • \( \lambda = 0.01 \times 100 = 1 \)
This mean value is central to all subsequent calculations with the Poisson formula, as it helps to determine the likelihood of different numbers of errors occurring. Understanding mean in Poisson distribution is fundamental for meaningful statistical analysis.
Understanding Statistical Probability with Poisson Distribution
Statistical probability refers to the measure of the likelihood that a given event will occur. With the Poisson distribution, statistical probability helps us predict the probability of a certain number of rare events happening over a fixed period or in a constant volume.
The beauty of Poisson distribution lies in its ability to handle occurrences that happen independently and sporadically. It's particularly useful in situations where events are infrequent and randomly spaced out, making it a powerful tool in statistical probability analyses.
When dealing with Poisson distribution, statistical probabilities are derived using well-defined formulas. By applying these formulas, we can determine the probability of specific outcomes (e.g., the number of errors in a textbook) occurring in a specific interval. For instance, to find the probability of having three or fewer errors in 100 pages, you sum the probabilities of having 0, 1, 2, and 3 errors:
  • \( P(X \leq 3) = P(X=0) + P(X=1) + P(X=2) + P(X=3) \approx 0.9809 \)
This calculation gives us a comprehensive understanding of the statistical likelihood, making Poisson an invaluable approach in probability theory.

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Most popular questions from this chapter

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