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In a manufacturing process that laminates several ceramic layers, \(1 \%\) of the assemblies are defective. Assume that the assemblies are independent. (a) What is the mean number of assemblies that need to be checked to obtain five defective assemblies? (b) What is the standard deviation of the number of assemblies that need to be checked to obtain five defective assemblies?

Short Answer

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(a) 500 assemblies (b) 222.36 assemblies

Step by step solution

01

Define the Distribution

We begin by identifying the type of statistical distribution involved. Since we are looking for a number of trials to get a fixed number of successes (defective assemblies, in this case), we use the negative binomial distribution. This distribution is suitable when we know the probability of success ( p = 0.01 ) and the number of successes required (five defective assemblies).
02

Mean of the Negative Binomial Distribution

The mean E(X) of a negative binomial distribution, with parameters r (number of successes) and p (probability of success), is calculated using the formula:\[ E(X) = \frac{r}{p} \]In this problem, we have r = 5 and p = 0.01. Thus, the mean is:\[ E(X) = \frac{5}{0.01} = 500 \]
03

Standard Deviation of the Negative Binomial Distribution

The standard deviation \sigma(X) is calculated using the formula for a negative binomial distribution:\[ \sigma(X) = \sqrt{\frac{r(1-p)}{p^2}} \]Plugging in r = 5 and p = 0.01, the calculation becomes:\[ \sigma(X) = \sqrt{\frac{5(1-0.01)}{0.01^2}} = \sqrt{\frac{5 \times 0.99}{0.0001}} \]\[ \sigma(X) = \sqrt{49500} \approx 222.36 \]
04

Conclusion

The calculations from the previous steps give us the mean and the standard deviation for the problem. Ensure the interpretations align with the expectations of a negative binomial distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Distributions
Statistical distributions are mathematical functions that describe the probabilities of different outcomes in a random variable. One common type is the Negative Binomial Distribution, which is especially used when we want to find out how many trials are needed to get a certain number of successes. In the context of the exercise given, a 'success' is actually a defective assembly. This may seem counterintuitive, but in statistics, success can simply mean the event we are interested in measuring.
The negative binomial distribution is used when the outcomes are binary, meaning each trial can either be a success or failure. Additionally, it requires you to know the probability of success for each trial (in our case, the assembly being defective). By using these parameters, this distribution helps to model scenarios where variability and independence of outcomes play a significant role.
Remember, choosing the right statistical distribution forms the foundation of correct problem-solving in statistics, as it directs you to the most appropriate formulas for calculation.
Probability of Success
The probability of success is a crucial element in statistical problems, especially when dealing with the negative binomial distribution. In our manufacturing process context, this probability is determined by the defect rate of the assemblies. Here, success refers to obtaining a defective assembly, with a probability of success, p, equal to 0.01, or 1%.
When tackling problems involving statistical distributions, clarifying what constitutes a 'success' in your specific scenario is vital. It aligns the distribution parameters accurately with the real-world problem.
  • Success in this context means finding a defective assembly, opposite to what success typically implies.
  • Understanding and correctly identifying the probability of success impacts the accuracy of your mean and standard deviation calculations.
Standard Deviation Calculation
The standard deviation is a measure of how spread out the trials are around the mean. For the negative binomial distribution, it quantifies variability when asking how many trials it takes to reach a set count of successes (defective assemblies).
To calculate the standard deviation in this context, use the formula: \[ \sigma(X) = \sqrt{\frac{r(1-p)}{p^2}} \] where \( r \) is the number of successes and \( p \) is the probability of success.
In our scenario, substituting the values \( r = 5 \) and \( p = 0.01 \) leads us to \[ \sigma(X) = \sqrt{\frac{5(1-0.01)}{0.01^2}} = \sqrt{49500} \approx 222.36 \].
Understanding standard deviation is crucial because it provides insight into the reliability and predictability of your mean. A higher standard deviation implies a greater spread of possible values, indicating less predictability of the number of trials needed.
Mean Calculation
Calculating the mean in the context of a negative binomial distribution tells us the average number of trials needed to achieve a certain number of successes. This is critical for planning and expectations in processes like manufacturing.
The formula to determine the mean for this distribution is: \[ E(X) = \frac{r}{p} \] where \( r \) stands for the desired number of successes and \( p \) represents the probability of achieving one success in any single trial.
In our example, with \( r = 5 \) defective assemblies and \( p = 0.01 \), the calculation becomes: \[ E(X) = \frac{5}{0.01} = 500 \].
This result means, on average, you need to check 500 assemblies to find five defects. It's a powerful way to manage expectations and optimize processes by providing a realistic expectation of outcomes.

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