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Let \(X\) denote the number of bits received in error in a digital communication channel, and assume that \(X\) is a binomial random variable with \(p=0.001\). If 1000 bits are transmitted, determine the following: (a) \(P(X=1)\) (b) \(P(X \geq 1)\) (c) \(P(X \leq 2)\) (d) mean and variance of \(X\)

Short Answer

Expert verified
(a) Use binomial formula for \(P(X=1)\). (b) Approximately 0.632 using Poisson. (c) Sum binomial probabilities \(P(X=0,1,2)\). (d) Mean is 1, variance is 0.999.

Step by step solution

01

Determine Parameters

The binomial distribution is defined by two parameters, \(n\) and \(p\). Here, \(n = 1000\) bits are transmitted and the probability of one bit being received in error is \(p = 0.001\).
02

Calculate Probability for One Error

The probability of receiving exactly one bit in error is given by the formula for a binomial probability: \[ P(X=1) = \binom{1000}{1} (0.001)^1 (0.999)^{999} \] Calculate this using a calculator.
03

Approximate with Poisson for P(X ≥ 1)

For the probability that at least one error occurs, use the approximation that for small \(p\) and large \(n\), a binomial distribution can be approximated using a Poisson distribution.\[ P(X \geq 1) = 1 - P(X=0) \] \[ \lambda = np = 1000 \times 0.001 = 1 \] Thus, \[ P(X=0) = e^{-1} \cdot \frac{1^0}{0!} = e^{-1} \] So \[ P(X \geq 1) = 1 - e^{-1} \]
04

Calculate P(X ≤ 2)

To find \( P(X \leq 2) \), calculate: \[ P(X=0) + P(X=1) + P(X=2) \] Use the binomial formula for all needed values and sum them: \[ P(X=0) = \binom{1000}{0} (0.001)^0 (0.999)^{1000} \] \[ P(X=1) = \binom{1000}{1} (0.001)^1 (0.999)^{999} \] \[ P(X=2) = \binom{1000}{2} (0.001)^2 (0.999)^{998} \] Add these probabilities together.
05

Determine Mean and Variance

For a binomial distribution, the mean \( \mu \) and variance \( \sigma^2 \) are calculated as follows: \[ \text{Mean: } \mu = np = 1000 \times 0.001 = 1 \] \[ \text{Variance: } \sigma^2 = np(1-p) = 1000 \times 0.001 \times 0.999 = 0.999 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Digital Communication
Digital communication involves the transmission of digital data between devices like computers. In our context, we are examining how digital communication channels handle errors. When we send a batch of bits across a channel, sometimes errors occur.
These errors might be due to noise or other interferences. When studying digital communication, it's vital to understand how often these errors happen and the likelihood of different error scenarios. With 1000 bits being transmitted, the task is to calculate the probability of errors occurring in this batch. We use probability models, such as the Binomial Distribution, to predict these error rates. This helps improve and assess the reliability of digital systems.
Probability Calculation
Calculating probabilities in digital communication involves determining the likelihood of different events, such as errors occurring. For our example, we focus on events like receiving exactly one error, none, or at least one error in 1000 transmitted bits.
  • The probability for exactly one error is computed using the binomial distribution: \[ P(X=1) = \binom{1000}{1} \times (0.001)^1 \times (0.999)^{999} \]
  • For at least one error, we consider the complementary event of having no errors: \[ P(X \geq 1) = 1 - P(X=0) \]
  • The probability of fewer or equal to two errors involves summing individual probabilities: \[ P(X \leq 2) = P(X=0) + P(X=1) + P(X=2) \]
These calculations allow engineers to design better error-detecting and correcting protocols, ensuring data integrity in digital communication.
Poisson Approximation
The Poisson Approximation is a useful technique when dealing with a large number of trials and a small probability of success in each.
It simplifies complex Binomial calculations using a simpler Poisson model.In our exercise, when determining the probability that at least one error occurs in transmitting 1000 bits, we can use the Poisson approximation. This is because the error probability, \(p = 0.001\), is very small, and the number of trials, \(n = 1000\), is large. This model reduces the computational complexity by allowing us to use the mean, \(\lambda = np = 1\), directly in calculations:\[ P(X=0) = e^{-1} \times \frac{1^0}{0!} = e^{-1} \]With this approximation:\[ P(X \geq 1) = 1 - P(X=0) \]This process showcases how approximations can offer practical solutions without significantly compromising accuracy.
Mean and Variance
Understanding the mean and variance of a distribution is crucial for assessing its behavior.
  • Mean: The mean provides the expected number of errors in our transmitted bits. For a binomial distribution, the mean \(\mu\) is the product of the number of trials \(n\) and the probability of error \(p\): \[ \mu = np = 1000 \times 0.001 = 1 \]
  • Variance: The variance \(\sigma^2\) measures the variability or spread of our data. For a binomial distribution, it is calculated as: \[ \sigma^2 = np(1-p) = 1000 \times 0.001 \times 0.999 = 0.999 \]
The mean tells us about the average behavior, while the variance indicates how much deviation we might expect from this average in digital communication errors.

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Most popular questions from this chapter

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