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If \(n(A)=16, n(B)=16, n(C)=14, n(A \cap B)=6\), \(n(A \cap C)=5, n(B \cap C)=6\), and \(n(A \cup B \cup C)=31\), find \(n(A \cap B \cap C) .\)

Short Answer

Expert verified
The value of \(n(A \cap B \cap C)\) is 8.

Step by step solution

01

Write down the given information and the PIE formula

We are given that \(n(A)=16, n(B)=16, n(C)=14, n(A \cap B)=6\), \(n(A \cap C)=5, n(B \cap C)=6\), and \(n(A \cup B \cup C)=31\). We want to find \(n(A \cap B \cap C)\). We will use the Principle of Inclusion and Exclusion (PIE) formula: $$n(A \cup B \cup C) = n(A) + n(B) + n(C) - n(A \cap B) - n(A \cap C) - n(B \cap C) + n(A \cap B \cap C)$$
02

Plug in the given values into the PIE formula

Now let's plug in the given values into the formula: $$31 = 16 + 16 + 14 - 6 - 5 - 6 + n(A \cap B \cap C)$$
03

Simplify the equation and solve for \(n(A \cap B \cap C)\)

Let's simplify the equation and solve for \(n(A \cap B \cap C)\): $$31 = 40 - 17 + n(A \cap B \cap C)$$ $$n(A \cap B \cap C) = 31 - 23 = 8$$ The value of the intersection of all the given sets, \(n(A \cap B \cap C)\), is 8.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Set Theory
Set theory is a fundamental area of mathematics that deals with collections of objects, known as sets. A set can be anything: numbers, letters, shapes, or even other sets. The language of set theory is used to describe how these sets relate to each other.

For example, the sets in our exercise refer to collections of elements, where 'A', 'B', and 'C' can be thought of as different groups with varying number of members. In mathematical terms, the number of elements in a set is referred to as the cardinality of the set, and is denoted as 'n(A)' for set 'A'. Understanding set theory is crucial when trying to figure out relationships like unions and intersections that are part of this exercise.

Sets can be related in different ways and set theory gives us the tools—such as union, intersection, and set difference—to analyze these relationships. By grasping the concepts of set theory, we can better understand complex relations and solve problems that involve multiple sets, just like in the textbook exercise we are examining.
Intersection of Sets
The intersection of two or more sets is a new set containing all the elements that are common to all the original sets. In notation, we use the symbol \( \cap \) to denote the intersection. So the intersection of sets 'A' and 'B' is written as \( A \cap B \).

In our exercise, for instance, \( n(A \cap B) \) equals 6, which means there are 6 elements that both set 'A' and set 'B' have in common. Understanding this concept is vital as it allows us to identify shared elements between groups and often plays a key role when we want to determine the total number of distinct elements in a collection of sets.
Union of Sets
While intersections deal with commonalities, the union of sets is all about inclusivity. The union of two or more sets includes every element that is in either set, without duplication. The union is denoted by the symbol \( \cup \).

For example, the union of sets 'A', 'B', and 'C' is symbolized as \( A \cup B \cup C \). In our exercise, \( n(A \cup B \cup C) = 31 \) tells us there are 31 unique elements collectively in sets 'A', 'B', and 'C'. To accurately calculate the cardinality of a union of sets, we need to apply the Principle of Inclusion and Exclusion, ensuring that we count each element exactly once even if it appears in more than one set.
Cardinality of Sets
The cardinality of a set is the term used to describe the number of elements it contains. It is essentially a measure of a set's size. For any set 'X', its cardinality is denoted by \( n(X) \).

The exercise provides the cardinality for sets 'A', 'B', and 'C', as well as for their intersections. When we use the Principle of Inclusion and Exclusion, we effectively adjust for overcounting or undercounting caused by multiple counting of elements that are present in more than one set. By calculating the cardinality of various unions and intersections, we can piece together the cardinality of a more complex set, like \( n(A \cap B \cap C) \), which represents elements common to 'A', 'B', and 'C'.

Understanding cardinality is crucial for answering many real-world problems that pertain to quantity and organization, making it one of the pivotal aspects of set theory.

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Most popular questions from this chapter

In an online survey for Talbots of 1095 women ages \(35 \mathrm{yr}\) and older, the participants were asked what article of clothing women most want to fit perfectly. A summary of the results of the survey follows: $$ \begin{array}{lc} \hline \text { Article of Clothing } & \text { Respondents } \\ \hline \text { Jeans } & 470 \\ \hline \text { Black Pantsuit } & 307 \\ \hline \text { Cocktail Dress } & 230 \\ \hline \text { White Shirt } & 22 \\ \hline \text { Gown } & 11 \\ \hline \text { Other } & 55 \\ \hline \end{array} $$ If a woman who participated in the survey is chosen at random, what is the probability that she most wants a. Jeans to fit perfectly? b. A black pantsuit or a cocktail dress to fit perfectly?

List the simple events associated with each experiment. In a survey conducted to determine whether movie attendance is increasing \((i)\), decreasing \((d)\), or holding steady \((s)\) among various sectors of the population, participants are classified as follows: Group 1: Those aged 10-19 Group 2: Those aged 20-29 Group 3: Those aged 30-39 Group 4: Those aged 40-49 Group 5: Those aged 50 and older The response and age group of each participant are recorded.

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. The numbers 1,2, and 3 are written separately on three pieces of paper. These slips of paper are then placed in a bowl. If you draw two slips from the bowl, one at a time and without replacement, then the sample space for this experiment consists of six elements.

The percentage of the general population that has each blood type is shown in the following table. Determine the probability distribution associated with these data. $$ \begin{array}{lcccc} \hline \text { Blood Type } & \text { A } & \text { B } & \text { AB } & \text { O } \\ \hline \text { Population, \% } & 41 & 12 & 3 & 44 \\ \hline \end{array} $$

In a survey of 106 senior information technology and data security professionals at major U.S. companies regarding their confidence that they had detected all significant security breaches in the past year, the following responses were obtained. $$ \begin{array}{lcccc} \hline & \begin{array}{c} \text { Very } \\ \text { Answer } \end{array} & \begin{array}{c} \text { Moderately } \\ \text { confident } \end{array} & \begin{array}{c} \text { Not very } \\ \text { confident } \end{array} & \begin{array}{c} \text { Not at all } \\ \text { confident } \end{array} & \text { confident } \\ \hline \text { Respondents } & 21 & 56 & 22 & 7 \\ \hline \end{array} $$ What is the probability that a respondent in the survey selected at random a. Had little or no confidence that he or she had detected all significant security breaches in the past year? b. Was very confident that he or she had detected all significant security breaches in the past year?

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