Chapter 2: Problem 35
Find an equation of the line that satisfies the given conditions. Through \((-1,-2) :\) perpendicular to the line \(2 x+5 y+8=0\)
Short Answer
Expert verified
The equation of the line is \(5x - 2y = 8\).
Step by step solution
01
Identify the Slope of the Given Line
The equation of the given line is \(2x + 5y + 8 = 0\). We will express it in the slope-intercept form \(y = mx + c\) to find its slope. Rearrange the equation:\[5y = -2x - 8\] \[y = -\frac{2}{5}x - \frac{8}{5}\]The slope \(m\) of this line is \(-\frac{2}{5}\).
02
Determine the Slope of the Perpendicular Line
Lines that are perpendicular to each other have slopes that are negative reciprocals. Given the slope of the original line is \(-\frac{2}{5}\), the slope \(m_p\) of the perpendicular line is the negative reciprocal:\[m_p = \frac{5}{2}\]
03
Use Point-Slope Formula for the Equation
To find the equation of the line that is perpendicular and passes through the point \((-1, -2)\), we use the point-slope form:\[y - y_1 = m(x - x_1)\]where \((x_1, y_1)\) is the point \((-1, -2)\) and \(m = \frac{5}{2}\).
04
Substitute the Values into the Equation
Substitute the point \((-1, -2)\) and slope \(\frac{5}{2}\) into the point-slope form:\[y - (-2) = \frac{5}{2}(x - (-1))\]Simplify the equation:\[y + 2 = \frac{5}{2}(x + 1)\]
05
Rearrange into Slope-Intercept or Standard Form
To express the equation, distribute and simplify:\[y + 2 = \frac{5}{2}x + \frac{5}{2}\]Subtract 2 from both sides:\[y = \frac{5}{2}x + \frac{5}{2} - 2\]Simplify further:\[y = \frac{5}{2}x - \frac{4}{0}\]Now, for a standard form, multiply through by 2 to remove fractions:\[2y = 5x - 8\]and rearrange:\[5x - 2y = 8\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form is a straightforward way to express the equation of a line. It is given by the formula \( y = mx + c \), where \( m \) is the slope of the line, and \( c \) is the y-intercept where the line crosses the y-axis.
This form is particularly useful because it immediately tells us two important things about the line:
This form is particularly useful because it immediately tells us two important things about the line:
- The slope \( m \) indicates how steep the line is. If \( m \) is positive, the line rises as it moves from left to right; if negative, it falls.
- The y-intercept \( c \) shows the point where the line intersects the y-axis.
Point-Slope Form
When you need the equation of a line and you know a point on the line and the slope, then the point-slope form is your go-to format. This form is written as \( y - y_1 = m(x - x_1) \). Here, \((x_1, y_1)\) is the point through which the line passes, and \( m \) is the slope. This is particularly helpful when you have the specific coordinates of the point.
- Perfect for deriving an equation when details of any single point and the slope are known.
- It easily converts into slope-intercept form by rearranging the equation.
Negative Reciprocal
To find the slope of a line perpendicular to another, you need to use the concept of a negative reciprocal. Two lines are perpendicular if the product of their slopes is \(-1\). This means if the slope of the original line is \( m \), a perpendicular line's slope will be \(-1/m\).
This technique is crucial when finding equations of perpendicular lines because:
This technique is crucial when finding equations of perpendicular lines because:
- It offers a simple mathematical method for finding the new slope needed for perpendicularity.
- For instance, if a line has a slope of \(-\frac{2}{5}\), the perpendicular slope will be \( \frac{5}{2} \).