/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 \(59-66\) . Find the solutions o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(59-66\) . Find the solutions of the inequality by drawing appropriate graphs. State each answer rounded to two decimals. $$ \sqrt{0.5 x^{2}+1} \leq 2|x| $$

Short Answer

Expert verified
Solution: \( -1.56 \leq x \leq 1.56 \).

Step by step solution

01

Analyze the Given Inequality

We are given the inequality \( \sqrt{0.5x^2 + 1} \leq 2|x| \). Our goal is to solve this inequality and find the range of \( x \) values that satisfy it.
02

Consider Cases for \( |x| \)

Since the inequality involves \( |x| \), we need to consider two cases:1. \( x \geq 0 \), where \( |x| = x \)2. \( x < 0 \), where \( |x| = -x \)We'll solve the inequality for each case separately.
03

Solve Case 1 (\( x \geq 0 \))

For \( x \geq 0 \), the inequality becomes \( \sqrt{0.5x^2 + 1} \leq 2x \). Squaring both sides gives:\[ 0.5x^2 + 1 \leq 4x^2 \]Rearrange to solve:\[ 0 \leq 3.5x^2 - 4x + 1 \]This is a quadratic inequality. Let's analyze its roots by solving \( 3.5x^2 - 4x + 1 = 0 \).
04

Find Roots of Quadratic Equation

Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) with \( a = 3.5 \), \( b = -4 \), and \( c = 1 \).\[ x = \frac{4 \pm \sqrt{(-4)^2 - 4 \cdot 3.5 \cdot 1}}{2 \cdot 3.5} \]Simplifies to:\[ x = \frac{4 \pm \sqrt{16 - 14}}{7} \]\[ x = \frac{4 \pm \sqrt{2}}{7} \]The roots are \( x_1 = \frac{4 + \sqrt{2}}{7} \) and \( x_2 = \frac{4 - \sqrt{2}}{7} \).
05

Determine Intervals for Case 1

The results divide the number line into intervals: \( x < \frac{4 - \sqrt{2}}{7} \), \( \frac{4 - \sqrt{2}}{7} \leq x \leq \frac{4 + \sqrt{2}}{7} \), and \( x > \frac{4 + \sqrt{2}}{7} \).Check each interval within the original inequality to determine the solution set.
06

Solve Case 2 (\( x < 0 \))

For \( x < 0 \), the inequality becomes \( \sqrt{0.5x^2 + 1} \leq -2x \). Squaring both sides gives:\[ 0.5x^2 + 1 \leq 4x^2 \]Rearrange similar to Case 1:\[ 0 \leq 3.5x^2 + 4x + 1 \]Solve the quadratic equation \( 3.5x^2 + 4x + 1 = 0 \) using the quadratic formula.
07

Find Roots for Case 2

Use \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) with \( a = 3.5 \), \( b = 4 \), \( c = 1 \):\[ x = \frac{-4 \pm \sqrt{4^2 - 4 \cdot 3.5 \cdot 1}}{2 \cdot 3.5} \]Simplifies to:\[ x = \frac{-4 \pm \sqrt{2}}{7} \]Roots are \( x_1 = \frac{-4 + \sqrt{2}}{7} \) and \( x_2 = \frac{-4 - \sqrt{2}}{7} \).
08

Determine Intervals for Case 2

The intervals are \( x < \frac{-4 - \sqrt{2}}{7} \), \( \frac{-4 - \sqrt{2}}{7} < x < \frac{-4 + \sqrt{2}}{7} \), and \( x > \frac{-4 + \sqrt{2}}{7} \). Check these intervals.
09

Combine Solutions from Both Cases

Combine the ranges obtained from both cases to get the solution set for the inequality. For numeric results, calculate approximate decimal values of the roots and combine satisfied intervals.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Inequalities
Quadratic inequalities are mathematical expressions that involve a quadratic polynomial and inequality signs such as <, >, ≤, or ≥. These inequalities typically look like the expression \[ax^2 + bx + c \leq 0\] and require careful analysis to solve. Instead of equalities, where the goal is to find specific values of \(x\) that satisfy the expression, inequalities involve finding a range of values. Quadratic inequalities often appear in real-life scenariors like finding safe speed limits or determining maximum heights in engineering projects.

When approaching quadratic inequalities, one common method involves solving the associated quadratic equation \(ax^2 + bx + c = 0\) to find its roots. These roots help divide the number line into different intervals. The next step is to choose test points from these intervals and substitute them back into the original inequality. This process determines which intervals satisfy the inequality, allowing us to represent the set of solutions clearly.

In some cases, the inequality might need to be rearranged to facilitate this process. Additionally, when dealing with squares, it's important to remember they can complicate both positive and negative values. Evaluating the inequality across all possible values ensures a comprehensive solution.
Absolute Value in Inequalities
Absolute value refers to the distance of a number from zero on a number line, irrespective of its direction. In other words, the absolute value of a number \( x \) is \(|x|\), which is always positive. When inequalities involve absolute values, they often contain expressions like \(|x| < a\) or \(|x| > a\). These expressions indicate that \( x \) is within a certain range from zero, whether closer or further.

For the inequality \(|x| < a\), the values of \(x\) must lie between \(-a\) and \(a\); so \(-a < x < a\). Conversely, \(|x| > a\) means \(x\) lies outside this interval (either less than \(-a\) or greater than \(a\)): \(x < -a\) or \(x > a\). Handling inequalities with absolute values requires considering each case separately because an absolute value represents two possible conditions.

In solving inequalities like \( \sqrt{0.5x^2 + 1} \leq 2|x| \), it's crucial to break down the inequality into distinct cases based on the behavior of \(|x|\) according to whether \(x\) is positive or negative. This allows the inequality to be rewritten without the absolute value term, simplifying the process of finding the solution.
Graphical Solutions
Graphical solutions are a powerful visual tool to understand and solve inequalities. They offer a way to visualize the solution set, giving an intuitive grasp of where the inequality holds true. The primary idea is to graph the functions involved in the inequality separately on the same coordinate plane. For example, in the inequality \( \sqrt{0.5x^2 + 1} \leq 2|x| \), you can graph \( y = \sqrt{0.5x^2 + 1} \) and \( y = 2|x| \).

Once both graphs are plotted, analysing their intersection points becomes crucial since these typically indicate boundary points for solutions. The areas where one graph lies entirely above or below the other on the y-axis tells us which values of \(x\) satisfy the inequality.
  • Intersections: Points where both graphs meet, these are important for establishing intervals of interest.
  • Above/below analysis: Helps in deciding which side of the inequality holds across intervals.
Graphical methods complement algebraic approaches by confirming solutions visually and making complex inequalities more understandable. They also serve as an effective validation tool to check the accuracy of algebraically derived solutions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Global Warming Some scientists believe that the average surface temperature of the world has been rising steadily. The average surface temperature can be modeled by $$ T=0.02 t+15.0 $$ where \(T\) is temperature in \(^{\circ} \mathrm{C}\) and \(t\) is years since \(1950 .\) (a) What do the slope and \(T\) -intercept represent? (b) Use the equation to predict the average global surface temperature in 2050 .

Crickets and Temperature Biologists have observed that the chirping rate of crickets of a certain species is related to temperature, and the relationship appears to be very nearly linear. A cricket produces 120 chirps per minute at \(70^{\circ} \mathrm{F}\) and 168 chirps per minute at \(80^{\circ} \mathrm{F} .\) (a) Find the linear equation that relates the temperature \(t\) and the number of chirps per minute \(n\) . (b) If the crickets are chirping at 150 chirps per minute, estimate the temperature.

\(55-58\) m Find all real solutions of the equation, rounded to two decimals. $$ x^{4}-8 x^{2}+2=0 $$

\(59-66\) . Find the solutions of the inequality by drawing appropriate graphs. State each answer rounded to two decimals. $$ x^{2} \leq 3 x+10 $$

Manufacturing Cost The manager of a furniture factory finds that it costs \(\$ 2200\) to manufacture 100 chairs in one day and \(\$ 4800\) to produce 300 chairs in one day. (a) Assuming that the relationship between cost and the number of chairs produced is linear, find an equation that expresses this relationship. Then graph the equation. (b) What is the slope of the line in part (a), and what does it represent? (c) What is the \(y\) -intercept of this line, and what does it represent?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.