Chapter 1: Problem 7
Man zeige, dass die Teilmenge \(\mathbb{Z}+\mathbb{Z} \mathrm{i}=\\{a+b \mathrm{i} \mid a, b \in \mathbb{Z}\\}\) von \(\mathbb{C}\), versehen mit der gewöhnlichen Multiplikation komplexer Zahlen, eine abelsche Halbgruppe mit neutralem Element ist. Ermitteln Sie die Einheiten von \(\mathbb{Z}+\mathbb{Z}\) i.
Short Answer
Step by step solution
Definition of Subset
Check for Abelian Property
Check for Associativity
Identify the Identity Element
Find Units in the Group
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
In the context of the exercise, the subset \(\mathbb{Z} + \mathbb{Z}i\) refers specifically to complex numbers with integer components. This means both the real part \(a\) and the imaginary part \(b\) are integers. Complex numbers with such integer components form a unique and interesting subset of the complex plane.
It's important to note that complex numbers follow specific arithmetic rules, such as commutativity and associativity. This exercise explores such properties in terms of multiplication, which is determined by the formula:
- \((a + bi) \times (c + di) = (ac - bd) + (ad + bc)i\)
Integer Components
In the domain of complex numbers, having integer components allows for certain algebraic properties to manifest meaningfully. For example, when multiplying numbers in the set \(\mathbb{Z} + \mathbb{Z}i\), any resulting number also naturally has integer components. This adherence to integer values is significant because:
- It ensures the closure property under multiplication, essential for the structure to be considered a semigroup.
- It ensures that operations respect the discrete nature of this subset.
- It preserves integer property across multiplication given the additive form \((a+b)\) and solutions such as \((ac-bd)\) remain within integer form.
Multiplicative Identity
In the subset \(\mathbb{Z} + \mathbb{Z}i\), the multiplicative identity plays the same fundamental role as within the larger set of complex numbers. For any complex number \(z = a + bi\), multiplying it by \(1 + 0i\) results in:
- \(z \times (1 + 0i) = a + bi\)
- This verifies that \(1 + 0i\) functions as the identity.
Invertible Elements
In the subset \(\mathbb{Z} + \mathbb{Z}i\), finding invertible elements is akin to finding numbers where both the real and imaginary parts of its inverse are integers. Solving \((a + bi) \times (c + di) = 1\) in this subset leads to the conclusion that:
- The numbers are \(\pm 1\) and \(\pm i\).
- These are the only elements whose inverses also belong to \(\mathbb{Z} + \mathbb{Z}i\).