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91Ó°ÊÓ

Solve each system of equations.

2a+b=25a=15a+b+c=−1

Short Answer

Expert verified

The solution of the system of equations: 2a+b=25a=15a+b+c=−1 is3,−4,0.

Step by step solution

01

- Solve for variables a

Let the equations be:

2a+b=2 … (i)

5a=15 … (ii)

a+b+c=-1 … (iii)

Solve equation (ii) so as to obtain variable a.

5a5=155a=3

02

- Solve for variable b

Substitute 3 for a into equation (i) so as to obtain the value of b.

23+b=26+b−6=2−6b=−4

03

- Solve for variable c

Now substitute 3 for a and -4 for b into the equation (iii) so as to obtain variable c.

3+−4+c=−13−4+c=−1−1+c+1=−1+1c=0

Therefore, the solution is 3,−4,0.

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