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Chapter 4: Q50. (page 174)

Solve each equation.50

[3x+215]=[23鈭�4y鈭�1]

Short Answer

Expert verified

The answer is (7,鈭�4) that isx=7 and y=鈭�4.

Step by step solution

01

- State the definition of a matrix.

A rectangular array of numbers arranged in rows and columns is called a matrix.

02

- Solve the equation.

Using the definition of equal matices is used to solve the equation.

If the dimension of the matrices are same and corresponding elements are equal then the matrices are equal.

Here the matrices are:

[3x+215]=[23鈭�4y鈭�1]

Since, the matrices are equal then corresponding elements are also equal.

Then, the two linear equations formed are:

3x+2=23鈭�4y鈭�1=15

Solve the equations to obtain values of x and y .

3x+2=233x+2鈭�2=23鈭�23x=21x=7

and鈭�4y鈭�1=15鈭�4y鈭�1+1=15+1鈭�4y=16y=鈭�4

03

- State the conclusion.

Therefore, x=7 and y=鈭�4. The solution is (7,鈭�4)

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Most popular questions from this chapter

For exercises 26 and 27, use the advertisement shown at the right.

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32. Find the difference in cookie sales from Friday to Saturday expressed as a matrix.
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