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Chapter 4: Q17. (page 157)

Solve each equation.
$[\begin{matrix} 4 x & 3 y \end{matrix}] = [\begin{matrix} 12 & - 1 \end{matrix}]$

Short Answer

Expert verified

The solution is $(3, - \frac{1}{3})$ .

Step by step solution

01

– Description of step.

As the matrices are equal, the corresponding elements are equal. Write the three linear equations to show this equality.

$\begin{matrix} 4 x = 12 \\ 3 y = 鈭� 1 \end{matrix}$

02

– Description of step.

Divide each side of $4 x = 12$ by 4 to find the value of x.

$\begin{matrix} \frac{4 x}{4} = \frac{12}{4} \\ x = 3 \end{matrix}$

03

– Description of step.

Divide each side of $3 y = 鈭� 1$ by 3 to find the value of y.

$\begin{matrix} \frac{3 y}{3} = \frac{鈭� 1}{3} \\ y = \frac{鈭� 1}{3} \end{matrix}$

Therefore, the solution is $(3, 鈭� \frac{1}{3})$ .

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Most popular questions from this chapter

Use matrices $A$ , $B$ , $C$ and $D$ to find the following.

$A = [\begin{matrix} 5 & 7 \\ 鈭� 1 & 6 \\ 3 & 鈭� 9 \end{matrix}], 鈥夆赌� B = [\begin{matrix} 8 & 3 \\ 5 & 1 \\ 4 & 4 \end{matrix}], 鈥夆赌� C = [\begin{matrix} 0 & 4 \\ 鈭� 2 & 5 \\ 7 & 鈭� 1 \end{matrix}], 鈥夆赌� D = [\begin{matrix} 6 & 2 \\ 9 & 0 \\ 鈭� 3 & 0 \end{matrix}]$

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