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Write the null and alternative hypotheses in words and then symbols for each of the following situations. (a) A tutoring company would like to understand if most students tend to improve their grades (or not) after they use their services. They sample 200 of the students who used their service in the past year and ask them if their grades have improved or declined from the previous year. (b) Employers at a firm are worried about the effect of March Madness, a basketball championship held each spring in the US, on employee productivity. They estimate that on a regular business day employees spend on average 15 minutes of company time checking personal email, making personal phone calls, etc. They also collect data on how much company time employees spend on such non-business activities during March Madness. They want to determine if these data provide convincing evidence that employee productivity changed during March Madness.

Short Answer

Expert verified
(a) \(H_0: \text{Proportion improved} \leq 0.5\), \(H_a: \text{Proportion improved} > 0.5\). (b) \(H_0: \mu = 15\), \(H_a: \mu \neq 15\).

Step by step solution

01

Understanding the situation for Part (a)

In this situation, we want to determine whether the grades of students tend to improve after using the tutoring company's services. This involves comparing grades from before and after using the services to see if there is a statistical improvement.
02

Formulating the null and alternative hypotheses for Part (a)

The null hypothesis (\(H_0\) ) is that there is no improvement in grades after using the tutoring company's services. In words, most students do not tend to improve their grades. The alternative hypothesis (\(H_a\) ) is that there is an improvement in grades after using the services. Formally, we write: \[ H_0: \text{The proportion of students whose grades improved} \leq 0.5 \] \[ H_a: \text{The proportion of students whose grades improved} > 0.5 \]
03

Understanding the situation for Part (b)

Here, employers are concerned that employee productivity may differ during March Madness compared to a regular business day. Specifically, they want to know if the time employees spend on non-business activities changes during this period.
04

Formulating the null and alternative hypotheses for Part (b)

For this scenario, the null hypothesis (\(H_0\) ) is that employee productivity does not change during March Madness, meaning the average time spent on non-business activities remains 15 minutes. The alternative hypothesis (\(H_a\) ) is that employee productivity changes. Formally, we write: \[ H_0: \mu = 15 \text{ minutes (no change)} \] \[ H_a: \mu eq 15 \text{ minutes (change)} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis is a crucial starting point. It is essentially a statement that there is no effect or no difference, providing a baseline to compare against an alternative. In the case of the tutoring company example, the null hypothesis, denoted by \( H_0 \), suggests that there is no improvement in student grades after utilizing the company's services. This means, in symbolic terms, that the proportion of students whose grades improved is less than or equal to 0.5 (50%).
For the March Madness scenario, the null hypothesis posits that there is no change in employee productivity during the basketball championship. It states, symbolically, that the average time employees spend on non-business activities remains unchanged at 15 minutes during this period.
  • The null hypothesis serves as a baseline or default assumption.
  • It allows statisticians to measure evidence against it with collected data.
  • If evidence is significant enough, the null hypothesis may be rejected.
Alternative Hypothesis
While the null hypothesis often suggests a status quo, the alternative hypothesis presents what you seek to prove with your data. It asserts a change or effect, which is the opposite of what the null suggests. In our tutoring company example, the alternative hypothesis \( H_a \) asserts that most students' grades improve after using the service. In symbolic terms, this is more than 50% of students showing improvement.
On the other hand, in the case of March Madness affecting employee productivity, the alternative hypothesis proposes that there is indeed a change in non-business activity times. This means, symbolically, the average time spent during March Madness is not equal to 15 minutes.
  • The alternative hypothesis is what researchers aim to support.
  • It is only considered if sufficient evidence counters the null hypothesis.
  • Denoted by \( H_a \), it usually represents the researchers' true belief or claim.
Statistical Significance
The concept of statistical significance is essential when interpreting the results of a hypothesis test. It helps determine whether the observed effect in your study is likely due to chance or a true underlying effect. A result is deemed statistically significant if the p-value is less than a pre-defined significance level, typically set at 0.05. This means there is a less than 5% probability that the observed difference or effect happened by chance.
For the tutoring scenario, statistical significance would mean that the improvement in grades is not just random variation but likely influenced by the tutoring service. For the March Madness case, statistical significance would suggest that any change in productivity could be related to the event rather than random day-to-day fluctuations.
  • Statistical significance helps validate research hypotheses.
  • A smaller p-value indicates stronger evidence against the null hypothesis.
  • While significant results suggest a real effect, they do not guarantee practical importance.
Proportion Hypothesis Test
A proportion hypothesis test is a specific type of statistical test used to determine if the proportion of a certain outcome is significantly different from a claimed proportion. This test is especially suitable for situations where data involves proportions or percentages.
In the tutoring company example, researchers use a proportion test to find out whether more than half of the students improved their grades. This involves comparing the observed proportion of grade improvements to the hypothesized proportion set under the null hypothesis.
  • It involves setting a null and an alternative hypothesis about a proportion.
  • Sample data is used to calculate the test statistic and p-value.
  • Results tell whether the observed proportions deviate significantly from expectations.

Understanding proportion hypothesis testing helps to interpret whether observed changes in categorical data are meaningful or not. This concept is widely utilized across fields like medicine, marketing, and social sciences.

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Most popular questions from this chapter

Teens were surveyed about cyberbullying, and \(54 \%\) to \(64 \%\) reported experiencing cyberbullying (95\% confidence interval). \(^{20}\) Answer the following questions based on this interval. (a) A newspaper claims that a majority of teens have experienced cyberbullying. Is this claim supported by the confidence interval? Explain your reasoning. (b) A researcher conjectured that \(70 \%\) of teens have experienced cyberbullying. Is this claim supported by the confidence interval? Explain your reasoning. (c) Without actually calculating the interval, determine if the claim of the researcher from part (b) would be supported based on a \(90 \%\) confidence interval?

A hospital administrator hoping to improve wait times decides to estimate the average emergency room waiting time at her hospital. She collects a simple random sample of 64 patients and determines the time (in minutes) between when they checked in to the ER until they were first seen by a doctor. A \(95 \%\) confidence interval based on this sample is \((128\) minutes, 147 minutes), which is based on the normal model for the mean. Determine whether the following statements are true or false, and explain your reasoning. (a) We are \(95 \%\) confident that the average waiting time of these 64 emergency room patients is between 128 and 147 minutes. (b) We are \(95 \%\) confident that the average waiting time of all patients at this hospital's emergency room is between 128 and 147 minutes. (c) \(95 \%\) of random samples have a sample mean between 128 and 147 minutes. (d) A \(99 \%\) confidence interval would be narrower than the \(95 \%\) confidence interval since we need to be more sure of our estimate. (e) The margin of error is 9.5 and the sample mean is 137.5 . (f) In order to decrease the margin of error of a \(95 \%\) confidence interval to half of what it is now, we would need to double the sample size.

Determine if the following statements are true or false, and explain your reasoning. If false, state how it could be corrected. (a) If a given value (for example, the null hypothesized value of a parameter) is within a \(95 \%\) confidence interval, it will also be within a \(99 \%\) confidence interval. (b) Decreasing the significance level \((\alpha)\) will increase the probability of making a Type 1 Error. (c) Suppose the null hypothesis is \(p=0.5\) and we fail to reject \(H_{0}\). Under this scenario, the true population proportion is 0.5 . (d) With large sample sizes, even small differences between the null value and the observed point estimate, a difference often called the effect size, will be identified as statistically significant.

In each part below, there is a value of interest and two scenarios (I and II). For each part, report if the value of interest is larger under scenario I, scenario II, or whether the value is equal under the scenarios. (a) The standard error of \(\hat{p}\) when (I) \(n=125\) or (II) \(n=500\). (b) The margin of error of a confidence interval when the confidence level is (I) \(90 \%\) or (II) \(80 \%\). (c) The p-value for a Z-statistic of 2.5 calculated based on a (I) sample with \(n=500\) or based on a (II) sample with \(n=1000\). (d) The probability of making a Type 2 Error when the alternative hypothesis is true and the significance level is (I) 0.05 or (II) 0.10 .

In Exercise \(5.19,\) we learned that a Rasmussen Reports survey of \(1,000 \mathrm{US}\) adults found that \(42 \%\) believe raising the minimum wage will help the economy. Construct a \(99 \%\) confidence interval for the true proportion of US adults who believe this.

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