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91Ó°ÊÓ

The lung cancer hazard rateλ(t)of a t-year-old male smoker is such that

λ(t)=.027+.00025(t−40)2t≥40

Assuming that a 40-year-old male smoker survives all other hazards, what is the probability that he survives to

(a)age50and (b)age 60 without contracting lung cancer?

Short Answer

Expert verified

t=50⇒λ(50)=0.052

t=60⇒λ(60)=0.127

Step by step solution

01

Given Information.

λ(t)=.027+.00025(t−40)2t≥40

02

Part a Step 2 Explanation.

t=50,

λ(50)=0.027+0.00025(50-40)2

=0.027+0.025=0.052

03

Part b Step 3 Explanation.

t=60,λ(60)=0.0027+0.000259(60-40)2

=0.127

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