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Suppose that the life distribution of an item has the hazard rate functionλ(t)=t3,t>0. What is the probability that

(a)the item survives to age2?

(b)the item’s lifetime is between.4and1.4?

(c)a 1-year-old item will survive to age2?

Short Answer

Expert verified

Therefore the,

(a)P(X≥2)≈0.0183(b)P(0.4≤X≤1.4)≈0.6109(c)P(X≥2X≥1)≈0.0235

Step by step solution

01

Given information:

The life distribution of an item has the hazard rate functionλ(t)=t3,t>0.

Let Xdenote the life distribution. First, we compute the probability function of the life distribution.

F(t)=1-exp-∫0tλ(u)duF(t)=1-exp-14t4

02

Part (a) step 2 Explanation:

It is to computeP(X≥2)

P(X≥2)=1-P(X<2)=1-F(2)=e-4≈0.0183

03

Part (b) step 3 Explanation:

The probability is given by

P(0.4≤X≤1.4)=P(X≤1.4)-P(X≤0.4)=F(1.4)-F(0.4)=(1-e-0.9604)-(1-e-0.0064)=e-0.0064-e-0.9604≈0.6109

04

Part (c) step 4 Explanation:

The probability that a 1-year-old item will survive to age 2is

P(X≥2X≥1)=P(X≥2)P(X≥1)=1-F(2)1-F(1)=e-4e-14=e-154≈0.0235

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