/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.3.8 A couple has 2 children. What is... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A couple has 2 children. What is the probability that both are girls if the older of the two is a girl ?

Short Answer

Expert verified

12is the probability that both are girls if the older of the two is a girl.

Step by step solution

01

Step 1:Given Information

Given that a couple has 2children.

02

Step 2:Explanation

Letg signify a girl and b indicate a boy.

Test space to the investigation is

S={gg,gb,bg,bb}

Allow A to signify the occasion that the two youngsters are girls.

A={gg}

Allow B to signify the occasion that the more established of the two is a girl.

B={gg,gb}

The occasion that more established of the two is a girl and the two youngsters are girls.

A∩B={gg}

03

Step 3:Final Answer

The probability that both are girls if the older of the two is a girl is

P(A∣B)=P(A∩B)P(B)

=1424

=12

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Example 3f, suppose that the new evidence is subject to different possible interpretations and in fact shows only that it is 90 percent likely that the criminal possesses the characteristic in question. In this case, how likely would it be that the suspect is guilty (assuming, as before, that he has the characteristic)?

A red die, a blue die, and a yellow die (all six-sided) are rolled. We are interested in the probability that the number appearing on the blue die is less than that appearing on the yellow die, which is less than that appearing on the red die. That is, with B, Y, and R denoting, respectively, the number appearing on the blue, yellow, and red die, we are interested in P(B<Y<R).

(a) What is the probability that no two of the dice land on the same number?

(b) Given that no two of the dice land on the same number, what is the conditional probability that B<Y<R?

(c) What is P(B<Y<R)?

If two fair dice are rolled, what is the conditional probability that the first one lands on 6 given that the sum of the dice is i? Compute for all values of ibetween 2and12

You ask your neighbor to water a sickly plant while you are on vacation. Without water, it will die with probability .8; with water, it will die with probability .15. You are 90percent certain that your neighbor will remember to water the plant.

(a) What is the probability that the plant will be alive when you return?

(b) If the plant is dead upon your return, what is the probability that your neighbor forgot to water it?

A coin having probability .8of landing on heads is flipped. A observes the result—either heads or tails—and rushes off to tell B. However, with probability .4, A will have forgotten the result by the time he reaches B. If A has forgotten, then, rather than admitting this to B, he is equally likely to tell Bthat the coin landed on heads or that it landed tails. (If he does remember, then he tells Bthe correct result.)

(a) What is the probability that B is told that the coin landed on heads?

(b) What is the probability that Bis told the correct result?

(c) Given that B is told that the coin landed on heads, what is the probability that it did in fact land on heads?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.