91Ó°ÊÓ

The king comes from a group of $2$children.

The group of two children comprises of the accompanying $4$prospects:

$\left\{\right(B,B),(B,G),(G,B),(G,G\left)\right\}$

Out of these $4$, just three kinds of families comprise the occasion that the king comes from a group of two children. Those are:

$\left\{\right(B,B),(B,G),(G,B\left)\right\}$

Out of these three, just two kinds of families comprise the occasion that the king comes from a family in which the other kid is his sister. Those are:

$\left\{\right(B,G),(G,B\left)\right\}$

Allow $A$being the occasion that the king comes from a group of $2$children.

Allow $B$being the occasion that the other kid is the sister.

Obviously from the above conversation, it has,

$P\left(AB\right)=P(\text{the king comes from a family in which the other child is his sister)}$

$=\frac{2}{4}$

$P\left(A\right)=P\left(\text{the king comes from a family of}2\text{children}\right)$

$=\frac{3}{4}$

Presently, the conditional probability that the other youngster his sister given that the king comes from a group of two kids.

That is,

$P(Bâˆ\pounds A)=\frac{P\left(AB\right)}{P\left(A\right)}$

$=\frac{2/4}{3/4}$

$=\frac{2}{3}$