/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 A game popular in Nevada gamblin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A game popular in Nevada gambling casinos is Keno, which is played as follows: Twenty numbers are selected at random by the casino from the set of numbers 1 through 80. A player can select from 1 to 15 numbers; a win occurs if some fraction of the player's chosen subset matches any of the 20 numbers drawn by the house. The payoff is a function of the number of elements in the player's selection and the number of matches. For instance, if the player selects only 1 number, then he or she wins if this number is among the set of \(20,\) and the payoff is \(\$ 2.20\) won for every dollar bet. (As the player's probability of winning in this case is \(\frac{1}{4},\) it is clear that the "fair" payoff should be \(\$ 3\) won for every \(\$ 1\) bet.) When the player selects 2 numbers, a payoff (of odds) of \(\$ 12\) won for every \(\$ 1\) bet is made when both numbers are among the \(20 .\) (a) What would be the fair payoff in this case? Let \(P_{n, k}\) denote the probability that exactly \(k\) of the \(n\) numbers chosen by the player are among the 20 selected by the house. (b) Compute \(P_{n, k}\) (c) The most typical wager at Keno consists of selecting 10 numbers. For such a bet, the casino pays off as shown in the following table. Compute the expected payoff:

Short Answer

Expert verified
To answer the exercise: 1. The fair payoff when selecting 2 numbers is calculated as \(P(\text{win}) = \frac{\dbinom{2}{2}\dbinom{78}{18}}{\dbinom{80}{20}}\), and the fair payoff = \(\frac{1}{P(\text{win})}\). 2. The probability of exactly k matches out of n chosen numbers is given by \(P_{n, k} = \frac{\dbinom{n}{k}\dbinom{80-n}{20-k}}{\dbinom{80}{20}}\). 3. The expected payoff for selecting 10 numbers is computed as the sum of the products of each case's probability and its corresponding payoff: Expected payoff = \(P_{10, 0}\) x (loss) + \(P_{10, 5}\) x (payoff for 5 matches) + ... + \(P_{10, 10}\) x (payoff for 10 matches).

Step by step solution

01

Calculate the probability of a win with 2 numbers

The probability of a player's two numbers both being drawn by the house is the total number of ways for the house to draw both of the player's chosen numbers divided by the total number of ways for the house to draw any 20 numbers. This is given by: \(P(\text{win}) = \frac{\dbinom{2}{2}\dbinom{78}{18}}{\dbinom{80}{20}}\)
02

Compute the fair payoff

A fair payoff would be the inverse of the winning probability, multiplied by $1 to get the dollar amount that should be won per dollar bet: \(\text{fair payoff} = \frac{1}{P(\text{win})}\) Now, we can calculate the fair payoff. #Step 2: Compute \(P_{n, k}\), the probability of exactly k matches out of n chosen numbers# We are given the formula \(P_{n, k}\), and we need to compute the probability.
03

Derive the formula for \(P_{n, k}\)

To find the probability of exactly k matches out of n chosen numbers, we can apply a similar logic as in Step 1. The total number of ways to get k matching numbers and n-k non-matching numbers is: \(\dbinom{n}{k}\dbinom{80-n}{20-k}\) The total number of ways for the house to draw 20 numbers from 80 is: \(\dbinom{80}{20}\) Then, the probability of getting exactly k matches out of n chosen numbers is: \(P_{n, k} = \frac{\dbinom{n}{k}\dbinom{80-n}{20-k}}{\dbinom{80}{20}}\) #Step 3: Compute the expected payoff for selecting 10 numbers# We are given a table of the payoffs for each number of matches for a 10-number wager. We need to calculate the expected payoff.
04

Calculate the expected payoff

For each case, we will multiply the probability of getting the specified number of matches (using the formula for \(P_{10, k}\)) by the corresponding payoff. Then, we will sum all these values. Expected payoff = \(P_{10, 0}\) x (loss) + \(P_{10, 5}\) x (payoff for 5 matches) + ... + \(P_{10, 10}\) x (payoff for 10 matches) Now that we have found the steps for solving each part of the problem, we can calculate the values needed to answer the exercise.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is all about counting the number of ways things can happen. In our Keno example, we're interested in exploring how the numbers are drawn. By using mathematical techniques, we can evaluate how many combinations of numbers exist. The math behind combinatorics often involves concepts like permutations and combinations. For instance, when dealing with Keno, you might use combinations to figure out how many ways you can choose 20 numbers from a pool of 80.

One of the key tools in combinatorics is the combination formula, which is \[\dbinom{n}{r} = \frac{n!}{r!(n-r)!}\]Here, \(n!\) ("n-factorial") represents the product of all positive integers up to \(n\), and this formula tells us how many ways we can choose \(r\) numbers from a set of \(n\) numbers.
  • Permutations - where order matters, such as the arrangement of certain numbers.
  • Combinations - where order does not matter, relevant in Keno where only the choice of numbers matters.
Understanding combinations in Keno helps calculate probabilities, such as the chance of a player selecting the correct numbers or determining how likely it is for an event to occur.
Expected Value
The expected value is like predicting the average outcome of an uncertain event. When playing Keno or any other gambling game, expected value gives you an idea of how much you could expect to win or lose per game, on average. It's a critical concept in probability and gambling mathematics.

To find the expected value, consider each possible outcome and multiply its value by the probability it'll happen. Then, sum these results. For Keno, you'd factor in all possible scenarios where you hit a certain number of matches and multiply those by the corresponding payoff. Through summing these, you obtain the expected payoff of the game. This concept allows players to make informed decisions about gambling and assess whether a game is in their favor.
  • Helps determine fair payouts, indicating how much one should expect to win in a fair setting.
  • Guides players in strategic decision-making.
Expected value is central to understanding whether a Keno game offers a fair chance to win or if the odds favor the casino.
Binomial Coefficient
The binomial coefficient plays a vital role in calculating probabilities, especially in games of chance like Keno. It is represented by \(\dbinom{n}{k}\) and is used to compute the number of ways to select \(k\) successes (like number matches) from \(n\) trials (chosen numbers). In our Keno context, the binomial coefficient helps calculate the probability of drawing exactly \(k\) numbers correctly.
  • The formula \(\dbinom{n}{k} = \frac{n!}{k!(n-k)!}\) is applied.
  • It's fundamental to determining the probability distribution across possible outcomes in a gambling scenario.
In this context, \(\dbinom{10}{k}\) might represent the player's chosen numbers in Keno when calculating probabilities for getting the correct matches against the 20 numbers drawn by the casino. Understanding the binomial coefficient allows players to calculate their winning probabilities accurately and decide how many numbers to bet in order to maximize their chances of winning.
Gambling Mathematics
Gambling mathematics involves the rigorous use of mathematical concepts to analyze games of chance like Keno. It combines probability, statistics, and other mathematical tools to calculate odds, potential payouts, and strategies.

In Keno, for example:
  • Probability helps determine how likely you are to win based on the numbers chosen and the numbers drawn by the casino.
  • Expected value helps assess the average payoff from playing multiple games, informing whether a game's setup is lucrative or not.
  • Combinatorics accounts for the number of possible ways numbers can be drawn and arranged.
Overall, gambling mathematics provides players with insights that allow them to make smarter betting decisions. It informs players whether certain games are worth playing based on a calculated risk versus reward. For players in Keno, understanding these principles can make the difference between blindly gambling and placing informed, strategic bets.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) An integer \(N\) is to be selected at random from \(\left\\{1,2, \ldots,(10)^{3}\right\\}\) in the sense that each integer has the same probability of being selected. What is the probability that \(N\) will be divisible by \(3 ?\) by \(5 ?\) by \(7 ?\) by \(15 ?\) by \(105 ?\) How would your answer change if \((10)^{3}\) is replaced by \((10)^{k}\) as \(k\) became larger and larger? (b) An important function in number theory-one whose properties can be shown to be related to what is probably the most important unsolved problem of mathematics, the Riemann hypothesis - is the Möbius function \(\mu(n)\) defined for all positive integral values \(n\) as follows: Factor \(n\) into its prime factors. If there is a repeated prime factor, as in \(12=2 \cdot 2 \cdot 3\) or \(49=7 \cdot 7,\) then \(\mu(n)\) is defined to equal 0. Now let \(N\) be chosen at random from \(\left\\{1,2, \ldots(10)^{k}\right\\}\) where \(k\) is large. Determine \(P\\{\mu(N)=0\\}\) as \(k \rightarrow \infty\) Hint: To compute \(P\\{\mu(N) \neq 0\\},\) use the identity $$\prod_{i=1}^{\infty} \frac{P_{i}^{2}-1}{P_{i}^{2}}=\left(\frac{3}{4}\right)\left(\frac{8}{9}\right)\left(\frac{24}{25}\right)\left(\frac{48}{49}\right) \cdots=\frac{6}{\pi^{2}}$$ where \(P_{i}\) is the \(i\) th-smallest prime. (The number 1 is not a prime.)

In some military courts, 9 judges are appointed. However, both the prosecution and the defense attorneys are entitled to a peremptory challenge of any judge, in which case that judge is removed from the case and is not replaced. A defendant is declared guilty if the majority of judges cast votes of guilty, and he or she is declared innocent otherwise. Suppose that when the defendant is, in fact, guilty, each judge will (independently) vote guilty with probability. \(7,\) whereas when the defendant is, in fact, innocent, this probability drops to .3. (a) What is the probability that a guilty defendant is declared guilty when there are (i) \(9,\) (ii) \(8,\) and (iii) 7 judges? (b) Repeat part (a) for an innocent defendant. (c) If the prosecuting attorney does not exercise the right to a peremptory challenge of a judge, and if the defense is limited to at most two such challenges, how many challenges should the defense attorney make if he or she is 60 percent certain that the client is guilty?

Suppose that a die is rolled twice. What are the possible values that the following random variables can take on: (a) the maximum value to appear in the two rolls; (b) the minimum value to appear in the two rolls; (c) the sum of the two rolls; (d) the value of the first roll minus the value of the second roll?

Suppose that the number of accidents occurring on a highway each day is a Poisson random variable with parameter \(\lambda=3\) (a) Find the probability that 3 or more accidents occur today. (b) Repeat part (a) under the assumption that at least 1 accident occurs today.

There are \(k\) types of coupons. Independently of the types of previously collected coupons, each new coupon collected is of type \(i\) with probability \(p_{i}, \quad \sum_{i=1}^{k} p_{i}=1\) If \(n\) coupons are collected, find the expected number of distinct types that appear in this set. (That is, find the expected number of types of coupons that appear at least once in the set of \(n\) coupons.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.