91影视

$$\begin{gathered} MarginalCost\left(MC\right)=\frac{Changeintotal\cos t\left(dTC\right)}{Changeintotaloutput\left(dQ\right)} \\ MarginalBenefit\left(MB\right)=\frac{Changeintotalbenefit\left(dTB\right)}{Changeintotaloutput\left(dQ\right)} \end{gathered}$$

For $0$acres land to be restored -

$$\begin{gathered} MC=\frac{dTC}{dQ} \\ or,MC=\frac{0}{0} \\ or,MC=0 \\ MB=\frac{dTB}{dQ} \\ or,MB=\frac{0}{0} \\ or,MB=0 \end{gathered}$$

For $100$acres land to be restored -

$$\begin{gathered} MC=\frac{dTC}{dQ} \\ or,MC=\frac{\$20-\$0}{100-0} \\ or,MC=\$0.2 \\ MB=\frac{dTB}{dQ} \\ or,MB=\frac{\$140-\$0}{100-0} \\ or,MB=\$1.4 \end{gathered}$$

Foe $200$acres land to be restored -

$$\begin{gathered} MC=\frac{dTC}{dQ} \\ or,MC=\frac{\$80-\$20}{200-100} \\ or,MC=\$0.6 \\ MB=\frac{dTB}{dQ} \\ or,MB=\frac{\$240-\$140}{200-100} \\ or,MB=\$1 \end{gathered}$$

For $300$acres land to be restored -

$$\begin{gathered} MC=\frac{dTC}{dQ} \\ or,MC=\frac{\$160-\$80}{300-200} \\ or,MC=\$0.8 \\ MB=\frac{dTB}{dQ} \\ or,MB=\frac{\$320-\$240}{300-200} \\ or,MB=\$0.8 \end{gathered}$$

For $400$acres land to be restored -

$$\begin{gathered} MC=\frac{dTC}{dQ} \\ or,MC=\frac{\$280-\$160}{400-300} \\ or,MC=\$1.2 \\ MB=\frac{dTB}{dQ} \\ or,MB=\frac{\$380-\$320}{400-300} \\ or,MB=\$0.6 \end{gathered}$$

It is the ideal level of land to be allocated when marginal cost = marginal benefit.

The optimal amount of land is $300$acres, after which marginal revenue decreases.