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Is the following formula satisfiable?

(x∨y)∧(x∨y)∧(x∨y)∧(x∨y).

Short Answer

Expert verified

This techniqueXYXVYX-VYX-VY- satisfiable since it uses every one of the variables that produce true and pair values based on X and Y.

Step by step solution

01

Step 1:Satisfiable means

It implies that the level of XandYmay be expressed in terms of True or False. This algorithm must yield one actual worth in just about any mixture of true and false. So, let's set the true and false combinations in the XandYpositions.

02

Truth Table

True=TandFalse=FX-isthebalanceoftheX

Truth table approach:

XYXVYX-VYX-VY-FinalresultTTTTFFTFTFTFFTTTTTFFFFFF

This ultimate method, which is really the As well as operations of the all the parameters, provides the True value for a pair of X=FalsewithY=True, hence the formula is satisfiable. However, it is not a tautology because it gives the erroneous value for some values

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Most popular questions from this chapter

Let SET-SPLITTINGcollection of subsets of S, for some k>0, such that elements of S can be colored red or blue so that no Ci has all its elements colored with the same color}. Show that SET-SPLITTINGis NP-complete.

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For a cnf-formula ∅ with m variables and cclauses O(cm) , show that you can construct in polynomial time an NFA with states that accept all nonsatisfying assignments, represented as Boolean strings of length m. Conclude that ±Êâ‰²Ó±Ê implies that NFAs cannot be minimized in polynomial time.

A cut in an undirected graph is a separation of the vertices V into two disjoint subsets S and T . The size of a cut is the number of edges that have one endpoint in S and the other in T . Let MAX-CUT=<G,K>|Ghasacutofsizekormore.

Show that MAX-CUT is NP-complete. You may assume the result of Problem 7.26. (Hint: Show that≠SAT⩽PMAXCUT. The variable gadget for variable x is a collection of 3c nodes labeled with x and another nodes labeled with x . The clause gadget is a triangle of three edges connecting three nodes labeled with the literals appearing in the clause. Do not use the same node in more than one clause gadget. Prove that this reduction works.)

The difference hierarchyDiPis defined recursively as

  1. role="math" localid="1664206013824" D1P∈NPand
  2. DiP={A|A=B\CforBinNPandCinDi-1P}.

(Here BC=B∩C.) For example, a language in D2P is the difference of two NP languages. Sometimes D2P is called DP (and may be written DP). Let Z={(G1,k1,G2,k2)|G1hasak1-cliqueandG2doesn'thaveak2-clique}

.Show that Z is complete for DP. In other words, show that Z is in DP and every language in DP is polynomial time reducible to Z.

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