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Show that if P=NP , then every languageA∈P , except A=∅ andA=Σ∗, is NP− complete.

Short Answer

Expert verified

Therefore, P is a category of languages in which membership can be determined in polynomial time.

Step by step solution

01

Hampath and Composite of NP

The class NP is significant because it contains a large number of practical issues. Both HAMPATH&COMPOSITES seem to be members of NP, as shown in the preceding discussion. COMPOSITES also is a member of P , which is a subset of NP, as we indicated; nevertheless, establishing this stronger result is considerably more difficult.

02

NP Complete

Even though all acceptable pseudorandom computer models are polynomially comparable, the class NPis unaffected by the model chosen. We use the same rules for describing and analysing nondeterministic polynomial time algorithms as we use for deterministic polynomial time algorithms.

A vocabulary BissaidtobeNP−completeif all of the previous conditions are met:

NP is indeed a category of systems that can be solved in polynomial time on a nondeterministic Turing machine; alternatively, to put it another way, it is a class of languages whose membership can be validated in polynomial time. P is a category of languages in which membership can be determined in polynomial time.

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Most popular questions from this chapter

You are given a box and a collection of cards as indicated in the following figure. Because of the pegs in the box and the notches in the cards, each card will fit in the box in either of two ways. Each card contains two columns of holes, some of which may not be punched out. The puzzle is solved by placing all the cards in the box so as to completely cover the bottom of the box (i.e., every hole position is blocked by at least one card that has no hole there). It represents a card and this collection of cards has a solution}. Show that PUZZLE is NP-complete.

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