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Given an undirected graphG=(V,E) in which each node hasdegree≤d , show how to efficiently find an independent set whose size is at least1d+1times that of the largest independent set.

Short Answer

Expert verified

This algorithm is proved.

Step by step solution

01

Step 1:

An undirected graph in which each node has degree ≤ d, efficiently an independent set whose size is at least1d+1 times that of the largest independent set is defined below.

02

Step 2:  

LetG be the graph with vertex set of V having d the maximum degree, and in an empty set.

The following process will get an independent set whose size is atleast1d+1 times that of the largest independent set.

1). Pick a vertex with smallest degree and add to it.

2). Delete vertex and all its adjacent vertices from the graph.

3). Repeat this process until the vertex set is empty.

The set is now the independent set of the graphG .

Since a vertex in the graph has most d neighbours , thus at each iteration , maximum d+1vertices are deleted. Thus, the vertex set reduces byd+1 vertices at each and every iteration.

Hence there are atleast|V|(d+1) iteration to get the I. At each iteration, one vertex is added in the set I.

Hence, I contains atleat |V|(d+1)vertices.

|V|(d+1)

Let k be the size of the maximum independent as |V|≥K

Therefore,

|1| â¶ÄŠâ¶ÄŠâ¶ÄŠâ‰¥|V|(d+1)≥Kd+1

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