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(III) precipitates from acidic solution by addition of OH-to form Fe(OH)3(s). At what concentration of localid="1663570454087" OH-will [Fe(III)]be reduced to 1.0x10-10M? If Fe(II)is used instead, what concentration of OH-will reduce Fe(II) to 1.0x10-10M?

Short Answer

Expert verified

When using [Fe(III)], concentration of OH-reduce to 1.0x10-10Mwas found to be 2.5x10-10Mand using [Fe(II)] concentration of OH-reduced to 1.0x10-10Mwas found to be 2.8x10-3M.

Step by step solution

01

concentration

Concentration of OH-reduced to 1.0x10-10when using [Fe(III)]and using [Fe(II)]must be calculated.

02

reduction of the concentration of OH- When use [Fe(III)],

When use [Fe(III)], the concentration of OH-reduced to 1.0x10-10Mis,

role="math" localid="1663571809159" Fe3+OH-3=10-10OH-3=1.6x10-39OH-=2.8x10-3M

03

reduction of the concentration of OH- When use  [Fe(II)] ,

When use[Fe(II)], the concentration of localid="1663572130523" OH-reduced to 1.0x10-10Mis,

Fe2+OH-2=10-10OH-2=7.9x10-16OH-=2.8x10-3M

When using [Fe(III)], concentration of OH-reduce to 1.0x10-10Mwas found to be 2.5x10-10Mand using [Fe(II)] concentration of OH-reduced to 1.0x10-10Mwas found to be 2.8x10-3M.

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