/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q14P  Describe how you would prepare... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Describe how you would prepare exactlyof picolinate buffer, . Possible starting materials are pure picolinic acid (pyridine-2-carboxylic acid, FM 123.11), 1.0 M HCl, and . Approximately how many milliliters of the orwill be required?

Short Answer

Expert verified

The volume of the container from here NaOHas a result ofV(NaOH)is5.63mL

Step by step solution

01

Definition of Henderson Hasselbalch and Picolinic Acid 

  • The Henderson Hasselbalch equation is a simplified formula that shows the connection between a solution's pH or pOH, pKa or pKb, and the ratio of concentrations of dissociated chemical species.
  • Picolinic Acid is an endogenous metabolite of L-tryptophan (TRP) that has been shown to have a variety of neuroprotective, immunological, and anti-proliferative properties.
02

Determine the picolinic acid

This work will show you how to make 100ml of 0.1M picolinate buffer with a pH of 5.50. Pure pocolinic acid (pyrid ne-2-carboxylic acid) could be used as a starting material, FM=123.11g/mol),1MHC1 and 1MNaOH.

It must first moles of picolinic acid are calculated as follows:

n(picolinicacid)=c×Vn(picolinicacid)=0.1M×100mLn(picolinicacid)=10mmol

03

Determine the value of x and volume of the container NaOH

Consider the reaction below:

HA+OH-⇌A-[HA]=10-x[A-]=x

The Henderson-Hasselbach equation should then be used to determine the value of x.

pH=pKa+log([A-]/[HA])5.50=5.39+logx10-xx=5.63mmol

It can calculate the volume of the container from hereNaOHas a result of:

localid="1663417082743" V(NaOH)=n×cV(NaOH)=5.63mmol×1MV(NaOH)=5.63mL

04

Determine the mass of picolinic acid

Then, using the formula below, determine the mass of picolinic acid:

m(picolinicacid)=n×Mm(picolinicacid)=10mmol×123.11g/molm(picolinicacid)=1.23g

In order to get ready 100ml of 0.1M using picolinate buffer pH=5.50 it must take the following steps:-

  • Dissolve In distilled water, 1.23g of picolinic acid
  • Add 5.63mL of NaOH until the pH=5.50 is reached.
  • Transfer the solution to a volumetric flask and dilute to a final concentration of 100mL .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A solid mixture weighing 0.05485 gcontained only ferrous ammonium sulphate and ferrous chloride. The sample was dissolved in1MH2SO4, and the Fe2+required 13.39 mL oflocalid="1663577431957" 0.01234MCe4+for complete oxidation to localid="1663577453691" Fe3+. Calculate the weight percent of Cl in the original sample. If you need refreshing, see Section 7-2 for an example of a titration of a mixture.

localid="1663574328546" FeSO4×(NH4)2SO4×6H2OFeCI2×6H2O

Ferrous ammonium sulfate Ferrous chloride

FM 392.13

FM 234.84

If there had beenn=13replications in both data sets, would the difference in standard deviations be significant?

Titration of metal ion with EDTA. Use Equation 12-11 to compute curves (pM versus mL of EDTA added) for the titration of 10.00 mL of 1.00 mM M2+ (= Cd2+ or Cu2+) with 10.0 mM EDTA at pH 5.00. Plot both curves on one graph.

Effect of concentration in the titration of weak acid with strong base.Use your spreadsheet from Problem 11-66 to prepare a family of titration curves for pKa = 6, with the following combinations of concentrations: (a) Ca = 20 mM, Cb = 100 mM; (b) Ca = 2 mM, Cb = 10 mM; (c) Ca = 0.2 mM, Cb = 1 mM.

The metal ion indicator xylenol orange (Table 12-3) is yellow atpH6(λmax=439nm).The spectral changes that occur asVO2+is added to the indicator atpH6 are shown here. The mole ratioVO2+/xylenol orange at each point is

Suggest a sequence of chemical reactions to explain the spectral changes, especially the isosbestic points at 457 and 528nm.

Absorption spectra for the reaction of xylenol orange withVO2+atpH 6.0

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.